{"id":7151,"date":"2022-01-31T09:00:00","date_gmt":"2022-01-31T12:00:00","guid":{"rendered":"https:\/\/professorpinguim.com.br\/blog\/?p=7151"},"modified":"2023-08-06T21:01:41","modified_gmt":"2023-08-07T00:01:41","slug":"aceleracao-escalar-exercicios-com-resolucao","status":"publish","type":"post","link":"https:\/\/professorpinguim.com.br\/blog\/aceleracao-escalar-exercicios-com-resolucao\/","title":{"rendered":"Acelera\u00e7\u00e3o Escalar: Exerc\u00edcios com resolu\u00e7\u00e3o"},"content":{"rendered":"\n<p class=\"wp-block-paragraph\">Ol\u00e1, pessoal! Neste post, vamos resolver alguns exerc\u00edcios sobre acelera\u00e7\u00e3o escalar. Para refrescar a mem\u00f3ria, vamos antes revisar alguns conceitos importantes sobre essa disciplina.<\/p>\n\n\n\n<!--more-->\n\n\n\n<h2 class=\"wp-block-heading\">Conceito: Acelera\u00e7\u00e3o escalar m\u00e9dia<\/h2>\n\n\n\n<p class=\"wp-block-paragraph\">A acelera\u00e7\u00e3o escalar m\u00e9dia \u00e9 uma grandeza que indica a varia\u00e7\u00e3o de velocidade em um intervalo de tempo. Ela \u00e9 calculada pela f\u00f3rmula:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><img decoding=\"async\" width=\"150\" height=\"76\" class=\"wp-image-7353\" style=\"width: 150px;\" src=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2022\/01\/Captura-de-Tela-2022-02-02-a\u0300s-19.22.53.png\" alt=\"\"><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Lembrando que \u0394 indica a varia\u00e7\u00e3o, ent\u00e3o podemos, sempre que necess\u00e1rio, fazer uma pequena substitui\u00e7\u00e3o na f\u00f3rmula:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><img decoding=\"async\" width=\"220\" height=\"104\" class=\"wp-image-7357\" style=\"width: 220px;\" src=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2022\/01\/Captura-de-Tela-2022-02-02-a\u0300s-19.23.37.png\" alt=\"\" srcset=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2022\/01\/Captura-de-Tela-2022-02-02-a\u0300s-19.23.37.png 306w, https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2022\/01\/Captura-de-Tela-2022-02-02-a\u0300s-19.23.37-300x141.png 300w\" sizes=\"(max-width: 220px) 100vw, 220px\" \/><\/p>\n\n\n\n<hr class=\"wp-block-separator\"\/>\n\n\n\n<h2 class=\"wp-block-heading\">Exerc\u00edcios sobre Acelera\u00e7\u00e3o Escalar<\/h2>\n\n\n\n<h3 class=\"wp-block-heading\">Quest\u00e3o 1<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>(UTFPR) Um determinado ve\u00edculo parte do repouso e aumenta sua velocidade at\u00e9 20,0 m\/s em 6,0 s.<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Depois disso, mant\u00e9m os mesmos 20,0 m\/s por mais 4,0 s. \u00c9 correto afirmar que o m\u00f3dulo da acelera\u00e7\u00e3o m\u00e9dia desse ve\u00edculo entre 0 e 10,0 s em m\/s\u00b2 \u00e9 igual a:<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">a) 2,0<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">b) 5,0<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">c) 2,5<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">d) 4,0<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">e) 3,3<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>RESOLU\u00c7\u00c3O:<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Vimos que:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><img decoding=\"async\" width=\"150\" height=\"84\" class=\"wp-image-7361\" style=\"width: 150px;\" src=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2022\/01\/Captura-de-Tela-2022-02-02-a\u0300s-19.25.42.png\" alt=\"\"><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Veja que a velocidade saiu de 0, foi a 20 e manteve-se em 20 m\/s. Como queremos encontrar a varia\u00e7\u00e3o de velocidade, queremos a varia\u00e7\u00e3o entre o final e o in\u00edcio. Ent\u00e3o, fica f\u00e1cil:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"> <img loading=\"lazy\" decoding=\"async\" width=\"210\" height=\"195\" class=\"wp-image-7363\" style=\"width: 210px;\" src=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2022\/01\/Captura-de-Tela-2022-02-02-a\u0300s-19.29.55.png\" alt=\"\" srcset=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2022\/01\/Captura-de-Tela-2022-02-02-a\u0300s-19.29.55.png 330w, https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2022\/01\/Captura-de-Tela-2022-02-02-a\u0300s-19.29.55-300x278.png 300w\" sizes=\"(max-width: 210px) 100vw, 210px\" \/><\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>RESPOSTA: A<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Quest\u00e3o 2<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>(IFSP) O jamaicano Usain Bolt, durante as Olimp\u00edadas de 2012 em Londres, bateu o recorde ol\u00edmpico da prova dos 100 metros rasos atingindo a marca dos 9,63 segundos. Durante a fase de acelera\u00e7\u00e3o, ele conseguiu atingir, aproximadamente, a m\u00e1xima velocidade de 44,28 km\/h (12,3 m\/s) durante os 6 primeiros segundos. A seguir, o gr\u00e1fico da velocidade pelo tempo registra esse feito.