{"id":8883,"date":"2022-03-25T09:00:00","date_gmt":"2022-03-25T12:00:00","guid":{"rendered":"https:\/\/professorpinguim.com.br\/blog\/?p=8883"},"modified":"2023-08-06T21:00:58","modified_gmt":"2023-08-07T00:00:58","slug":"lista-de-exercicios-1a-lei-termodinamica-e-transformacoes","status":"publish","type":"post","link":"https:\/\/professorpinguim.com.br\/blog\/lista-de-exercicios-1a-lei-termodinamica-e-transformacoes\/","title":{"rendered":"Lista de exerc\u00edcios: 1\u00aa Lei Termodin\u00e2mica e Transforma\u00e7\u00f5es"},"content":{"rendered":"\n<p class=\"wp-block-paragraph\">Vamos aplicar a conserva\u00e7\u00e3o de energia \u00e0s transforma\u00e7\u00f5es gasosas. Acompanhe! <\/p>\n\n\n\n<!--more-->\n\n\n\n<p class=\"wp-block-paragraph\"><strong>1. (Espcex (Aman)) Um g\u00e1s ideal sofre uma transforma\u00e7\u00e3o adiab\u00e1tica em que o meio externo realiza um trabalho sobre o g\u00e1s. Podemos afirmar que, nesta transforma\u00e7\u00e3o:<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">a) a energia interna do g\u00e1s diminui.&nbsp;&nbsp;&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">b) o calor trocado aumenta.&nbsp;&nbsp;&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">c) a press\u00e3o do g\u00e1s diminui.&nbsp;&nbsp;&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">d) o volume do g\u00e1s aumenta.&nbsp;&nbsp;&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">e) a temperatura do g\u00e1s aumenta.&nbsp;&nbsp;&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Resposta: <\/strong>E<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/lh5.googleusercontent.com\/JwW0d74smUMpUWCdzvYJSsO385VRrS8bv5FFKuy1ZXN6NhioBSwbrB-_n3NDXZjRCYwGf551c3Os8OHnmIn6MyFApH6gJeA7nzkuMYN9uWUKGuiGDZ5SN4WsOXJFTenydICzzdPU\" alt=\"\"\/><\/figure>\n\n\n\n<hr class=\"wp-block-separator\"\/>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>2. (Unesp) Em um recipiente de paredes r\u00edgidas, est\u00e3o confinados 4 mols de um g\u00e1s monoat\u00f4mico ideal que, ao absorver determinada quantidade de calor, sofreu uma transforma\u00e7\u00e3o isovolum\u00e9trica entre dois estados, I e II, representada no diagrama P.V<\/strong>:<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/lh5.googleusercontent.com\/wVdrXH5hkhvc-lnkmnMuDAszydSfEmLt6y7_lEd-Qj12jS5GS4OrKQSIEibOSC8RpXz09r7zEIY2l98KfN_uRBEhMxeOIyUXpbtMvPuEopegFVQtVkGp_c2TXO2gVtlu4PCDjXcZ\" alt=\"\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Adotando os valores para a constante universal dos gases e para o calor espec\u00edfico molar desse g\u00e1s a volume constante, a quantidade de calor absorvida pelo g\u00e1s para que sofresse tal transforma\u00e7\u00e3o foi de:<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">a) 16.000 J.&nbsp;&nbsp;&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">b) 14.000 J.&nbsp;&nbsp;&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">c) 18.000 J.&nbsp;&nbsp;&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">d) 12.000 J.&nbsp;&nbsp;&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">e) 10.000 J.