{"id":7949,"date":"2022-02-21T09:00:00","date_gmt":"2022-02-21T12:00:00","guid":{"rendered":"https:\/\/professorpinguim.com.br\/blog\/?p=7949"},"modified":"2023-08-06T21:01:32","modified_gmt":"2023-08-07T00:01:32","slug":"5-questoes-resolvidas-sobre-movimento-uniformemente-variado-muv","status":"publish","type":"post","link":"https:\/\/professorpinguim.com.br\/blog\/5-questoes-resolvidas-sobre-movimento-uniformemente-variado-muv\/","title":{"rendered":"5 Quest\u00f5es resolvidas sobre Movimento Uniformemente Variado (MUV)"},"content":{"rendered":"\n<p class=\"wp-block-paragraph\">Fala, pessoal! Nesta aula vamos resolver exerc\u00edcios sobre Movimento Uniformemente Variado (MUV). Antes, por\u00e9m, vamos relembrar algumas coisas desta disciplina.<\/p>\n\n\n\n<!--more-->\n\n\n\n<p class=\"wp-block-paragraph\"><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">A f\u00f3rmula mais importante que vamos utilizamos nas quest\u00f5es de MUV \u00e9 a Equa\u00e7\u00e3o de Torricelli:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>v\u00b2 = v<\/strong><strong><sub>0<\/sub><\/strong><strong>\u00b2 + 2 . a . \u0394s<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">v: velocidade do corpo.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">v<sub>0<\/sub>: velocidade inicial.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">a: acelera\u00e7\u00e3o.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">\u0394s: varia\u00e7\u00e3o de espa\u00e7o (deslocamento escalar).<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">\u00c9 importante lembrar que, em muitas quest\u00f5es, vamos nos deparar com gr\u00e1ficos. Nesses casos, temos que ter nossos conhecimentos de matem\u00e1tica afiados para calcular a \u00e1rea das figuras formadas no gr\u00e1fico, como tri\u00e2ngulos e trap\u00e9zios.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Por\u00e9m, nem sempre poderemos utilizar Torricelli, porque a quest\u00e3o pode nos dar grandezas diferentes. Assim, temos outras f\u00f3rmulas que podemos utilizar nos exerc\u00edcios de MUV, de acordo com a grandeza que n\u00e3o temos \u00e0 disposi\u00e7\u00e3o. Veja:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Para quando n\u00e3o tivermos a posi\u00e7\u00e3o (s):<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">\u00a0<img decoding=\"async\" width=\"46\" height=\"32\" src=\"https:\/\/lh6.googleusercontent.com\/VYqkwoyY2l7jH6jNqDbKiKm1brmQ5QmmHd19S11A6qRzMfvtO7uusIVKqz7WSoVk8LOEKhEtkjBp5VBq-Ivj0N8eI_Zc38F3Xfopjyi3M8GvzAusmA-KR1g2gZjNT6Rwz1hXf02gQvucuolMs7fPmg\"><\/p>\n\n\n\n<p class=\"wp-block-paragraph\"> <strong>ou<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\"> v = v<sub>0<\/sub> + a . t<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Para quando n\u00e3o tivermos a velocidade (v)<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">: <img decoding=\"async\" src=\"https:\/\/lh4.googleusercontent.com\/pZl0JxSqu2zp4q84FPM3jJpryGo2gHyDpMvUeCeX-2gUsL6pPHU10K-gigjJkugElm2Mv3B8wfywe3dOnleMVtJkFyEwAiUcg02z-XKL7GJNmLqihD6NfK59rzIxgkS3vUgUcJXPz2hu4J_z5XvU-Q\" width=\"107\" height=\"28\"><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Para quando n\u00e3o tivermos a acelera\u00e7\u00e3o (a):<\/p>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img decoding=\"async\" src=\"https:\/\/lh5.googleusercontent.com\/2_K2Q5-0LhGlq528dsLxLvcWWU4ZV8d6T735PKwvP9n3Q1LFPL1UTetCOxqp4baxaJhX8DKMMnN7hj48J6JPCIUlmiqjG1QFHzPBqR9B-L2lOLspDuorOnFy0mA1hcpWBkpaKHS0kL2IkPizBTbk9w\" alt=\"\" width=\"204\" height=\"50\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Para quando n\u00e3o tivermos o tempo (t):<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">&nbsp;v\u00b2 = v<sub>0<\/sub>\u00b2 + 2 . a . \u0394s<\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><a href=\"https:\/\/professorpinguim.com.br\"><img loading=\"lazy\" decoding=\"async\" width=\"1024\" height=\"488\" src=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2023\/02\/EXTENSIVO-BLOG-1-1024x488.png\" alt=\"Extensivo de Fisica para Vestibulares Paulistas\" class=\"wp-image-19816\" srcset=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2023\/02\/EXTENSIVO-BLOG-1-1024x488.png 1024w, https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2023\/02\/EXTENSIVO-BLOG-1-300x143.png 300w, https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2023\/02\/EXTENSIVO-BLOG-1-768x366.png 768w, https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2023\/02\/EXTENSIVO-BLOG-1-670x319.png 670w, https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2023\/02\/EXTENSIVO-BLOG-1-1060x505.png 1060w, https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2023\/02\/EXTENSIVO-BLOG-1.png 1280w\" sizes=\"(max-width: 1024px) 100vw, 1024px\" \/><\/a><\/figure>\n\n\n\n<h2 class=\"wp-block-heading\">Exerc\u00edcios sobre MUV<\/h2>\n\n\n\n<h3 class=\"wp-block-heading\">Quest\u00e3o 1<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>(Unicamp) A Ag\u00eancia Espacial Brasileira est\u00e1 desenvolvendo um ve\u00edculo lan\u00e7ador de sat\u00e9lites (VLS) com a finalidade de colocar sat\u00e9lites em \u00f3rbita ao redor da Terra. A ag\u00eancia pretende lan\u00e7ar o VLS em 2016, a partir do Centro de Lan\u00e7amento de Alc\u00e2ntara, no Maranh\u00e3o.<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>a) Considere que, durante um lan\u00e7amento, o VLS percorre uma dist\u00e2ncia de 1200 km em 800 s. Qual \u00e9 a velocidade m\u00e9dia do VLS nesse trecho?<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">A primeira coisa que devemos fazer \u00e9 lembrar da f\u00f3rmula da velocidade m\u00e9dia:<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/lh6.googleusercontent.com\/WyDE6tW-BzOg4Ww6TBFpnincgfXW1rQqX_9efIeN-X8ItNKxCwF_CPvitwmJuqlqnWNTeIe2AzB0wiSrasD8ScbuOJIOvCFAotH8DtfUOxRCVrMJJpi5uwjLxJecbnDHymMt1AoxChLjJkh-aEt9qQ\" alt=\"\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">V<sub>m<\/sub> = 1500 m\/s<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>b) Suponha que no primeiro est\u00e1gio do lan\u00e7amento o VLS suba a partir do repouso com acelera\u00e7\u00e3o resultante constante de m\u00f3dulo a<\/strong><strong><sub>R<\/sub><\/strong><strong>. Considerando que o primeiro est\u00e1gio dura 80 s, e que o VLS percorre uma dist\u00e2ncia de 32 km, calcule a<\/strong><strong><sub>R<\/sub><\/strong><strong>.<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Se o corpo parte do repouso, temos que v<sub>0<\/sub> = 0. E se a acelera\u00e7\u00e3o \u00e9 constante, temos um MUV. Veja tamb\u00e9m que \u0394t = 80 e que \u0394s = 32000.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Temos que encontrar uma f\u00f3rmula que contenha todas as grandezas pedidas. No caso, n\u00e3o sabemos apenas a acelera\u00e7\u00e3o. Portanto:<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/lh4.googleusercontent.com\/b5kkHIt3ekCfYLrFYTtXB0Kk-lCix-Q9yDSl1kSDRRci3yXi3EkTEkDFMY-Jtc7avBnNmTqPs6jpvOZsmiwAzhJZblta4685T3SyJqoCpZdaZxyh4Y1vJJ-5PCH7m3REN-mEealXC59L2F55mYWwjA\" alt=\"\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">a = 10 m\/s<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Quest\u00e3o 2<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>(Pucrs) Muitos acidentes acontecem nas estradas porque o motorista n\u00e3o consegue frear seu carro antes de colidir com o que est\u00e1 \u00e0 sua frente. Analisando as caracter\u00edsticas