<\/strong><\/p>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/lh5.googleusercontent.com\/2SY39hnTwXVpL_-Kt-P5SXNsUYsz8fFes1UocgoliWiRD_UNML-PA7aOKZDUXs6HIZD3OGjPCs3SSfNGQT-ua7tZWSkvN6dUoE1No16D8xXA7T6cdnICPN8fiwEKW0618_LOca3b\" alt=\"\" width=\"455\" height=\"224\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>De acordo com o gr\u00e1fico, pode-se afirmar que a acelera\u00e7\u00e3o m\u00e9dia de Usain Bolt, durante os primeiros 6 segundos, foi, em m\/s\u00b2, de:<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">a) 2,05.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">b) 2,50.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">c) 3,05.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">d) 4,50.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">e) 5,10<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>RESOLU\u00c7\u00c3O:<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Novamente, temos que recorrer \u00e0 nossa f\u00f3rmula:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"> <img loading=\"lazy\" decoding=\"async\" width=\"150\" height=\"163\" class=\"wp-image-7364\" style=\"width: 150px;\" src=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2022\/01\/Captura-de-Tela-2022-02-02-a\u0300s-19.31.09.png\" alt=\"\"><\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>RESPOSTA: A<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Quest\u00e3o 3<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Um motorista trafega numa rodovia reta com velocidade 162 km\/h. Supondo que os freios do carro possam imprimir uma acelera\u00e7\u00e3o m\u00e1xima de retardamento de m\u00f3dulo igual a 5 m\/s\u00b2, determine o intervalo de tempo m\u00ednimo no qual o motorista pode parar o carro.<\/strong> <img loading=\"lazy\" decoding=\"async\" width=\"130\" height=\"78\" class=\"wp-image-7365\" style=\"width: 130px;\" src=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2022\/01\/Captura-de-Tela-2022-02-02-a\u0300s-19.32.38.png\" alt=\"\"><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Cuidado: como a velocidade inicial \u00e9 positiva, a acelera\u00e7\u00e3o tem que ser negativa. Repare tamb\u00e9m que a velocidade dada pelo enunciado est\u00e1 em km\/h, ou seja, \u00e9 preciso transform\u00e1-la em m\/s (dividir por 3,6): Ent\u00e3o:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><img loading=\"lazy\" decoding=\"async\" width=\"120\" height=\"105\" class=\"wp-image-7366\" style=\"width: 120px;\" src=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2022\/01\/Captura-de-Tela-2022-02-02-a\u0300s-19.33.26.png\" alt=\"\"><\/p>\n\n\n\n<hr class=\"wp-block-separator\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Quest\u00e3o 4<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>(UCS) Um corpo descreve um movimento retil\u00edneo com velocidade variando conforme o gr\u00e1fico a seguir:<\/strong><\/p>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/lh4.googleusercontent.com\/I1fJn4EIXaowoV3ggJPSx5ZfJmZPSDwrhfdgYznrR8uHgz-l7akfAtkI9-6AyUqEwoO-UPaHFxbrppFjRJuUi6vG-5BtC_nHLzn2KChJfauosyKeTAGysaOh95iJPoj1HM_gzBNB\" alt=\"\" width=\"406\" height=\"214\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>a) Calcule a acelera\u00e7\u00e3o escalar m\u00e9dia entre os instantes t = 10 s e t = 14 s.<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Repare no gr\u00e1fico que, no instante t = 10 s, a velocidade do corpo era -20 m\/s. J\u00e1 no instante t = 14 s, sua velocidade era nula. Ent\u00e3o:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><img loading=\"lazy\" decoding=\"async\" width=\"150\" height=\"172\" class=\"wp-image-7367\" style=\"width: 150px;\" src=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2022\/01\/Captura-de-Tela-2022-02-02-a\u0300s-19.34.25.png\" alt=\"\"><\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>b) Classifique o movimento nesse intervalo de tempo.