&nbsp;&nbsp;&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Resposta: <\/strong>D<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/lh4.googleusercontent.com\/3Z6rQkM-aKkmh2Je2R7ghy6Bm_G8-c53zZj4ZV2T_hySuCaq7lmQcMrUScEkiEdu-_UlovZrpHRYMzJGo_bNKsOP2NMKpKFTG1XzPEnY2OMb5KdXbkPodQ8GPWDwdgpFOTWiQbAC\" alt=\"\"\/><\/figure>\n\n\n\n<hr class=\"wp-block-separator\"\/>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>3. (Fgv) Certa massa de g\u00e1s ideal sofreu tr\u00eas transforma\u00e7\u00f5es. A primeira, AB, foi isot\u00e9rmica, a segunda, BC, foi isovolum\u00e9trica e a terceira, CA, foi isob\u00e1rica, como mostra a figura.<\/strong><\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/lh4.googleusercontent.com\/--328DkTkKgMCywKZIU938b9pdaKqx7AZFn3duYkkJdahfUW3C_fzio2DttZ6aP8GUce0qm2x7Tnq3ji9X0u9_Kqf9pFEcBBDaorTDGrrzX9SVgYrgvvck0DyZ7SCnK3eSuLz6Zn\" alt=\"\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Considerando-se que o calor absorvido pelo g\u00e1s seja positivo, que o calor cedido seja negativo, que o trabalho realizado pela for\u00e7a aplicada pelo g\u00e1s no meio exterior seja positivo e que o trabalho realizado pela for\u00e7a aplicada pelo meio exterior sobre o g\u00e1s seja negativo, montou-se o quadro a seguir.<\/p>\n\n\n\n<figure class=\"wp-block-table\"><table><tbody><tr><td>Transforma\u00e7\u00e3o<\/td><td>Calor envolvido<\/td><td>Trabalho realizado<\/td><td>Energia interna do g\u00e1s<\/td><\/tr><tr><td>AB<\/td><td>positivo<\/td><td>positivo<\/td><td>X<\/td><\/tr><tr><td>BC<\/td><td>positivo<\/td><td>Y<\/td><td>aumenta<\/td><\/tr><tr><td>CA<\/td><td>Z<\/td><td>negativo<\/td><td>diminui<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>&nbsp;Completam, respectivamente, as c\u00e9lulas X, Y e Z do quadro:<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">a) n\u00e3o se altera, nulo e negativo.&nbsp;&nbsp;&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">b) n\u00e3o se altera, positivo e negativo.&nbsp;&nbsp;&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">c) aumenta, positivo e positivo.&nbsp;&nbsp;&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">d) aumenta, nulo e positivo.&nbsp;&nbsp;&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">e) diminui, negativo e nulo.&nbsp;&nbsp;&nbsp;<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/lh6.googleusercontent.com\/G0g6ITIpAuazLGbQ4vrAofYlScolZ4jjQiGwCeIgBp30dePTZAaw20-yfixJiCxjniTdkD6I7NifszdEhLpto743SSF4SVLOQk5nyNkbgkLcY2vh1QZbYCYc_2Rd20V7B9jZtFa_\" alt=\"\"\/><\/figure>\n\n\n\n<hr class=\"wp-block-separator\"\/>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>4. (Fuvest) Um mol de um g\u00e1s ideal percorre o processo c\u00edclico ABCA em um diagrama P.V conforme mostrado na figura, sendo que a etapa AB \u00e9 isob\u00e1rica, a etapa BC \u00e9 isoc\u00f3rica e a etapa CA \u00e9 isot\u00e9rmica.<\/strong><\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/lh3.googleusercontent.com\/Rv7zyrmE0PUNgzQHnePpbMxRjzLpj4slXoXV-kvcVqZ8BLyr0oy42Voa4wdC-260HBybDr0d0dFDvsZLYz05b-c_ITa0JHe1kFF_I8VvttTMxXLO2eF0B3RA5Xh-OhxBqvXlfSvg\" alt=\"\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Considere as seguintes afirma\u00e7\u00f5es:<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">I. O g\u00e1s libera calor tanto na etapa BC quanto na etapa CA<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">II. O m\u00f3dulo do trabalho realizado pelo g\u00e1s \u00e9 n\u00e3o nulo tanto na etapa AB quanto na etapa BC<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">III. O g\u00e1s tem sua temperatura aumentada tanto na etapa AB quanto na etapa CA<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>&nbsp;\u00c9 correto o que se afirma em:<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">a) Nenhuma delas.