{"id":8657,"date":"2022-03-16T09:00:00","date_gmt":"2022-03-16T12:00:00","guid":{"rendered":"https:\/\/professorpinguim.com.br\/blog\/?p=8657"},"modified":"2023-08-06T21:01:03","modified_gmt":"2023-08-07T00:01:03","slug":"exercicios-de-eletrodinamica-carga-corrente-eletrica-e-ddp","status":"publish","type":"post","link":"https:\/\/professorpinguim.com.br\/blog\/exercicios-de-eletrodinamica-carga-corrente-eletrica-e-ddp\/","title":{"rendered":"Exerc\u00edcios de Eletrodin\u00e2mica: Carga, Corrente El\u00e9trica e DDP"},"content":{"rendered":"\n<p class=\"wp-block-paragraph\">Fala pessoal, tudo beleza? Nesta aula, vamos resolver alguns exerc\u00edcios da Eletrodin\u00e2mica, mais especificamente carga, corrente el\u00e9trica e ddp. Para resolv\u00ea-los, vamos antes revisar alguns conceitos e f\u00f3rmulas importantes. Acompanhe!<\/p>\n\n\n\n<!--more-->\n\n\n\n<h2 class=\"wp-block-heading\">Carga el\u00e9trica e corrente el\u00e9trica<\/h2>\n\n\n\n<p class=\"wp-block-paragraph\">Para calcular carga el\u00e9trica, utilizaremos a seguinte f\u00f3rmula:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">|Q| = n . e<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">n: n\u00famero de portadores de carga.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">e: carga el\u00e9trica elementar, de valor fixo 1,6.10<sup>-19<\/sup> C.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Q \u00e9 medido em coulomb (C)<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">J\u00e1 para calcular a intensidade m\u00e9dia de corrente el\u00e9trica que passa por um condutor, vamos utilizar:<\/p>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img decoding=\"async\" src=\"https:\/\/lh6.googleusercontent.com\/fpYFGWS3l6SWtr1ZLO_6FHEXD1GjpuLxEWsex-1RXQryXjoaMPN79C2mb0mwWYF6BCVVIXstmVPYIWsvikLprdy-7Yca0g7kSkeV3Ykz_AdrDxBwiRfC08Y77YCIF7T7KeivoVAd\" alt=\"\" width=\"112\" height=\"67\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">i<sub>m<\/sub> \u00e9 medido em amp\u00e8re (A).<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Note tamb\u00e9m que, \u00e0s vezes, para calcular a carga, teremos que utilizar a \u00e1rea de um gr\u00e1fico. Veja:<\/p>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img decoding=\"async\" src=\"https:\/\/lh6.googleusercontent.com\/Qgw9P9mgZKuYHSYfsllQ1KBoCo-TWqjmBh2mckgodfTKjzM6ZtfT1VDQihYvM2hZFCv8ZtwwPYDJi63QIffTWqQ9i1UTqnHvPj_C8amF4J4LWAmUDsfj2qAVWuEJJW8SK7giiyv_\" alt=\"\" width=\"313\" height=\"118\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Nesses casos, n\u00e3o podemos utilizar a f\u00f3rmula Q = i . \u0394t, pois ela s\u00f3 se aplica quando a corrente (i) for constante.<\/p>\n\n\n\n<hr class=\"wp-block-separator\"\/>\n\n\n\n<h2 class=\"wp-block-heading\">Exerc\u00edcios sobre carga, corrente el\u00e9trica e ddp<\/h2>\n\n\n\n<h3 class=\"wp-block-heading\">Quest\u00e3o 1<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>(UEL) Pela sec\u00e7\u00e3o reta de um condutor de eletricidade passam 12,0 C a cada minuto. Nesse condutor a intensidade da corrente el\u00e9trica, em amp\u00e9res, \u00e9 igual a<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">a) 0,08<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">b) 0,20<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">c) 5,0<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">d) 7,2<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">e) 