{"id":9638,"date":"2022-04-01T09:00:00","date_gmt":"2022-04-01T12:00:00","guid":{"rendered":"https:\/\/professorpinguim.com.br\/blog\/?p=9638"},"modified":"2023-08-06T21:00:53","modified_gmt":"2023-08-07T00:00:53","slug":"questoes-de-transformacao-adiabatica-e-maquinas-termicas","status":"publish","type":"post","link":"https:\/\/professorpinguim.com.br\/blog\/questoes-de-transformacao-adiabatica-e-maquinas-termicas\/","title":{"rendered":"Quest\u00f5es de Transforma\u00e7\u00e3o Adiab\u00e1tica e M\u00e1quinas T\u00e9rmicas"},"content":{"rendered":"\n<p class=\"wp-block-paragraph\">Ol\u00e1 pessoal, tudo bem? Hoje trouxe alguns exerc\u00edcios resolvidos para voc\u00eas sobre Transforma\u00e7\u00e3o Adiab\u00e1tica e M\u00e1quinas T\u00e9rmicas. Acompanhe!<\/p>\n\n\n\n<!--more-->\n\n\n\n<p class=\"wp-block-paragraph\">1. (Efomm 2022)\u00a0 Uma m\u00e1quina t\u00e9rmica opera em um ciclo termodin\u00e2mico, retirando 1000 J da fonte quente, que se encontra a 600\u00b0C\u00a0 e produzindo 400 J de trabalho. Se o rendimento dessa m\u00e1quina \u00e9 70% do rendimento de um ciclo de Carnot nas mesmas condi\u00e7\u00f5es, a temperatura da fonte fria, em \u00b0C \u00e9\u00a0<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">a) 101&nbsp;&nbsp;&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">b) 141&nbsp;&nbsp;&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">c) 180&nbsp;&nbsp;&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">d) 219&nbsp;&nbsp;&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">e) 258&nbsp;&nbsp;&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">1: A<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Rendimento da m\u00e1quina:<\/p>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img decoding=\"async\" src=\"https:\/\/lh4.googleusercontent.com\/k-xoNAsv0kDfr_dQpA3yrSLoqckRAx0x-gqq9hDTjh6_h8s9XzkoRA9gZvkXcIOr7jmxLYjC70OiFS5aq0dzda9T4Y4abBudgCY9ckeHXvyegNayspebToBL2LwqhEM2ut-HUnGj\" alt=\"\" width=\"232\" height=\"66\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Logo:<\/p>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img fetchpriority=\"high\" decoding=\"async\" src=\"https:\/\/lh4.googleusercontent.com\/bwGFcn-jEpFqTY7YS_mhLJkt8cGT7BF_zgxiF19akxojl_HtLg3BJNKPSRpiziqlMheouzQzsbmWXC_j_v0y6-cF5Rprdb9Hb_5jU-wVKPWKFy_NsY5cf5Ly1EnQn7y9BiXTUVNo\" alt=\"\" width=\"245\" height=\"226\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">2<strong>.<\/strong> (Eear)&nbsp; O gr\u00e1fico press\u00e3o (P) por volume (V) a seguir representa uma s\u00e9rie de transforma\u00e7\u00f5es termodin\u00e2micas pelas quais passam uma amostra de g\u00e1s ideal em uma m\u00e1quina t\u00e9rmica.<\/p>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img decoding=\"async\" src=\"https:\/\/lh5.googleusercontent.com\/lVfkLtth4Mi-3jp_rkp-rwJbvbIBaoJM1kdEVTLGw25WyGdeeQxTwwaKN_NaF7vrD28w4hpL3mVDMRwHKKLDRsq2_7VwrZBXxf388v5h5jioq-sFpi9AfsVWWiBMpEAc3Qf4Tdn2\" alt=\"\" width=\"314\" height=\"241\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Assinale entre as alternativas, aquela que indica corretamente uma \u00fanica mudan\u00e7a no ciclo representado no gr\u00e1fico que aumentar\u00e1 o rendimento dessa m\u00e1quina t\u00e9rmica.