{"id":3431,"date":"2022-02-08T09:00:00","date_gmt":"2022-02-08T12:00:00","guid":{"rendered":"https:\/\/professorpinguim.com.br\/blog\/?p=3431"},"modified":"2023-08-06T21:01:37","modified_gmt":"2023-08-07T00:01:37","slug":"exercicios-resolvidos-de-campo-eletrico","status":"publish","type":"post","link":"https:\/\/professorpinguim.com.br\/blog\/exercicios-resolvidos-de-campo-eletrico\/","title":{"rendered":"Exerc\u00edcios resolvidos de Campo El\u00e9trico"},"content":{"rendered":"\n<p class=\"wp-block-paragraph\">Neste post, vamos resolver juntos alguns exerc\u00edcios sobre campo el\u00e9trico. Ent\u00e3o l\u00e1pis e caderno na m\u00e3o e bons estudos!<\/p>\n\n\n\n<!--more-->\n\n\n\n<h2 class=\"wp-block-heading\">Exerc\u00edcios de Campo El\u00e9trico<\/h2>\n\n\n\n<h3 class=\"wp-block-heading\">Quest\u00e3o 1<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Represente o vetor campo el\u00e9trico E produzido pela carga Q no ponto P de cada item abaixo:<\/strong><\/p>\n\n\n\n<figure class=\"wp-block-image size-large is-resized\"><img fetchpriority=\"high\" decoding=\"async\" src=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2022\/05\/Captura-de-Tela-2022-05-02-a\u0300s-14.54.10.png\" alt=\"\" class=\"wp-image-10315\" width=\"242\" height=\"280\" srcset=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2022\/05\/Captura-de-Tela-2022-05-02-a\u0300s-14.54.10.png 536w, https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2022\/05\/Captura-de-Tela-2022-05-02-a\u0300s-14.54.10-259x300.png 259w\" sizes=\"(max-width: 242px) 100vw, 242px\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>RESOLU\u00c7\u00c3O:<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Como a carga \u00e9 negativa, ela gera campo de aproxima\u00e7\u00e3o:<\/p>\n\n\n\n<figure class=\"wp-block-image size-large is-resized\"><img decoding=\"async\" src=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2022\/05\/Captura-de-Tela-2022-05-02-a\u0300s-14.55.44.png\" alt=\"\" class=\"wp-image-10316\" width=\"479\" height=\"293\" srcset=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2022\/05\/Captura-de-Tela-2022-05-02-a\u0300s-14.55.44.png 864w, https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2022\/05\/Captura-de-Tela-2022-05-02-a\u0300s-14.55.44-300x184.png 300w, https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2022\/05\/Captura-de-Tela-2022-05-02-a\u0300s-14.55.44-768x471.png 768w, https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2022\/05\/Captura-de-Tela-2022-05-02-a\u0300s-14.55.44-670x411.png 670w\" sizes=\"(max-width: 479px) 100vw, 479px\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Repare agora que, em C e D, eu n\u00e3o indiquei a linha tracejada, pois isso induz o aluno a colocar o vetor em cima da linha e resolver a quest\u00e3o rapidamente. Por\u00e9m, quando n\u00e3o h\u00e1 tra\u00e7os, muitos alunos se complicam. Nesse caso, a primeira coisa a ser feita \u00e9 tra\u00e7ar uma linha que passe pelo meio da carga para, em seguida, desenhar o campo el\u00e9trico:<\/p>\n\n\n\n<figure class=\"wp-block-image size-large is-resized\"><img decoding=\"async\" src=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2022\/05\/Captura-de-Tela-2022-05-02-a\u0300s-14.56.39.png\" alt=\"\" class=\"wp-image-10317\" width=\"318\" height=\"235\" srcset=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2022\/05\/Captura-de-Tela-2022-05-02-a\u0300s-14.56.39.png 576w, https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2022\/05\/Captura-de-Tela-2022-05-02-a\u0300s-14.56.39-300x222.png 300w\" sizes=\"(max-width: 318px) 100vw, 318px\" \/><\/figure>\n\n\n\n<h3 class=\"wp-block-heading\">Quest\u00e3o 2<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>(FEI-SP) A intensidade do vetor campo el\u00e9trico num ponto P \u00e9 6.10<\/strong><strong><sup>5 <\/sup><\/strong><strong>N\/C. Uma carga puntiforme q = 3.10<\/strong><strong><sup>-6<\/sup><\/strong><strong> C colocada em P, ficar\u00e1 sujeita a uma for\u00e7a el\u00e9trica cuja intensidade:<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">a) para o c\u00e1lculo, necessita da constante do meio em que a carga se encontra.