t\u00e9cnicas, fornecidas por uma revista especializada, encontra-se a informa\u00e7\u00e3o de que um determinado carro consegue diminuir sua velocidade, em m\u00e9dia, 5,0 m\/s a cada segundo. Se a velocidade inicial desse carro for 90,0 km\/h (25,0 m\/s), a dist\u00e2ncia necess\u00e1ria para ele conseguir parar ser\u00e1 de, aproximadamente,<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">a) 18,5 m<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">b) 25,0 m<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">c) 31,5 m<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">d) 45,0 m<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">e) 62,5 m<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>RESOLU\u00c7\u00c3O:<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Repare: quando ele fala que o carro diminui sua velocidade, temos um \u0394v negativo. Nesse caso: \u0394v = -5 m\/s. J\u00e1 \u0394t = 1 s e v<sub>0<\/sub> = 25 m\/s. Note, agora, que ele nos diz que o carro vai parar, ou seja, a velocidade final ser\u00e1 igual a zero (v = 0).<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Vamos novamente buscar uma f\u00f3rmula que atenda \u00e0 nossa necessidade, que nesta quest\u00e3o \u00e9 o \u0394s. Ent\u00e3o, nosso primeiro passo ser\u00e1:<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/lh3.googleusercontent.com\/trtkL0GIBzl5NZuTQ3V4Djvxd9wqnpFJ0H1oyW5ZuhcQJtfo7tMwQom8s9F6f9EQLi0iCbZXOFVwtpVCXp38IQ_ML5_pKrVGPgfA_29_oIBKs5LPTYG3oqhWyKBiyS5URvn2ZE9BK-XvgoZQvu_ztw\" alt=\"\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">a = -5 m\/s\u00b2<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Veja que temos duas situa\u00e7\u00f5es: as informa\u00e7\u00f5es que utilizamos para calcular a acelera\u00e7\u00e3o n\u00e3o fazem parte da mesma situa\u00e7\u00e3o dos outros dados que temos, incluindo o \u0394s que queremos encontrar.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Como n\u00e3o temos a grandeza tempo, podemos usar Torricelli:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">v\u00b2 = v<sub>0<\/sub>\u00b2 2 + 2. a . \u0394s<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">0 = 25 . 2 . (-5) . \u0394s<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">\u0394s = 62,5 m<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>RESPOSTA: E<\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Quest\u00e3o 3<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>(Uern) Seja o gr\u00e1fico da velocidade em fun\u00e7\u00e3o do tempo de um corpo em movimento retil\u00edneo uniformemente variado representado abaixo.<\/strong><\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/lh4.googleusercontent.com\/KJzAvCc2DSuVLp162UPbQL1hTEReIpMlBRy_6Sf6oOTty-FjGSu_uXIAx0PcvXLHkiZgjMab9eeH6jTVXUexH7k1Oqrqp10C5adY-3nKpy3JT-_bZct4rCq6yTJuQC1e_13PE-rbi7SnDYYGGEnDsQ\" alt=\"\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Considerando a posi\u00e7\u00e3o inicial desse movimento igual a 46 m, ent\u00e3o a posi\u00e7\u00e3o do corpo no instante t = 8 s \u00e9<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">a) 54 m.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">b) 62 m.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">c) 66 m.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">d) 74 m.