12<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>RESOLU\u00c7\u00c3O:<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Veja que o enunciado nos fornece a carga que passa a cada minuto. Para isso, vamos utilizar a f\u00f3rmula que vimos acima, lembrando que temos que tuilizar segundos como unidade de tempo:<\/p>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img decoding=\"async\" src=\"https:\/\/lh4.googleusercontent.com\/HmVxmyHTtmTotqRdpRWn6CSnhz281u5cQqdlqtZxnThCOTnQIKQ8DknkdVS5pgy3YcAd_a2fKFZcz7C0p6znmVePg-cO5r0QHurWJ7Bcp6LoTq30o0GF2HoQDAkdcVBpICaLeRr-\" alt=\"\" width=\"95\" height=\"57\"\/><\/figure>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/lh3.googleusercontent.com\/HEf_sHC0Rf5XY5zrd4TFx8r2aSb_iHuyuqGThEgn71hokCFvmTnjH2ockL913JR0_9GnodGZF0sXiAprkZ_6B1AHXD05Qj4sLGQIRyRpe6whony20CdcLLVgaFU1_rbUjpS5fJMY\" alt=\"\" width=\"99\" height=\"62\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">i<sub>m<\/sub> = 0,2 A<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>RESPOSTA: B<\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Quest\u00e3o 2<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>(Unesp) Mediante est\u00edmulo, 2\u00d710<\/strong><strong><sup>5<\/sup><\/strong><strong> \u00edons de K+ atravessam a membrana de uma c\u00e9lula nervosa em 1,0 milissegundo. Calcule a intensidade dessa corrente el\u00e9trica, sabendo-se que a carga elementar \u00e9 1,5\u00d710<\/strong><strong><sup>-19<\/sup><\/strong><strong>.<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Repare na unidade de tempo: milissegundo. Isso significa 10-3 s. Com isso em mente, para descobrir a corrente m\u00e9dia, podemos usar a f\u00f3rmula. Mas, devido aos dados que temos, podemos combinar as duas f\u00f3rmulas que vimos:<\/p>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/lh3.googleusercontent.com\/g6_DIhaxL4s-Jm3AbuCUsA54ZlHP9sOWT5pkOYk3sd5Tymh2ZK7e9Hoh0tB2yEFC0rxEPGsQ6Y_hHFh2EiA7eYfB1bnN8sxIWp448_sYYmFphJt4N8zo_Edz_MhE0-mch4fRt1oP\" alt=\"\" width=\"143\" height=\"38\"\/><\/figure>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/lh6.googleusercontent.com\/WtRJy7vSisOEzx0T5xPd1lRGYST3I_Tb9qcknJJGz3ipYMC6PjHgVwaJH1n8mfZEk_LjuTQ4oTJePHVVmgRlPMacZcehJ8vI9myUyqCGVXN1RVVxffb8v_LBYl-8n9ypW3N0BDr4\" alt=\"\" width=\"139\" height=\"40\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">i<sub>m<\/sub> = 3,2.10<sup>-11<\/sup> A<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Quest\u00e3o 3<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>(UFSM-RS) Uma l\u00e2mpada permanece acesa durante 5 minutos por efeito de uma corrente de 2 A, fornecida por uma bateria. Nesse intervalo de tempo, a carga total (em C) liberada pela bateria \u00e9<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">a) 0,4<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">b) 2,5<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">c) 10<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">d) 150<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">e) 600<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>RESOLU\u00c7\u00c3O:<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Veja que aqui temos corrente constante, ent\u00e3o podemos utilizar a f\u00f3rmula: Q = i . \u0394t. Ent\u00e3o?<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Q = 2 . 5 . 60<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Q = 600 C<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Quest\u00e3o 4<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>A figura a seguir mostra uma pilha de 9 volts ligada a uma l\u00e2mpada por meio de fios condutores.