<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Cuidado aqui: no intervalo pedido, veja que a velocidade era negativa e est\u00e1 indo em dire\u00e7\u00e3o a 0. Quando isso acontece, significa que o corpo est\u00e1 parando.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Como temos velocidades negativas (v &lt; 0), o movimento \u00e9 chamado de retr\u00f3grado, que vai contra a trajet\u00f3ria. Al\u00e9m disso, como a velocidade \u00e9 negativa, mas a acelera\u00e7\u00e3o \u00e9 positiva (a &gt; 0), esse movimento tamb\u00e9m \u00e9 chamado de retardado.<\/p>\n\n\n\n<hr class=\"wp-block-separator\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Quest\u00e3o 5<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>A velocidade de um m\u00f3vel varia com o tempo de acordo com o gr\u00e1fico a seguir.<\/strong><\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/lh5.googleusercontent.com\/d5VLoug7QfWLjL7yK0nsELKwKywEE6kLd9g8Ge6eCGOWySxeLUDDklusxSx5VzWznDvkd0oqGiLvu_YC2TkAr57R6-dCi6glVtHF0B8uL-6z2Qo-2ko7lLZTTGNwTstwUXLodTgN\" alt=\"\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>a) Entre t<\/strong><strong><sub>2<\/sub><\/strong><strong> e t<\/strong><strong><sub>3<\/sub><\/strong><strong>, o movimento \u00e9 progressivo e uniforme?<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">N\u00e3o. Neste intervalo de tempo, o m\u00f3dulo da velocidade \u00e9 constante. Por isso, o movimento \u00e9 uniforme. Mas, cuidado: as velocidades s\u00e3o negativas. E quando v &lt; 0, o movimento \u00e9 retr\u00f3grado e n\u00e3o pode ser chamado de progressivo.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>b) Entre t<\/strong><strong><sub>1<\/sub><\/strong><strong> e t<\/strong><strong><sub>2<\/sub><\/strong><strong>, o corpo est\u00e1 movimentando-se a favor ou contra a trajet\u00f3ria? Est\u00e1 acelerando ou retardando?<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Neste intervalo, a velocidade \u00e9 negativa. Isso significa que o corpo se move contra a trajet\u00f3ria. Repare agora que, em t<sub>1<\/sub>, a velocidade era 0. Se um corpo para, o movimento logo depois \u00e9 sempre acelerado, mesmo que a velocidade seja negativa.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Veja no gr\u00e1fico que a reta est\u00e1 decrescente. Isso significa que a acelera\u00e7\u00e3o \u00e9 negativa. Como a velocidade tamb\u00e9m \u00e9 negativa, o movimento \u00e9 acelerado (para tr\u00e1s).<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>c) Classifique o movimento entre os instante t = 0 e t<\/strong><strong><sub>1<\/sub><\/strong><strong>.<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Como as velocidades no intervalo s\u00e3o positivas, o movimento \u00e9 progressivo (a favor da trajet\u00f3ria). Agora, como a velocidade est\u00e1 indo a 0, significa que o corpo vai parar (a &lt; 0 e v &gt; 0), ou seja, o movimento \u00e9 retardado.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>d) Se t<sub>2<\/sub> = 8 s, qual a acelera\u00e7\u00e3o escalar m\u00e9dia entre t = 0 e t<sub>2<\/sub> = 8 s?<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><img loading=\"lazy\" decoding=\"async\" width=\"150\" height=\"168\" class=\"wp-image-7369\" style=\"width: 150px;\" src=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2022\/01\/Captura-de-Tela-2022-02-02-a\u0300s-19.35.21.png\" alt=\"\"><\/p>\n\n\n\n<hr class=\"wp-block-separator\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Quest\u00e3o 6<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>(UERJ) O c\u00e9rebro humano demora cerca de 0,36 segundos para responder a um est\u00edmulo. Por exemplo, se um motorista decide parar o carro, levar\u00e1 no m\u00ednimo esse tempo da resposta para acionar o freio.&nbsp; Determine a dist\u00e2ncia que um carro a 100km\/h percorre durante o tempo de resposta do motorista e calcule a acelera\u00e7\u00e3o m\u00e9dia imposta ao carro se ele para totalmente em 5 segundos.