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>RESOLU\u00c7\u00c3O:<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Vamos lembrar que a equa\u00e7\u00e3o que nos d\u00e1 a posi\u00e7\u00e3o \u00e9:<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/lh6.googleusercontent.com\/OItPcPxjDU8CQo8ZWCxLUgJAjQd1TPhjkwP4Na86ryAGueSmtZPIy_loCC39FzFGUfA8BnkiOSrQKqaKql3d2Cs_PIVL7L2GR9fgkiDckHDQaI2d6G3HErH6VvdSqsLxwmkrVRDBcAkD76_sm4op1A\" alt=\"\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Por\u00e9m, ainda precisamos da acelera\u00e7\u00e3o para usar essa f\u00f3rmula. Como n\u00e3o temos a posi\u00e7\u00e3o (s), a f\u00f3rmula que podemos utilizar para calcular a acelera\u00e7\u00e3o \u00e9:<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/lh6.googleusercontent.com\/0GB53j025nkooJgkKBAAHA5Bf_fOVs92AK9BiAJPLIclgKICkyzQ6zP7bWi88nUTY9h-ht7qnnNPgKe5cnGdzk1Y32ldttI5JDbrPYXWC0fpX6K15hmpJnZXNKWruhncNqxMqqKNLUzE9mR2_7zRjg\" alt=\"\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Para isso, vou usar os dados que j\u00e1 tenho no gr\u00e1fico. Repare que, como a acelera\u00e7\u00e3o \u00e9 constante (MUV), o mesmo valor que posso calcular entre t = 0 e t = 5 s vale para o intervalo de t = 5 s a t = 8 s.<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/lh3.googleusercontent.com\/dhj0HVi62qpnHc3iF0CXyK-zwX7HbdmH_N3hTTse7wdQvyc7sWSgWwNEnhGJNUVrqdB8wFOeltJ19A8Y-Ip7cuYe63iMCSawDoJSz0okNms-bdaEBJssvBiC3wsShDNflFAp7GcJ7BJUVEdvenE49g\" alt=\"\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">a = -2 m\/s<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Agora, basta substituir:<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/lh5.googleusercontent.com\/ZvsX2v2-88-wyFp_aYqHiVprxOjIU8YTiS8KoVmCSJw8siffUtP0HTWKrnrDk7JXjdHdWlrSFgthHAx7FT04hXuNH5MzPefThSGs8DtH-xMaUPxezffGcCSphK2wLi3DtAgTioLxokJy1zI80lWEnA\" alt=\"\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">\u0394s = 62 m<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>RESPOSTA: B<\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Quest\u00e3o 4<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Determine a velocidade escalar m\u00e9dia entre os instantes t = 0 e t = T, para o movimento descrito pelo gr\u00e1fico v x t abaixo.<\/strong><\/p>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/lh3.googleusercontent.com\/8bb4GadCVC7qwCamz5wHpLhNXbZOyEwnB8d48kN4ZekoiS_92FjZPQZm9lVDFlO4XW1VsDt1_-po0lrjatn78aZ8svqklo7bdz7B5u-2m9aVQOySajigsxAFrTgx_QdD8b5l0ea51yRTJNHIU4lCYg\" alt=\"\" width=\"295\" height=\"162\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>RESOLU\u00c7\u00c3O:<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Vamos lembrar que temos duas maneiras de calcular a velocidade m\u00e9dia:<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/lh4.googleusercontent.com\/NGC1y1KR_CG_kzSZA3p3cXNCY-P2x83b2PEjNSBKDrqtErWeLCT-WkkDmCBGDspxr3mXcAiEx6HapsRdx69HnOSDnGF98dh0YsZGQvPNp7Y76xJT3aYcw65uCjnuLDxgyYH1CvjNiMpbzp9C61ZcGA\" alt=\"\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Essas f\u00f3rmulas valem para um \u00fanico MUV, como vemos no gr\u00e1fico. Aten\u00e7\u00e3o: se o gr\u00e1fico n\u00e3o possuir apenas uma reta, ent\u00e3o h\u00e1 mais de um MUV.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Ent\u00e3o, utilizado as informa\u00e7\u00f5es que temos:<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/lh4.googleusercontent.com\/4vYllIpkygHbXGJZ5yrUBhtfoY-dnvbW83UBlwZ_6eeRplxuzdnfIjkZq7gFdqRgOszz_ZjasBYIneVKlVaWnlQyqhfcbFPPuHC5tY2D4-pdIgejptlnytdDm9vhxksGcRZS3i4F9FXk5kYhbWNuiA\" alt=\"\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">V<sub>m<\/sub> = 15 m\/s<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Quest\u00e3o 5<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>(Fuvest-SP-modificada) Um corpo movimenta-se sobre o eixo X, com acelera\u00e7\u00e3o constante, de acordo com a fun\u00e7\u00e3o hor\u00e1ria x = 2 + 2 . t &#8211; 2t\u00b2, em que t \u00e9 dado em segundos e x em metros.<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>a) Qual a velocidade escalar m\u00e9dia entre t = 0 e t = 2 s?