<\/strong><\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/lh6.googleusercontent.com\/Gi8kZgonF3GBzX1nTu3RQp_k4eCOJQxv03PtRN_WkMcr2JNiayNFhxnxtnKCy9fviOhdtOhxMIBb9374b0uVNUX1LNswuOfTfHPS2n65dXh_pvemC7r57dHHblK7A0Jy_ZYtuunv\" alt=\"\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>a) Represente o sentido do movimento dos el\u00e9trons e o sentido convencional da corrente el\u00e9trica.<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Vamos lembrar que na Qu\u00edmica fala-se que a corrente vai no sentido das cargas positivas. Por\u00e9m, na F\u00edsica, quem anda \u00e9 el\u00e9tron, que tem carga positiva. Ent\u00e3o temos que falar que a corrente (i) anda no sentido oposto ao sentido dos el\u00e9trons.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Ent\u00e3o se o el\u00e9tron \u00e9 puxado pelo polo positivo da pilha (em cima), a corrente el\u00e9trica no sentido oposto. Podemos afirmar ent\u00e3o que o el\u00e9tron desce e a corrente sobe.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>b) A ddp pode ser entendida com a ra\u00e7\u00e3o entre a energia el\u00e9trica e a quantidade de carga que atravessa a pilha.<\/strong><\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/lh4.googleusercontent.com\/UAFk2h0b-l1ajDHuAcBfXtoCjDuZls6VVk5DCKeCNW4pYP4iEkGrN01C36yCPfUw66UO7o9J0JXpdKUnFAgNUGHyqcQw5zMc3_Fmfiv7criTEgn63aVLiGOe4HOVPr7wfhH6oT22\" alt=\"\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Qual a energia el\u00e9trica que uma carga de 20 C adquire ao atravessar a pilha?<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Basta utilizarmos a f\u00f3rmula dada:<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/lh4.googleusercontent.com\/gehV_soIclXm1G83XcNrEIHS2xYryrWWSMtkqofeyFN_NiXGIiajGjPI9ATIZ7_4SuxKLyqLR4vhWGfMjVEawz8cqlfsP2aIv9K3Ki0WW-RzYjnhhTMkddlIXY3yY7Q3gieaGFOQ\" alt=\"\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">E<sub>el<\/sub> = 180 J<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Quest\u00e3o 5<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>A corrente el\u00e9trica de um condutor met\u00e1lico tem calor representado no gr\u00e1fico, durante 100 s.<\/strong><\/p>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/lh5.googleusercontent.com\/gHGnyQERUoLdTbQht2cEDQlqxpe9-T-4blTr_f2PDx6ORob7xirIwYN_SwtI0l6mUOag-DZZKPdc7X98swipX0YDpVojhSUntDqqsYP6SgO5z2-MEjqXpbV2i1JfHLm9l1abuckL\" alt=\"\" width=\"152\" height=\"119\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>a) Determine a quantidade de carga el\u00e9trica, em coulomb, que atravessa a sec\u00e7\u00e3o transversal desse condutor.<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Veja que n\u00e3o podemos utilizar a f\u00f3rmula Q = i . \u0394t, pois a corrente n\u00e3o \u00e9 constante. Ent\u00e3o devemos utilizar a \u00e1rea do gr\u00e1fico, que se trata de um trap\u00e9zio:<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/lh6.googleusercontent.com\/57ZfAGnrEtNleXi4YXGGgxZeTFgOUfaRmNLqZU4EI8yVE6gH-p2uhXWbKw5i2XUGF3rRix_Mt40Hoyn2GU2mEsJNY7LYen9t5o24_fkg4TBBbNbHPyu6psyI5XXyX9MI0bOo6vLy\" alt=\"\"\/><\/figure>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/lh3.googleusercontent.com\/-WYMw1_qEgdubmdALrYV9YVb-wkgM_5Z2F_Eqlk157Tt64rJjWcaynpIisI9YtwNexwSdEwy0aK6j437eBTewez5vP3t9m03_k9rxD4GLEXAIy8uWxUEULYbBbZ5XK40uU7POgQe\" alt=\"\" width=\"137\" height=\"38\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Q = 1600 C<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>b) Calcule a intensidade m\u00e9dia da corrente el\u00e9trica, em amp\u00e9re, nesses 100 s.