<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Para calcular a dist\u00e2ncia que o carro vai andar, podemos utilizar a f\u00f3rmula do movimento uniforme:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">\u0394s = v. \u0394t<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Repare, no entanto, que a velocidade no enunciado est\u00e1 em km\/h. N\u00e3o se esque\u00e7a de converter para m\/s (dividir por 3,6). Para facilitar nossas contas, j\u00e1 que vai dar um n\u00famero quebrado, vamos fazer assim:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><img loading=\"lazy\" decoding=\"async\" width=\"180\" height=\"394\" class=\"wp-image-7370\" style=\"width: 180px;\" src=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2022\/01\/Captura-de-Tela-2022-02-02-a\u0300s-19.36.13.png\" alt=\"\" srcset=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2022\/01\/Captura-de-Tela-2022-02-02-a\u0300s-19.36.13.png 354w, https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2022\/01\/Captura-de-Tela-2022-02-02-a\u0300s-19.36.13-137x300.png 137w\" sizes=\"(max-width: 180px) 100vw, 180px\" \/><\/p>\n\n\n\n<hr class=\"wp-block-separator\"\/>\n\n\n\n<p class=\"wp-block-paragraph\">Espero que voc\u00ea tenha entendido um pouco melhor como resolver exerc\u00edcios de acelera\u00e7\u00e3o escalar. <\/p>\n\n\n\n<p class=\"wp-block-paragraph\">E se quiser ajuda para melhorar seu n\u00edvel de F\u00edsica em outras mat\u00e9rias,&nbsp;<a href=\"https:\/\/professorpinguim.com.br\/\"><strong>entre em contato comigo e escolha o curso de F\u00edsica mais adequado para voc\u00ea<\/strong><\/a><strong>!<\/strong><\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><a href=\"https:\/\/conteudo.professorpinguim.com.br\/curso-de-fisica-gratuito\" target=\"_blank\" rel=\"noopener noreferrer\"><img decoding=\"async\" src=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2022\/05\/curso-fisica-professor-pinguim.png\" alt=\"Curso de F\u00edsica Gr\u00e1tis do Professor Pinguim\" class=\"wp-image-11364\"\/><\/a><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>SAIBA MAIS<\/strong><br>\ud83d\udc49&nbsp;<a rel=\"noreferrer noopener\" href=\"https:\/\/professorpinguim.com.br\/blog\/aceleracao-escalar-media\/\" target=\"_blank\"><strong>Acelera\u00e7\u00e3o escalar m\u00e9dia e classifica\u00e7\u00e3o dos movimentos<\/strong><\/a><br>\ud83d\udc49&nbsp;<strong><a rel=\"noreferrer noopener\" href=\"https:\/\/professorpinguim.com.br\/blog\/velocidade-media-exercicios\/\" target=\"_blank\">Exerc\u00edcios sobre velocidade m\u00e9dia<\/a><\/strong><br>\ud83d\udc49<a href=\"https:\/\/professorpinguim.com.br\/blog\/pinguimrevisa-cinematica-sp\/\" target=\"_blank\" rel=\"noreferrer noopener\"><strong>&nbsp;Tudo sobre cinem\u00e1tica<\/strong><\/a> <\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Me acompanhe nas redes sociais: curta a minha&nbsp;<a rel=\"noreferrer noopener\" href=\"https:\/\/www.facebook.com\/professorpinguim\/\" target=\"_blank\"><strong>p\u00e1gina no Facebook<\/strong><\/a><strong>,<\/strong>&nbsp;me&nbsp;siga no&nbsp;<a rel=\"noreferrer noopener\" href=\"https:\/\/www.instagram.com\/professorpinguim\/\" target=\"_blank\"><strong>Instagram<\/strong><\/a><strong>,<\/strong>&nbsp;se inscreva no&nbsp;<a rel=\"noreferrer noopener\" href=\"https:\/\/www.youtube.com\/c\/PinguimV%C3%ADdeoF%C3%ADsica\/?sub_confirmation=1\" target=\"_blank\"><strong>Youtube<\/strong><\/a>&nbsp;e participe do meu canal oficial no&nbsp;<strong><a href=\"https:\/\/professorpinguim.com.br\/telegram\">Telegram<\/a><\/strong>.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Neste post, vamos resolver alguns exerc\u00edcios sobre acelera\u00e7\u00e3o escalar. Para refrescar a mem\u00f3ria, vamos antes revisar alguns conceitos importantes. <\/p>\n","protected":false},"author":1,"featured_media":7155,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[420,744,355],"tags":[753,565,363,641],"class_list":["post-7151","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-cinematica","category-exercicios-resolvidos","category-mecanica","tag-aceleracao-escalar","tag-aceleracao-escalar-media","tag-cinematica","tag-mecanica"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v20.12 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Acelera\u00e7\u00e3o Escalar: Exerc\u00edcios com resolu\u00e7\u00e3o - Professor Pinguim | F\u00edsica<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/professorpinguim.com.br\/blog\/aceleracao-escalar-exercicios-com-resolucao\/\" \/>\n<meta property=\"og:locale\" content=\"pt_BR\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Acelera\u00e7\u00e3o Escalar: Exerc\u00edcios com resolu\u00e7\u00e3o - Professor Pinguim | F\u00edsica\" \/>\n<meta property=\"og:description\" content=\"Neste post, vamos resolver alguns exerc\u00edcios sobre acelera\u00e7\u00e3o escalar. 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