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">b) para o c\u00e1lculo, necessidade da dist\u00e2ncia.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">c) Vale 2N<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">d) Vale 2&#215;10(<sup>-11)<\/sup>N<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">e) Vale 1,8 N<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>RESOLU\u00c7\u00c3O:<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Vamos lembrar que:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">F<sub>el<\/sub> = |q| . E<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Portanto:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">F<sub>el<\/sub> = 3 . 10<sup>-6<\/sup> . 6 . 10<sup>5<\/sup><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">F<sub>el<\/sub> = 18 . 10<sup>-1<\/sup><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">F<sub>el <\/sub>= 1,8 N<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>RESPOSTA: E<\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Quest\u00e3o 3<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>(Mack-SP) Uma carga el\u00e9trica puntiforme com q = 4,0 \u03bcC, que \u00e9 colocada em um ponto P do v\u00e1cuo, fica sujeita a uma for\u00e7a el\u00e9trica de intensidade 1,2 N. O campo el\u00e9trico nesse ponto P tem intensidade:<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">a) 3,0 . 10<sup>5 <\/sup>N\/C<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">b) 2,4 . 10<sup>5 <\/sup>N\/C<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">c) 1,2 . 10<sup>5<\/sup> N\/C<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">d) 4,0 . 10<sup>-6 <\/sup>N\/C<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">e) 4,8 . 10<sup>-6 <\/sup>N\/C<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>RESOLU\u00c7\u00c3O:<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Veja que o enunciado nos fornece a for\u00e7a e quer saber o campo. Com isso, podemos utilizar:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">E = Fel \/ |q|<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Mas agora repare que a quest\u00e3o nos forneceu a carga colocada no campo. O \u2018q\u2019 n\u00e3o \u00e9 a carga que gerou o campo, mas a carga que recebeu a for\u00e7a do campo. Nesse caso, n\u00e3o precisamos saber quem gerou o campo. Lembre tamb\u00e9m que \u03bc \u00e9 igual a 10<sup>-6<\/sup>.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Assim:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">E = 1,2 \/ 4 . 10<sup>-6<\/sup><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">E = 0,3 . 10<sup>6<\/sup><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">E = 3,0 . 10<sup>-1<\/sup> . 10<sup>6<\/sup><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">E = 3,0 . 10<sup>5 <\/sup>N\/C<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>RESPOSTA: A<\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Quest\u00e3o 4<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Uma part\u00edcula de carga q, com excesso de 5.10<\/strong><strong><sup>13<\/sup><\/strong><strong> el\u00e9trons, encontra-se numa regi\u00e3o do espa\u00e7o onde h\u00e1 um campo el\u00e9trico E = 100 kN\/C, dirigido verticalmente para cima. Considere a carga elementar e = 1,6.10<\/strong><strong><sup>-19<\/sup><\/strong><strong> C. Determine a for\u00e7a el\u00e9trica que surge em q devido \u00e0 sua presen\u00e7a no campo el\u00e9trico.<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>RESOLU\u00c7\u00c3O:<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Em primeiro lugar, lembre-se que k (quilo) vale 10<sup>3<\/sup>. Agora, veja que foi pedida a for\u00e7a, ou seja, a quest\u00e3o quer saber o m\u00f3dulo, a dire\u00e7\u00e3o e o sentido.