<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Para corrente m\u00e9dia, temos uma f\u00f3rmula:<\/p>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/lh6.googleusercontent.com\/8LFQYKEEQmLg-Dl2k_Z7AjpZKRxIEfv1qtyPFHJPvUrdPurS8Oz8mbgE89ssMnqUrcV8MpF6UT-pO1XTKNeSjrNeVF7nCX6Q5C6uGafZDh8Ego_g9UdqfkVgmQZV2v6C0DXzG6vq\" alt=\"\" width=\"119\" height=\"56\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">i<sub>m<\/sub> = 16 A<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Quest\u00e3o 6<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>(Unicamp) Outro exemplo de desenvolvimento, com vistas a recargas r\u00e1pidas, \u00e9 o prot\u00f3tipo de uma bateria de \u00edon-l\u00edtio, com estrutura tridimensional. Considere que uma bateria, inicialmente descarregada, \u00e9 carregada com uma corrente m\u00e9dia i<\/strong><strong><sub>m<\/sub><\/strong><strong> = 3,2 A at\u00e9 atingir sua carga m\u00e1xima de Q = 0,8 Ah . O tempo gasto para carregar a bateria \u00e9 de<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">a) 240 minutos.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">b) 90 minutos.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">c) 15 minutos.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">d) 4 minutos.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>RESOLU\u00c7\u00c3O:<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Quando uma quest\u00e3o nos traz Ah (amp\u00e8re-hora), estamos falando de corrente por tempo, ou seja, \u00e9 uma unidade de carga. Vou deixar as unidades para repararmos algo:<\/p>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/lh4.googleusercontent.com\/vfxcaVUg5vGNpiWCqeTx5YkUw5PjwZWkjlx7daqdof04iXJ68PrYoHPgOYjo7wBua2AfYzZDW4RhcOY3UALoM8jrrgLZxZ9-fS5pGzl8MuD3NUQX9TvZmmS2uYs9fNVmAQtDiJLM\" alt=\"\" width=\"131\" height=\"73\"\/><\/figure>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/lh5.googleusercontent.com\/TCTZajwkm4wNxJqx3edmWTj6PqRs2GFulkJv3E2HOL2jPqiZVuePrIRhCBddvily58U6iM-tpxHbRGjcb7ymPEnWriIamh-rhdlegFw0pZqkUGhbJxda9Yjq5uXNdqMfl72NXEDO\" alt=\"\" width=\"133\" height=\"40\"\/><\/figure>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/lh5.googleusercontent.com\/3LV4MDEP7bNBWMhkBVgqFgt2ZU8fMyTZrZmvUab9nJ8Aaw0NNW2QyHUzcAiEtddjeS-gdhUvyZKc4518ZwrTV3E4Xvl7uR660e7t7nBNkXg93y1EyBIxVEPNrsQfaL1iRvcU9NZC\" alt=\"\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Repare que o resultado deu na unidade hora. E, se fizermos as contas, vamos chegar que essa fra\u00e7\u00e3o equivale a 1\/4 de hora, ou seja, 15 minutos.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Quest\u00e3o 7<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>(Unifesp) Num livro de eletricidade voc\u00ea encontra tr\u00eas informa\u00e7\u00f5es: a primeira afirma que isolantes s\u00e3o corpos que n\u00e3o permitem a passagem da corrente el\u00e9trica; a segunda afirma que o ar \u00e9 isolante e a terceira afirma que, em m\u00e9dia, um raio se constitui de uma descarga el\u00e9trica correspondente a uma corrente de 10000 amp\u00e8res que atravessa o ar e desloca, da nuvem \u00e0 Terra, cerca de 20 coulombs.