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">a) aumentar, na mesma propor\u00e7\u00e3o, o calor captado e emitido pela amostra&nbsp;&nbsp;&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">b) diminuir, na mesma propor\u00e7\u00e3o, o calor captado e emitido pela amostra&nbsp;&nbsp;&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">c) aumentar o valor da press\u00e3o P1&nbsp;&nbsp;&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">d) diminuir o valor da press\u00e3o P1&nbsp;&nbsp;&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>2: <\/strong>D<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">&nbsp;O rendimento da m\u00e1quina t\u00e9rmica \u00e9 dado por:<\/p>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/lh5.googleusercontent.com\/CDHXh3RTTVPRzoHn2zyAqjAn7aA2U4EEbDZ8eqYyg-xNrVdEfWiCd_-YqAe3Htbb5foVI6MP3446aK3aAbCTbtFFmisAyEUSSyHLCFzU6UAO-OgryiDQ-PA2eBEzRFn9jZ73X4vX\" alt=\"\" width=\"294\" height=\"73\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Ao aumentar a \u00e1rea do ciclo, aumentamos o trabalho realizado. Portanto, podemos diminuir o valor da press\u00e3o P1.&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">3<strong>.<\/strong> (Efomm )&nbsp; Um refrigerador que opera sob o ciclo de Carnot tem pot\u00eancia de 200 W e devolve 1400 J de calor ao exterior a cada segundo. Em um dia de ver\u00e3o, em que a temperatura ambiente \u00e9 de 27\u00b0C a m\u00ednima temperatura que se pode obter no interior do refrigerador \u00e9 de:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">a) -20\u00b0C&nbsp;&nbsp;&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">b) -16\u00b0C&nbsp;&nbsp;&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">c) -10\u00b0C&nbsp;&nbsp;&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">d) 0\u00b0C&nbsp;&nbsp;&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">e) 2\u00b0C&nbsp;&nbsp;&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>3:<\/strong>B<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">&nbsp;A cada segundo t\u00eam-se:<\/p>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/lh4.googleusercontent.com\/ZUszlFnsP6dpQ6iWacl_WJtGpAh7_W55gLOk_TVxA86cOs2Nf7ktCA-1VrG0Omc6yi8kMWYD4RrOF454Tjkk253ymbwvt-ZeBlcnqJBxd6-eArwcpzajkfAqtfGuG5B5VzY6a2ID\" alt=\"\" width=\"455\" height=\"66\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Da equa\u00e7\u00e3o do refrigerador, calcula-se a quantidade de calor retirada do ambiente frio (congelador).<\/p>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/lh5.googleusercontent.com\/9JBYFsVGLJblcU2m0NUgq0PGak3Zy3hULkcU7HYpPqcPdnTYjn-GrsEhfM2UJtPLw3-g8kU2eQD7aKlAheatefMJ5GjnS8QBbtI0ayIoW3Ov7nOqthnxmdtjfcbIvIQPZ4mITc1E\" alt=\"\" width=\"468\" height=\"40\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Para o ciclo de Carnot:<\/p>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/lh3.googleusercontent.com\/D0iHxg8HqQGUiAYpqYIuHLreulofDhyBNveCwZ2gii3WBT1t6hVbKni2RQyh09H_JGZ1StF0PD_PRC_EMse3HC3bs-cJpHs4gRnzanMs54_HE5iZBvC4LzdZm-sj4amWrKZkqHRe\" alt=\"\" width=\"461\" height=\"93\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">4<strong>.<\/strong> (Espcex (Aman) Considere uma m\u00e1quina t\u00e9rmica que opera um ciclo termodin\u00e2mico que realiza trabalho. A m\u00e1quina recebe 400J de uma fonte quente cuja temperatura \u00e9 de 400 K e rejeita 200 J para uma fonte fria, que se encontra a 200 K Neste ciclo a m\u00e1quina t\u00e9rmica realiza um trabalho de 200 J<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">&nbsp;&#8211; Analisando o ciclo termodin\u00e2mico exposto acima conclui-se que a m\u00e1quina t\u00e9rmica \u00e9 um ____I____.