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Isso posto, temos que calcular a carga. Para isso, utilizamos o n\u00famero de part\u00edculas multiplicado pela carga elementar. Por\u00e9m, como h\u00e1 excesso de el\u00e9trons, a carga \u00e9 negativa, o que nos d\u00e1:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">q = -N . e<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">q = -5 . 10<sup>13<\/sup> . 1,6 . 10<sup>-19<\/sup><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">q = -8 . 10<sup>6<\/sup> C<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Agora, temos que calcular a for\u00e7a. Para isso:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Fel = |q| . E<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Antes de continuar, repare que a carga deve ser em m\u00f3dulo! Portanto:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Fel = 8 . 10<sup>-6<\/sup> . 100 . 10<sup>3<\/sup><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Fel = 8 . 10<sup>-1<\/sup><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Fel = 0,8 N<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Importante notar que, dessa forma, a nossa resposta ainda est\u00e1 incompleta, pois devemos indicar a dire\u00e7\u00e3o e o sentido da for\u00e7a. Ent\u00e3o, vamos lembrar que o campo est\u00e1 dirigido para cima e que a carga \u00e9 negativa. Quando a carga negativa \u00e9 colocada em campo el\u00e9trico para cima, ela recebe uma for\u00e7a el\u00e9trica contra o campo.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Portanto, a resposta completa \u00e9 que a for\u00e7a el\u00e9trica vale 0,8 N, com dire\u00e7\u00e3o vertical e sentido para baixo.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Quest\u00e3o 5<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Uma carga Q<\/strong><strong><sub>A<\/sub><\/strong><strong> = -160 \u03bcC est\u00e1 fixa num ponto A da figura abaixo.<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Dado: k<sub>0<\/sub> = 9.10<sup>9<\/sup> unidade do SI.<\/strong><\/p>\n\n\n\n<figure class=\"wp-block-image size-large is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2022\/05\/Captura-de-Tela-2022-05-02-a\u0300s-14.58.06.png\" alt=\"\" class=\"wp-image-10319\" width=\"364\" height=\"173\" srcset=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2022\/05\/Captura-de-Tela-2022-05-02-a\u0300s-14.58.06.png 600w, https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2022\/05\/Captura-de-Tela-2022-05-02-a\u0300s-14.58.06-300x143.png 300w\" sizes=\"(max-width: 364px) 100vw, 364px\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">a) Determine as intensidades dos vetores campo el\u00e9trico nos pontos P<sub>1<\/sub> e P<sub>2<\/sub>.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">b) Em P<sub>1<\/sub>, coloca-se uma carga de prova q<sub>1<\/sub> = -200 \u03bcC. Em P<sub>2<\/sub>, coloca-se uma carga de prova q<sub>2<\/sub> = +100 nC. Determine as intensidade e as orienta\u00e7\u00f5es das for\u00e7as el\u00e9tricas que o campo el\u00e9trico Q<sub>A<\/sub> provoca em q<sub>1<\/sub> e q<sub>2<\/sub>.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>RESOLU\u00c7\u00c3O:<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">a) E = k . |Q| \/ d<sup>2<\/sup><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Tome cuidado, porque o dado fornecido pela quest\u00e3o est\u00e1 no Sistema Internacional e o gr\u00e1fico est\u00e1 em cent\u00edmetro. Ent\u00e3o, temos que converter para metros. Para isso:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">d = 40 cm = 40 . 10<sup>-2 <\/sup>m<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">d = 4 . 10<sup>-1<\/sup> m<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">E j\u00e1 podemos passar para o quadrado, pois a f\u00f3rmula utiliza d<sup>2:<\/sup><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">d<sup>2<\/sup> = 16 . 10<sup>-2<\/sup> m<sup>2<\/sup><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Seguimos:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">E<sub>1<\/sub> = 9 . 