<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Pode-se concluir que essas tr\u00eas informa\u00e7\u00f5es s\u00e3o:<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">a) coerentes e que o intervalo de tempo m\u00e9dio de uma descarga el\u00e9trica \u00e9 de 2,0\u221910<sup>-3<\/sup> s.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">b) conflitantes e que o intervalo de tempo m\u00e9dio de uma descarga el\u00e9trica \u00e9 de 2,0\u221910<sup>-3<\/sup> s.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">c) coerentes e que o intervalo de tempo m\u00e9dio de uma descarga el\u00e9trica \u00e9 de 2,0\u221910<sup>-4<\/sup> s.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">d) conflitantes e que o intervalo de tempo m\u00e9dio de uma descarga el\u00e9trica \u00e9 de 2,0\u221910<sup>-6<\/sup> s.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">e) conflitantes e que n\u00e3o \u00e9 poss\u00edvel avaliar o intervalo de tempo m\u00e9dio de uma descarga el\u00e9trica.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>RESOLU\u00c7\u00c3O:<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Vamos analisar as informa\u00e7\u00f5es:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">I) Verdadeira. Se o corpo \u00e9 isolante, n\u00e3o h\u00e1 tantos el\u00e9trons livres para portar carga. Por\u00e9m, h\u00e1 corpos que s\u00e3o isolantes, mas que, em determinadas situa\u00e7\u00f5es, s\u00e3o condutores. tudo vai depender da ddp.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">II) Nem sempre o ar \u00e9 isolante.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">III) Veja que pelos dados fornecidos podemos calcular o tempo:<\/p>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/lh3.googleusercontent.com\/_gvimLcn_dEFIsMDdkOnwVTzfxEcCJLsSt2ifMyW259pACNXgoBlFjNheLh_x3OYDuAOxqMY973CDl7ck8QyQ-ODF8Z2FgfdzQcPSVM0ECk4iv9EO5VSr_-xn-3RiuqSiapyv3VE\" alt=\"\" width=\"124\" height=\"69\"\/><\/figure>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/lh3.googleusercontent.com\/1Wvyz2VS708JPhnPhVvFPFBRWWfd6Jr-j37j7ktZTaHqEHuPLpEA8RPvVUYs1KXhhpYhZkYHdxat5cjfCo4RMx_OI7XJTLvQvezmImEH-sB_kfu2LuHwMZrDa5yY1D06GIlHnP8s\" alt=\"\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">\u0394t = 2.10<sup>-3<\/sup> s ou 0,002 s<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>RESPOSTA: C<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Para aprender mais:<\/strong><\/h3>\n\n\n\n<figure class=\"wp-block-embed-youtube wp-block-embed is-type-video is-provider-youtube wp-embed-aspect-16-9 wp-has-aspect-ratio\"><div class=\"wp-block-embed__wrapper\">\n<iframe title=\"Corrente El\u00e9trica - F\u00edsica - Eletrodin\u00e2mica - Aula 1 - Professor Pinguim\" width=\"800\" height=\"450\" src=\"https:\/\/www.youtube.com\/embed\/gb_yf-K45pM?start=5&amp;feature=oembed\" frameborder=\"0\" allow=\"accelerometer; autoplay; clipboard-write; encrypted-media; gyroscope; picture-in-picture; web-share\" referrerpolicy=\"strict-origin-when-cross-origin\" allowfullscreen><\/iframe>\n<\/div><\/figure>\n\n\n\n<hr class=\"wp-block-separator\"\/>\n\n\n\n<p class=\"wp-block-paragraph\">Espero que voc\u00ea tenha entendido um pouco melhor como resolver exerc\u00edcios sobre carga, corrente el\u00e9trica e ddp. E se quiser ajuda para melhorar seu n\u00edvel de F\u00edsica em outras mat\u00e9rias,<a href=\"https:\/\/professorpinguim.com.br\/\"> entre em contato comigo e escolha o curso de F\u00edsica mais adequado para voc\u00ea<\/a>!