<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Repare que em t = 0, temos que x<sub>0<\/sub> = 2 m. J\u00e1 para t = 2, basta usar a f\u00f3rmula que ele nos deu:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">x = 2 + 2 . 2 &#8211; 2 . 2\u00b2<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">x = -2 m<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Agora:<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/lh4.googleusercontent.com\/U6CS07WUX4rBIxFTHYCleSmxw8-IXbqNwJLVrxrvgB8dQXRJr1uGiK0ZQVyrwoPi4Rvq6jqFmDjObhGFIYk4WS5TnFzEUOKlh98bbqnS1beW49o38dry_FkzmbOTfLk83AmDGsHrTLycr46DBHgfXg\" alt=\"\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">&nbsp;V<sub>m<\/sub> = -2 m\/s<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>b) Qual a velocidade no instante t = 2 s?<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Veja que o que calculamos n\u00e3o \u00e9 a velocidade instant\u00e2nea final. Para isso, precisamos utilizar:&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">v = v<sub>0<\/sub> + a . t<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Veja que a f\u00f3rmula que temos no enunciado nada mais \u00e9 que:<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/lh3.googleusercontent.com\/xyO2pEChNPhoTR67HA458gx5iJDmHiWd-pDSPxZ1VUJi3-UzjOQrvay9NAu_O9dJpdmT3kYx48vcWmHhv97Hf7krgUIgBDXFwT5v7Mtey8hENWl0CFUUPXDmp4rwn53JMvzC-HF5YnIhSrQTHRr0Ug\" alt=\"\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Ent\u00e3o, basta comparar essa equa\u00e7\u00e3o com a do enunciado. Sabemos, portanto, que v<sub>0<\/sub> = 2 m\/s e que a\/2 = -2, ent\u00e3o a = -4 m\/s\u00b2. Agora basta voltar \u00e0 equa\u00e7\u00e3o da velocidade:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">v = v<sub>0<\/sub> + a . t<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">v = 2 &#8211; 4 . 2<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">v = -6 m\/s<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>c) Em que instante esse corpo inverte o sentido do movimento? Em que posi\u00e7\u00e3o ocorre essa invers\u00e3o?<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Inverter o sentido significa parar. Ent\u00e3o, v = 0:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">v = 2 &#8211; 4 . t<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">0 = 2 &#8211; 4 . t<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">t = 0,5 s<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Para achar a posi\u00e7\u00e3o de invers\u00e3o, basta substituir na f\u00f3rmula que a pr\u00f3pria quest\u00e3o nos deus:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">x = 2 + 2 . 0,5 &#8211; 2 . 0,5\u00b2<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">x = 2,5 m<\/p>\n\n\n\n<hr class=\"wp-block-separator\"\/>\n\n\n\n<p class=\"wp-block-paragraph\">Espero que voc\u00ea tenha entendido um pouco melhor como resolver os<strong> Exerc\u00edcios de Movimento Uniformemente Variado (MUV)<\/strong>. E se quiser praticar mais, confira minha live de resolu\u00e7\u00e3o de mais exerc\u00edcios sobre o tema. Assista:<\/p>\n\n\n\n<figure class=\"wp-block-embed-youtube wp-block-embed is-type-video is-provider-youtube wp-embed-aspect-16-9 wp-has-aspect-ratio\"><div class=\"wp-block-embed__wrapper\">\n<iframe title=\"Cinem\u00e1tica MUV - Um autom\u00f3vel partindo do repouso, pode - F\u00edsica - Professor Pinguim\" width=\"800\" height=\"450\" src=\"https:\/\/www.youtube.com\/embed\/sG2jZj69A0A?feature=oembed\" frameborder=\"0\" allow=\"accelerometer; autoplay; clipboard-write; encrypted-media; gyroscope; picture-in-picture; web-share\" referrerpolicy=\"strict-origin-when-cross-origin\" allowfullscreen><\/iframe>\n<\/div><\/figure>\n\n\n\n<hr