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">&#8211; Essa m\u00e1quina t\u00e9rmica ____II____ a 1\u00aa Lei da Termodin\u00e2mica.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">&#8211; O rendimento desta m\u00e1quina \u00e9 ____III_____ a 50%<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">&nbsp;A op\u00e7\u00e3o que corresponde ao preenchimento correto das lacunas (I), (II) e (III) \u00e9:<\/p>\n\n\n\n<figure class=\"wp-block-table\"><table><tbody><tr><td>a)<\/td><td>I &#8211; refrigerador<\/td><td>II &#8211; N\u00e3o atende<\/td><td>III &#8211; maior que<\/td><\/tr><tr><td>b)<\/td><td>I &#8211; refrigerador<\/td><td>II &#8211; atende<\/td><td>III &#8211; igual a<\/td><\/tr><tr><td>c)<\/td><td>I &#8211; motor t\u00e9rmico<\/td><td>II &#8211; atende<\/td><td>III &#8211; menor que<\/td><\/tr><tr><td>d)<\/td><td>I &#8211; motor t\u00e9rmico<\/td><td>II &#8211; N\u00e3o atende<\/td><td>III &#8211; maior que<\/td><\/tr><tr><td>e)<\/td><td>I &#8211; motor t\u00e9rmico<\/td><td>II &#8211; Atende<\/td><td>III &#8211; igual a<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>4: <\/strong>E<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">&nbsp;Como a m\u00e1quina recebe calor e devolve a energia em forma de trabalho, ela \u00e9 um motor t\u00e9rmico.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">&nbsp;Como a soma do calor rejeitado com o trabalho realizado equivale \u00e0 energia recebida, h\u00e1 conserva\u00e7\u00e3o de energia, o que respeita a 1\u00aa Lei da Termodin\u00e2mica.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">&nbsp;Calculando o rendimento:<\/p>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/lh6.googleusercontent.com\/Vgq3Mp2yCZmgQPYuc0dx8mZd4PjAMIR2RRp3LBBFio7mKGior-_k_eGrn-renPey4JGrkryHbF_jjKvVNhhJp7i4t850rhlGi4EYZAcTsYulAj6_vgDRn-2RT3RRejMnecfQJ7jB\" alt=\"\" width=\"283\" height=\"127\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">5<strong>.<\/strong> (Esc. Naval)&nbsp; Um refrigerador, com efici\u00eancia de 40% fornece 1400J de calor para a fonte quente por ciclo de opera\u00e7\u00e3o. Sabendo que ele opera fazendo 5,00 ciclos por segundo, calcule em quanto tempo este refrigerador congela 4 kg de \u00e1gua a 25\u00b0C e assinale a op\u00e7\u00e3o correta.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">&nbsp;Dados: calor latente de fus\u00e3o da \u00e1gua 300 kJ\/kg calor espec\u00edfico da \u00e1gua 4200 J\/(kg.\u00b0C)<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">a) 750 s&nbsp;&nbsp;&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">b) 810 s&nbsp;&nbsp;&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">c) 920 s&nbsp;&nbsp;&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">d) 1040 s&nbsp;&nbsp;&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">e) 1100 s&nbsp;&nbsp;&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>5: <\/strong>B<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">&nbsp;Calor da fonte fria:<\/p>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/lh6.googleusercontent.com\/N1Wa40qTq3lZFg2oQAdV71GnczbO1KZ0aHFKb9gEpg21k6jiu6QgKo9DJ-xRKRrCDVlfrSp67TPjnVobBHl1kATKg5za2sGR7cz-xRHp3DutMV9lxkOIvY5c5eogIkRX4oBktpye\" alt=\"\" width=\"183\" height=\"222\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Logo, o