<\/p>\n\n\n\n<figure class=\"wp-block-image\"><a href=\"https:\/\/curso.professorpinguim.com.br\/pt\/comprar\/produto\/curso-gratuito-matematica-para-aprender-fisica\" target=\"_blank\" rel=\"noreferrer noopener\"><img decoding=\"async\" src=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2022\/02\/curso-fisica-para-matematica-professor-pinguim.png\" alt=\"Curso gr\u00e1tis de Matem\u00e1tica para aprender F\u00edsica - Professor Pinguim\" class=\"wp-image-7950\"\/><\/a><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>SAIBA MAIS<\/strong><br>\u2705&nbsp;<a rel=\"noreferrer noopener\" href=\"https:\/\/professorpinguim.com.br\/blog\/lista-de-exercicios-sobre-condutor-em-equilibrio-eletrostatico\/\" target=\"_blank\">Quest\u00f5es sobre condutor em equil\u00edbrio eletrost\u00e1tico<\/a><br>\u2705&nbsp;<a rel=\"noreferrer noopener\" href=\"https:\/\/professorpinguim.com.br\/blog\/exercicios-resolvidos-sobre-campo-eletrico-uniforme-ceu\/\" target=\"_blank\">Exerc\u00edcios sobre Campo El\u00e9trico Uniforme (CEU)<\/a><br>\u2705&nbsp;<a href=\"https:\/\/professorpinguim.com.br\/blog\/potencial-eletrico-energia-e-trabalho-exercicios-com-gabarito\/\" target=\"_blank\" rel=\"noreferrer noopener\">Potencial el\u00e9trico, energia potencial e trabalho da for\u00e7a el\u00e9trica<\/a><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Me acompanhe nas redes sociais: curta a minha&nbsp;<a href=\"https:\/\/www.facebook.com\/professorpinguim\/\"><strong>p\u00e1gina no Facebook<\/strong><\/a><strong>,<\/strong>&nbsp;me&nbsp;siga no&nbsp;<a href=\"https:\/\/www.instagram.com\/professorpinguim\/\"><strong>Instagram<\/strong><\/a><strong>,<\/strong>&nbsp;se inscreva no&nbsp;<a href=\"https:\/\/www.youtube.com\/c\/PinguimV%C3%ADdeoF%C3%ADsica\/?sub_confirmation=1\"><strong>Youtube<\/strong><\/a>&nbsp;e participe do meu canal oficial no&nbsp;<a href=\"https:\/\/professorpinguim.com.br\/telegram\"><strong>Telegram<\/strong><\/a>.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Nesta aula, vamos resolver alguns exerc\u00edcios da Eletrodin\u00e2mica, mais especificamente carga, corrente el\u00e9trica e ddp. Para resolv\u00ea-los, vamos antes revisar alguns conceitos e f\u00f3rmulas importantes. Acompanhe!<\/p>\n","protected":false},"author":1,"featured_media":8660,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[746,262,729,744,770,742],"tags":[446,443,806,807,211],"class_list":["post-8657","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-eletricidade","category-eletrodinamica","category-eletrostatica","category-exercicios-resolvidos","category-gravitacao","category-hidrostatica","tag-carga-eletrica","tag-corrente-eletrica","tag-ddp","tag-eletrodinamica","tag-exercicios"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v20.12 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Exerc\u00edcios de Eletrodin\u00e2mica: Carga, Corrente El\u00e9trica e DDP - Professor Pinguim | F\u00edsica<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/professorpinguim.com.br\/blog\/exercicios-de-eletrodinamica-carga-corrente-eletrica-e-ddp\/\" \/>\n<meta property=\"og:locale\" content=\"pt_BR\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Exerc\u00edcios de Eletrodin\u00e2mica: Carga, Corrente El\u00e9trica e DDP - Professor Pinguim | F\u00edsica\" \/>\n<meta property=\"og:description\" content=\"Nesta aula, vamos resolver alguns exerc\u00edcios da Eletrodin\u00e2mica, mais especificamente carga, corrente el\u00e9trica e ddp. 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