&nbsp;&nbsp;&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">b) Apenas I.&nbsp;&nbsp;&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">c) Apenas II.&nbsp;&nbsp;&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">d) Apenas III.&nbsp;&nbsp;&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">e) Apenas I e II.&nbsp;&nbsp;&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">&nbsp;<strong>Resposta: <\/strong>B<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/lh4.googleusercontent.com\/vvGOp5QwDb_W8vGrPU4km_sgEKplt5ionyyfRYUbEOfGkXwCOifF0U-RuLSkTMgGXrf8Wcg2q6ti69u4KZ-YTVC1aqvBUYx4zLIvjbc_v4qZyDiilDl1SMzivGuVnseAuxhzBU7d\" alt=\"\"\/><\/figure>\n\n\n\n<hr class=\"wp-block-separator\"\/>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>5. (Fuvest)&nbsp; No diagrama P.V da figura, A, B e C representam transforma\u00e7\u00f5es poss\u00edveis de um g\u00e1s entre os estados I e II<\/strong><\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/lh4.googleusercontent.com\/QjxX63gv9qnQhrQlM_-j5dbm0EUqMoPiSG6PM036gYWu9kokazDhDFX5X5nvrSq4MWt_yeUCxCw7s8lVvS0wSlVkbLacK2Xu_I5ZPz9rHWy9cff2Jh_rxlLE19IB2yWRRyC9X1U1\" alt=\"\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Com rela\u00e7\u00e3o \u00e0 varia\u00e7\u00e3o&nbsp; da energia interna do g\u00e1s e ao trabalho&nbsp; por ele realizado, entre esses estados, \u00e9 correto afirmar que:<\/strong><\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/lh4.googleusercontent.com\/DUv0CgYtKfa18aJsHo_WOObIgThncK5mQJwr5CCxhylS0bpfqAmfsiOLwoTkh9zz1XkjETU5BC4V5gs3fB9GdxOJOX_2OAhyN2KeEwOh1lSYh1FZmkPpb4WIwtApOZjjTepnL9u8\" alt=\"\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Resposta: <\/strong>A<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">&nbsp;Como&nbsp; \u00e9 o mesmo para as tr\u00eas transforma\u00e7\u00f5es, devemos ter que:<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/lh3.googleusercontent.com\/WICCiNSWyILTe81vP7cYH1mOnYfAZ_RpPuGM52Yh3cWMYrBrfeXLIkdhQ3Vwu0etLwxKqUSGGaFLP_38n0KPdIBal8bh6MYtKIbJ6PGAifW3JluZ8pCRj5BRYW8fLKWP05CBbDyQ\" alt=\"\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">E como os trabalhos s\u00e3o dados pelas \u00e1reas sob as curvas das transforma\u00e7\u00f5es, de acordo com a figura abaixo, podemos concluir que:<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/lh4.googleusercontent.com\/2YVPcAL6fsY79jfjNjtqnBH3phwy8Dxjn4Lgft6ku_i9nAeodXx7u-IHtrv7VuJn9De_GVkgKMXLJh-eTzIrm2q4ErB2_10XX9J9kqmbbQGvz_1qeNE6JmTm3xkzIuUl0w9q4-lh\" alt=\"\"\/><\/figure>\n\n\n\n<hr class=\"wp-block-separator\"\/>\n\n\n\n<p class=\"wp-block-paragraph\">Espero que voc\u00ea tenha entendido um pouco melhor sobre <strong>Energia \u00e0s transforma\u00e7\u00f5es gasosas<\/strong>. E se quiser ajuda para melhorar seu n\u00edvel de F\u00edsica em outras mat\u00e9rias,\u00a0<strong><a href=\"https:\/\/professorpinguim.com.br\/\">entre em contato comigo e escolha o curso de F\u00edsica mais adequado para voc\u00ea<\/a>!