class=\"wp-block-separator\"\/>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>SAIBA MAIS<\/strong><br>\u2705 <a rel=\"noreferrer noopener\" href=\"https:\/\/professorpinguim.com.br\/blog\/muv-e-equacao-de-torricelli\/\" target=\"_blank\">MUV e Equa\u00e7\u00e3o de Torricelli<\/a><br>\u2705 <a rel=\"noreferrer noopener\" href=\"https:\/\/professorpinguim.com.br\/blog\/questoes-para-praticar-de-velocidade-relativa\/\" target=\"_blank\">Exerc\u00edcios sobre velocidade relativa<\/a><br>\u2705\u00a0<a rel=\"noreferrer noopener\" href=\"https:\/\/professorpinguim.com.br\/blog\/movimento-uniforme-exercicios-resolvidos\/\" target=\"_blank\">Quest\u00f5es sobre movimento uniforme<\/a><\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><a href=\"https:\/\/professorpinguim.com.br\"><img loading=\"lazy\" decoding=\"async\" width=\"1024\" height=\"488\" src=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2023\/02\/EXTENSIVO-BLOG-1-1024x488.png\" alt=\"Extensivo de Fisica para Vestibulares Paulistas\" class=\"wp-image-19816\" srcset=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2023\/02\/EXTENSIVO-BLOG-1-1024x488.png 1024w, https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2023\/02\/EXTENSIVO-BLOG-1-300x143.png 300w, https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2023\/02\/EXTENSIVO-BLOG-1-768x366.png 768w, https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2023\/02\/EXTENSIVO-BLOG-1-670x319.png 670w, https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2023\/02\/EXTENSIVO-BLOG-1-1060x505.png 1060w, https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2023\/02\/EXTENSIVO-BLOG-1.png 1280w\" sizes=\"(max-width: 1024px) 100vw, 1024px\" \/><\/a><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Me acompanhe nas redes sociais: curta a minha&nbsp;<a href=\"https:\/\/www.facebook.com\/professorpinguim\/\"><strong>p\u00e1gina no Facebook<\/strong><\/a><strong>,<\/strong>&nbsp;me&nbsp;siga no&nbsp;<a href=\"https:\/\/www.instagram.com\/professorpinguim\/\"><strong>Instagram<\/strong><\/a><strong>,<\/strong>&nbsp;se inscreva no&nbsp;<a href=\"https:\/\/www.youtube.com\/c\/PinguimV%C3%ADdeoF%C3%ADsica\/?sub_confirmation=1\"><strong>Youtube<\/strong><\/a>&nbsp;e participe do meu canal oficial no&nbsp;<a href=\"https:\/\/professorpinguim.com.br\/telegram\"><strong>Telegram<\/strong><\/a>.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Nesta aula vamos resolver exerc\u00edcios sobre Movimento Uniformemente Variado (MUV). Antes, por\u00e9m, vamos relembrar algumas coisas desta disciplina.<\/p>\n","protected":false},"author":1,"featured_media":7951,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[420,355],"tags":[363,211,773,641,772,700],"class_list":["post-7949","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-cinematica","category-mecanica","tag-cinematica","tag-exercicios","tag-exercicios-muv","tag-mecanica","tag-movimento-uniformemente-variado","tag-muv"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v20.12 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>5 Quest\u00f5es resolvidas sobre Movimento Uniformemente Variado (MUV) - Professor Pinguim | F\u00edsica<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/professorpinguim.com.br\/blog\/5-questoes-resolvidas-sobre-movimento-uniformemente-variado-muv\/\" \/>\n<meta property=\"og:locale\" content=\"pt_BR\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"5 Quest\u00f5es resolvidas sobre Movimento Uniformemente Variado (MUV) - Professor Pinguim | F\u00edsica\" \/>\n<meta property=\"og:description\" content=\"Nesta aula vamos resolver exerc\u00edcios sobre Movimento Uniformemente Variado (MUV). 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