10<sup>9<\/sup> . 160 . 10<sup>-6<\/sup> \/ 16 . 10<sup>-2<\/sup><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">E<sub>1<\/sub> = 90 . 10<sup>5<\/sup> N\/C<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">E<sub>1<\/sub> = 9 . 10<sup>6<\/sup> N\/C<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">J\u00e1 para calcular o campo 2, podemos usar a f\u00f3rmula de novo ou aplicar a propor\u00e7\u00e3o. Repare no gr\u00e1fico que a dist\u00e2ncia passou de 40 para 20 cm. Quando a dist\u00e2ncia \u00e9 dividida pela metade, de acordo com nossa f\u00f3rmula, o campo el\u00e9trico fica 4 vezes maior.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Ent\u00e3o:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">E<sub>2<\/sub> = 36 . 10<sup>6 <\/sup>N\/C<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">b) Veja o mC, isso significa &#8216;mili&#8217;, que vale 10<sup>-3<\/sup>. Depois, ele nos informa o nC, que \u00e9 &#8216;nano&#8217;, que vale 10<sup>-9<\/sup>.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Vamos calcular a for\u00e7a 1:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">F<sub>1<\/sub> = |q<sub>1<\/sub>| . E<sub>1<\/sub><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">F<sub>1<\/sub> = 200 . 10<sup>-3<\/sup> . 9 . 10<sup>6<\/sup><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">F<sub>1<\/sub> = 1800 . 10<sup>3<\/sup><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">F<sub>1<\/sub> = 1,8 . 10<sup>6<\/sup> N<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Agora precisamos determinar a orienta\u00e7\u00e3o da for\u00e7a. Veja o gr\u00e1fico: quando colocamos uma carga negativa em um local que tinha um campo el\u00e9trico para a esquerda, a for\u00e7a fica para a direita. Portanto, o vetor da for\u00e7a F<sub>1<\/sub> ser\u00e1 para a direita.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Agora, o c\u00e1lculo da for\u00e7a 2:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">F<sub>2<\/sub> = |q<sub>2<\/sub>| . E<sub>2<\/sub><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">F<sub>2<\/sub> = 100 . 10<sup>-9<\/sup> . 36 . 10<sup>6<\/sup><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">F<sub>2<\/sub> = 3600 . 10<sup>-3<\/sup><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">F<sub>2<\/sub> = 3,6 N<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Agora a orienta\u00e7\u00e3o: o campo gerado pela carga negativa no P<sub>2<\/sub> \u00e9 um campo de aproxima\u00e7\u00e3o. Como foi colocada uma carga positiva (q<sub>2<\/sub>), a for\u00e7a aparece a favor do campo, ou seja, ela \u00e9 orientada para baixo.<\/p>\n\n\n\n<hr class=\"wp-block-separator is-style-wide\"\/>\n\n\n\n<p class=\"wp-block-paragraph\">Espero que voc\u00ea tenha entendido um pouco melhor <strong>como resolver exerc\u00edcios b\u00e1sicos de campo el\u00e9trico<\/strong>. Para conferir a resolu\u00e7\u00e3o dessas e de muitas outras quest\u00f5es sobre essa mat\u00e9ria, assista minha videoaula:<\/p>\n\n\n\n<figure class=\"wp-block-embed-youtube wp-block-embed is-type-video is-provider-youtube wp-embed-aspect-16-9 wp-has-aspect-ratio\"><div class=\"wp-block-embed__wrapper\">\n<iframe title=\"Campo El\u00e9trico Exerc\u00edcios - Lista N\u00edvel 1 Professor Pinguim\" width=\"800\" height=\"450\" src=\"https:\/\/www.youtube.com\/embed\/FbmKGMxZGOQ?feature=oembed\" frameborder=\"0\" allow=\"accelerometer; autoplay; clipboard-write; encrypted-media; gyroscope; picture-in-picture; web-share\" referrerpolicy=\"strict-origin-when-cross-origin\" allowfullscreen><\/iframe>\n<\/div><\/figure>\n\n\n\n<hr class=\"wp-block-separator is-style-wide\"\/>\n\n\n\n<p class=\"wp-block-paragraph\">E se quiser ajuda para melhorar seu n\u00edvel de F\u00edsica em outras mat\u00e9rias,&nbsp;<strong><a href=\"https:\/\/professorpinguim.com.br\/\">entre em contato comigo e escolha o curso de F\u00edsica mais adequado para voc\u00ea<\/a>!