tempo necess\u00e1rio para que o refrigerador congele a \u00e1gua \u00e9 de:<\/p>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/lh6.googleusercontent.com\/M9PcliYvHQuo1M8yrBe5wRQrsEuH-AXQUTGi0oPYi5aa8CCCCJbq7Ir-GRovdemsYT6uIbOb8WUPuMKB5BcVdKSLdkTfj1RK4ceATuUqkwMK6a9qjMtFkHl2MsHSCXU2P-X3OPvM\" alt=\"\" width=\"464\" height=\"170\"\/><\/figure>\n\n\n\n<hr class=\"wp-block-separator\"\/>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>SAIBA MAIS<\/strong><br>\ud83d\udc27<strong>&nbsp;<a rel=\"noreferrer noopener\" href=\"https:\/\/professorpinguim.com.br\/blog\/resumo-sobre-dilatacao-termica-de-solidos-com-exercicios\/\" target=\"_blank\">Exerc\u00edcios sobre Dilata\u00e7\u00e3o T\u00e9rmica S\u00f3lidos<\/a><br>\ud83d\udc27&nbsp;<a rel=\"noreferrer noopener\" href=\"https:\/\/professorpinguim.com.br\/blog\/dilatacao-termica-e-calorimetria\/\" target=\"_blank\"><strong>Calorimetria e dilata\u00e7\u00e3o t\u00e9rmica<\/strong><\/a><br>\ud83d\udc27&nbsp;<\/strong><a rel=\"noreferrer noopener\" href=\"https:\/\/professorpinguim.com.br\/blog\/dilatacao-de-liquidos-exercicios-com-gabarito\/\" target=\"_blank\"><strong>Exerc\u00edcios sobre Dilata\u00e7\u00e3o de l\u00edquidos<\/strong><\/a><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Me acompanhe nas redes sociais: curta a minha&nbsp;<a href=\"https:\/\/www.facebook.com\/professorpinguim\/\"><strong>p\u00e1gina no Facebook<\/strong><\/a><strong>,<\/strong>&nbsp;me&nbsp;siga no&nbsp;<a href=\"https:\/\/www.instagram.com\/professorpinguim\/\"><strong>Instagram<\/strong><\/a><strong>,<\/strong>&nbsp;se inscreva no&nbsp;<a href=\"https:\/\/www.youtube.com\/c\/PinguimV%C3%ADdeoF%C3%ADsica\/?sub_confirmation=1\"><strong>Youtube<\/strong><\/a>&nbsp;e participe do meu canal oficial no&nbsp;<strong><a href=\"https:\/\/professorpinguim.com.br\/telegram\">Telegram<\/a><\/strong>.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Hoje trouxe alguns exerc\u00edcios resolvidos para voc\u00eas sobre Transforma\u00e7\u00e3o Adiab\u00e1tica e M\u00e1quinas T\u00e9rmicas. Acompanhe!<\/p>\n","protected":false},"author":1,"featured_media":9639,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[764,228,656],"tags":[217,660,834,610],"class_list":["post-9638","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-ondas","category-optica","category-termologia","tag-exercicios-resolvidos","tag-maquinas-termicas","tag-termodinamico","tag-transformacao-adiabatica"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v20.12 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Quest\u00f5es de Transforma\u00e7\u00e3o Adiab\u00e1tica e M\u00e1quinas T\u00e9rmicas - Professor Pinguim | F\u00edsica<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/professorpinguim.com.br\/blog\/questoes-de-transformacao-adiabatica-e-maquinas-termicas\/\" \/>\n<meta property=\"og:locale\" content=\"pt_BR\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Quest\u00f5es de Transforma\u00e7\u00e3o Adiab\u00e1tica e M\u00e1quinas T\u00e9rmicas - Professor Pinguim | F\u00edsica\" \/>\n<meta property=\"og:description\" content=\"Hoje trouxe alguns exerc\u00edcios resolvidos para voc\u00eas sobre Transforma\u00e7\u00e3o Adiab\u00e1tica e M\u00e1quinas T\u00e9rmicas. 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