<\/strong><\/p>\n\n\n\n<figure class=\"wp-block-image\"><a href=\"https:\/\/curso.professorpinguim.com.br\/pt\/comprar\/produto\/curso-gratuito-matematica-para-aprender-fisica\" target=\"_blank\" rel=\"noreferrer noopener\"><img decoding=\"async\" src=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2022\/02\/curso-fisica-para-matematica-professor-pinguim.png\" alt=\"Curso de Matem\u00e1tica para aprender F\u00edsica - Professor Pinguim\" class=\"wp-image-7950\"\/><\/a><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>SAIBA MAIS<\/strong><br>\u2705&nbsp;<a rel=\"noreferrer noopener\" href=\"https:\/\/professorpinguim.com.br\/blog\/resumo-com-exercicios-sobre-energia-interna-e-trabalho-da-forca-de-um-gas\/\" target=\"_blank\">Exerc\u00edcios de Energia interna e trabalho<\/a><strong><br>\u2705&nbsp;<\/strong><a href=\"https:\/\/professorpinguim.com.br\/blog\/revisao-com-exercicio-sobre-gases-ideias\/\" target=\"_blank\" rel=\"noreferrer noopener\">Exerc\u00edcios resolvido para treinar: G\u00e1s ideal<\/a><strong><br>\u2705&nbsp;<\/strong><a href=\"https:\/\/professorpinguim.com.br\/blog\/questoes-sobre-calorimetria-calor-latente-e-potencia\/\" target=\"_blank\" rel=\"noreferrer noopener\">Calor Latente e Pot\u00eancia<\/a><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Me acompanhe nas redes sociais: curta a minha&nbsp;<a href=\"https:\/\/www.facebook.com\/professorpinguim\/\"><strong>p\u00e1gina no Facebook<\/strong><\/a><strong>,<\/strong>&nbsp;me&nbsp;siga no&nbsp;<a href=\"https:\/\/www.instagram.com\/professorpinguim\/\"><strong>Instagram<\/strong><\/a><strong>,<\/strong>&nbsp;se inscreva no&nbsp;<a href=\"https:\/\/www.youtube.com\/c\/PinguimV%C3%ADdeoF%C3%ADsica\/?sub_confirmation=1\"><strong>Youtube<\/strong><\/a>&nbsp;e participe do meu canal oficial no&nbsp;<a href=\"https:\/\/professorpinguim.com.br\/telegram\"><strong>Telegram<\/strong><\/a>.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Hoje vamos aplicar a conserva\u00e7\u00e3o de energia da 1\u00aa Lei Termodin\u00e2mica \u00e0s transforma\u00e7\u00f5es gasosas. Acompanhe!<\/p>\n","protected":false},"author":1,"featured_media":8886,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[744,764,228,656],"tags":[814,751,533,815,536],"class_list":["post-8883","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-exercicios-resolvidos","category-ondas","category-optica","category-termologia","tag-1a-lei-termodinamica","tag-energia","tag-gas-ideal","tag-transformacoes","tag-transformacoes-gasosas"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v20.12 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Lista de exerc\u00edcios: 1\u00aa Lei Termodin\u00e2mica e Transforma\u00e7\u00f5es - Professor Pinguim | F\u00edsica<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/professorpinguim.com.br\/blog\/lista-de-exercicios-1a-lei-termodinamica-e-transformacoes\/\" \/>\n<meta property=\"og:locale\" content=\"pt_BR\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Lista de exerc\u00edcios: 1\u00aa Lei Termodin\u00e2mica e Transforma\u00e7\u00f5es - Professor Pinguim | F\u00edsica\" \/>\n<meta property=\"og:description\" content=\"Hoje vamos aplicar a conserva\u00e7\u00e3o de energia da 1\u00aa Lei Termodin\u00e2mica \u00e0s transforma\u00e7\u00f5es gasosas. 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