<\/strong><\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><a href=\"https:\/\/conteudo.professorpinguim.com.br\/curso-de-fisica-gratuito\" target=\"_blank\" rel=\"noreferrer noopener\"><img decoding=\"async\" src=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2022\/05\/curso-fisica-professor-pinguim.png\" alt=\"Curso de F\u00edsica Gr\u00e1tis do Professor Pinguim\" class=\"wp-image-11364\"\/><\/a><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>SAIBA MAIS<\/strong><br>\u2705&nbsp;<a rel=\"noreferrer noopener\" href=\"https:\/\/professorpinguim.com.br\/blog\/pinguimrevisa-cinematica-enem\/\" target=\"_blank\"><strong>Quest\u00f5es de Cinem\u00e1tica resolvidas em v\u00eddeo<\/strong><\/a><br><a rel=\"noreferrer noopener\" href=\"https:\/\/professorpinguim.com.br\/blog\/pinguimrevisa-cinematica-enem\/\" target=\"_blank\">\u2705<\/a>&nbsp;<a rel=\"noreferrer noopener\" href=\"https:\/\/professorpinguim.com.br\/blog\/conceitos-basicos-de-cinematica-equacao-dos-espacos-em-funcao-do-tempo\/\" target=\"_blank\"><strong>Conceitos b\u00e1sicos de Cinem\u00e1tica: Equa\u00e7\u00e3o do espa\u00e7o em fun\u00e7\u00e3o do tempo<\/strong><\/a><br>\u2705&nbsp;<a rel=\"noreferrer noopener\" href=\"https:\/\/professorpinguim.com.br\/blog\/pinguimrevisa-cinematica-sp\/\" target=\"_blank\"><strong>Tudo sobre Cinem\u00e1tica: Revis\u00e3o das principais quest\u00f5es dos vestibulares Paulista<\/strong><\/a><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Me acompanhe nas redes sociais: curta a minha&nbsp;<a href=\"https:\/\/www.facebook.com\/professorpinguim\/\"><strong>p\u00e1gina no Facebook<\/strong><\/a><strong>,<\/strong>&nbsp;me&nbsp;siga no&nbsp;<a href=\"https:\/\/www.instagram.com\/professorpinguim\/\"><strong>Instagram<\/strong><\/a><strong>,<\/strong>&nbsp;se inscreva no&nbsp;<a href=\"https:\/\/www.youtube.com\/c\/PinguimV%C3%ADdeoF%C3%ADsica\/?sub_confirmation=1\"><strong>Youtube<\/strong><\/a>&nbsp;e participe do meu canal oficial no&nbsp;<strong><a href=\"http:\/\/professorpinguim.com.br\/telegram\">Telegram<\/a><\/strong>.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Vamos resolver juntos alguns exerc\u00edcios de n\u00edvel b\u00e1sico sobre campo el\u00e9trico. Ent\u00e3o l\u00e1pis e caderno na m\u00e3o e bons estudos!<\/p>\n","protected":false},"author":1,"featured_media":3432,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[746,729,744],"tags":[669,388,762,670],"class_list":["post-3431","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-eletricidade","category-eletrostatica","category-exercicios-resolvidos","tag-campo-eletrico","tag-eletricidade","tag-eletrostatica","tag-exercicios-campo-eletrico"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v20.12 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Exerc\u00edcios resolvidos de Campo El\u00e9trico - Professor Pinguim | F\u00edsica<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/professorpinguim.com.br\/blog\/exercicios-resolvidos-de-campo-eletrico\/\" \/>\n<meta property=\"og:locale\" content=\"pt_BR\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Exerc\u00edcios resolvidos de Campo El\u00e9trico - Professor Pinguim | F\u00edsica\" \/>\n<meta property=\"og:description\" content=\"Vamos resolver juntos alguns exerc\u00edcios de n\u00edvel b\u00e1sico sobre campo el\u00e9trico. Ent\u00e3o l\u00e1pis e caderno na m\u00e3o e bons estudos!\" \/>\n<meta property=\"og:url\" content=\"https:\/\/professorpinguim.com.br\/blog\/exercicios-resolvidos-de-campo-eletrico\/\" \/>\n<meta property=\"og:site_name\" content=\"Professor Pinguim | F\u00edsica\" \/>\n<meta property=\"article:publisher\" content=\"https:\/\/www.facebook.com\/Betminds.Digital\/\" \/>\n<meta property=\"article:published_time\" content=\"2022-02-08T12:00:00+00:00\" \/>\n<meta property=\"article:modified_time\" content=\"2023-08-07T00:01:37+00:00\" \/>\n<meta property=\"og:image\" content=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2021\/07\/campo-eletrico-exercicios-resolvidos.jpg\" \/>\n\t<meta property=\"og:image:width\" content=\"1280\" \/>\n\t<meta property=\"og:image:height\" content=\"720\" \/>\n\t<meta property=\"og:image:type\" content=\"image\/jpeg\" \/>\n<meta name=\"author\" content=\"Professor Pinguim\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Escrito por\" \/>\n\t<meta name=\"twitter:data1\" content=\"Professor Pinguim\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. tempo de leitura\" \/>\n\t<meta name=\"twitter:data2\" content=\"6 minutos\" \/>\n<script type=\"application\/ld+json\" class=\"yoast-schema-graph\">{\"@context\":\"https:\/\/schema.org\",\"@graph\":[{\"@type\":\"WebPage\",\"@id\":\"https:\/\/professorpinguim.com.br\/blog\/exercicios-resolvidos-de-campo-eletrico\/\",\"url\":\"https:\/\/professorpinguim.com.br\/blog\/exercicios-resolvidos-de-campo-eletrico\/\",\"name\":\"Exerc\u00edcios resolvidos de Campo El\u00e9trico - Professor Pinguim | F\u00edsica\",\"isPartOf\":{\"@id\":\"https:\/\/professorpinguim.com.br\/blog\/#website\"},\"datePublished\":\"2022-02-08T12:00:00+00:00\",\"dateModified\":\"2023-08-07T00:01:37+00:00\",\"author\":{\"@id\":\"https:\/\/professorpinguim.com.br\/blog\/#\/schema\/person\/dcbdcdaaf74b619f8b699c2454e5d536\"},\"breadcrumb\":{\"@id\":\"https:\/\/professorpinguim.com.br\/blog\/exercicios-resolvidos-de-campo-eletrico\/#breadcrumb\"},\"inLanguage\":\"pt-BR\",\"potentialAction\":[{\"@type\":\"ReadAction\",\"target\":[\"https:\/\/professorpinguim.com.br\/blog\/exercicios-resolvidos-de-campo-eletrico\/\"]}]},{\"@type\":\"BreadcrumbList\",\"@id\":\"https:\/\/professorpinguim.com.br\/blog\/exercicios-resolvidos-de-campo-eletrico\/#breadcrumb\",\"itemListElement\":[{\"@type\":\"ListItem\",\"position\":1,\"name\":\"In\u00edcio\",\"item\":\"https:\/\/professorpinguim.com.br\/blog\/\"},{\"@type\":\"ListItem\",\"position\":2,\"name\":\"Exerc\u00edcios resolvidos de Campo El\u00e9trico\"}]},{\"@type\":\"WebSite\",\"@id\":\"https:\/\/professorpinguim.com.br\/blog\/#website\",\"url\":\"https:\/\/professorpinguim.com.br\/blog\/\",\"name\":\"Professor Pinguim | F\u00edsica\",\"description\":\"F\u00edsica para Vestibular Paulista, ENEM e Ensino M\u00e9dio\",\"potentialAction\":[{\"@type\":\"SearchAction\",\"target\":{\"@type\":\"EntryPoint\",\"urlTemplate\":\"https:\/\/professorpinguim.com.br\/blog\/?s={search_term_string}\"},\"query-input\":\"required name=search_term_string\"}],\"inLanguage\":\"pt-BR\"},{\"@type\":\"Person\",\"@id\":\"https:\/\/professorpinguim.com.br\/blog\/#\/schema\/person\/dcbdcdaaf74b619f8b699c2454e5d536\",\"name\":\"Professor Pinguim\",\"image\":{\"@type\":\"ImageObject\",\"inLanguage\":\"pt-BR\",\"@id\":\"https:\/\/professorpinguim.com.br\/blog\/#\/schema\/person\/image\/\",\"url\":\"https:\/\/secure.gravatar.com\/avatar\/ffd75b6cb46865dcea0fd25e6b0348a12def6ae98b940d19c65c9a512d1f0cf6?s=96&r=g\",\"contentUrl\":\"https:\/\/secure.gravatar.com\/avatar\/ffd75b6cb46865dcea0fd25e6b0348a12def6ae98b940d19c65c9a512d1f0cf6?s=96&r=g\",\"caption\":\"Professor Pinguim\"},\"description\":\"A plataforma do Professor Pinguim \u00e9 dedicada ao ensino da F\u00edsica e vai te ensinar com uma metodologia completa essa incr\u00edvel mat\u00e9ria.\",\"sameAs\":[\"https:\/\/professorpinguim.com.br\/\"],\"url\":\"https:\/\/professorpinguim.com.br\/blog\/author\/admin\/\"}]}<\/script>\n<!-- \/ Yoast SEO plugin. -->","yoast_head_json":{"title":"Exerc\u00edcios resolvidos de Campo El\u00e9trico - Professor Pinguim | F\u00edsica","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/professorpinguim.com.br\/blog\/exercicios-resolvidos-de-campo-eletrico\/","og_locale":"pt_BR","og_type":"article","og_title":"Exerc\u00edcios resolvidos de Campo El\u00e9trico - Professor Pinguim | F\u00edsica","og_description":"Vamos resolver juntos alguns exerc\u00edcios de n\u00edvel b\u00e1sico sobre campo el\u00e9trico. 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