{"id":30572,"date":"2024-08-14T17:17:46","date_gmt":"2024-08-14T20:17:46","guid":{"rendered":"https:\/\/professorpinguim.com.br\/blog\/?p=30572"},"modified":"2024-08-14T17:17:47","modified_gmt":"2024-08-14T20:17:47","slug":"resolucao-famema-2024","status":"publish","type":"post","link":"https:\/\/professorpinguim.com.br\/blog\/resolucao-famema-2024\/","title":{"rendered":"Resolu\u00e7\u00e3o FAMEMA 2024"},"content":{"rendered":"\n<figure class=\"wp-block-embed is-type-video is-provider-youtube wp-block-embed-youtube wp-embed-aspect-16-9 wp-has-aspect-ratio\"><div class=\"wp-block-embed__wrapper\">\n<iframe title=\"Resolu\u00e7\u00e3o FAMEMA 2024 VUNESP - Gabarito de F\u00edsica \ud83d\udc27  Professor Pinguim\" width=\"800\" height=\"450\" src=\"https:\/\/www.youtube.com\/embed\/8CeGf1U8Gag?feature=oembed\" frameborder=\"0\" allow=\"accelerometer; autoplay; clipboard-write; encrypted-media; gyroscope; picture-in-picture; web-share\" referrerpolicy=\"strict-origin-when-cross-origin\" allowfullscreen><\/iframe>\n<\/div><figcaption class=\"wp-element-caption\">Resolu\u00e7\u00e3o completa no canal Youtube do professor<\/figcaption><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>QUEST\u00c3O 36&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; <\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Uma sequ\u00eancia engra\u00e7ada que j\u00e1 foi muitas vezes explora- da em com\u00e9dias e desenhos animados tem como cen\u00e1rio as estruturas em a\u00e7o de edif\u00edcios. Nessa sequ\u00eancia, um perso- nagem, son\u00e2mbulo, caminha sobre uma viga da estrutura de um pr\u00e9dio. Quando o personagem est\u00e1 prestes a cair, uma outra viga, que est\u00e1 sendo erguida por um guindaste, nivela&#8211;se com a primeira, possibilitando que o pr\u00f3ximo passo n\u00e3o seja no vazio. O personagem passa, ent\u00e3o, a caminhar sobre essa viga que est\u00e1 subindo e, novamente, quando tudo pa- rece que vai dar errado, a viga em ascens\u00e3o nivela-se com a outra viga do pr\u00f3ximo andar, garantindo a continuidade da caminhada.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full is-resized\"><img fetchpriority=\"high\" decoding=\"async\" width=\"743\" height=\"464\" src=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2024\/08\/image-7.png\" alt=\"\" class=\"wp-image-30582\" style=\"width:514px;height:auto\" srcset=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2024\/08\/image-7.png 743w, https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2024\/08\/image-7-300x187.png 300w, https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2024\/08\/image-7-600x375.png 600w, https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2024\/08\/image-7-670x418.png 670w\" sizes=\"(max-width: 743px) 100vw, 743px\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Admita que a viga em ascens\u00e3o me\u00e7a 30 m de comprimen- to, se mantenha sempre na horizontal e realize movimento uniforme; que a velocidade do son\u00e2mbulo seja constante e de valor igual a 0,5 m\/s; que a altura entre as vigas de um andar e do pr\u00f3ximo seja de 3 m. Considerando a sequ\u00eancia de acontecimentos descritos, a velocidade com que a viga em ascens\u00e3o se movimenta \u00e9 de<\/p>\n\n\n\n<figure class=\"wp-block-image size-full is-resized\"><img decoding=\"async\" width=\"179\" height=\"259\" src=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2024\/08\/image-8.png\" alt=\"\" class=\"wp-image-30583\" style=\"width:120px;height:auto\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>QUEST\u00c3O 37&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; <\/strong><strong><\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Um corpo dotado de rodinhas ideais, inicialmente em repouso, e apoiado sobre uma superf\u00edcie plana, horizontal e livre de atritos, passa a receber a a\u00e7\u00e3o de uma for\u00e7a resultante horizon- tal, de dire\u00e7\u00e3o, sentido e intensidade constantes. O esbo\u00e7o do gr\u00e1fico que corresponde \u00e0 varia\u00e7\u00e3o da energia cin\u00e9tica desse corpo em fun\u00e7\u00e3o do tempo \u00e9:<\/p>\n\n\n\n<figure class=\"wp-block-image size-large is-resized\"><img decoding=\"async\" width=\"346\" height=\"1024\" src=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2024\/08\/image-9-346x1024.png\" alt=\"\" class=\"wp-image-30584\" style=\"width:323px;height:auto\" srcset=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2024\/08\/image-9-346x1024.png 346w, https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2024\/08\/image-9-101x300.png 101w, https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2024\/08\/image-9.png 457w\" sizes=\"(max-width: 346px) 100vw, 346px\" \/><\/figure>\n\n\n<p><strong>QUEST\u00c3O 38\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/strong><\/p>\n<p>No painel dos carros a combust\u00e3o interna, uma l\u00e2mpada de advert\u00eancia se acende quando a temperatura do l\u00edquido de arrefecimento do motor chega a 115 \u00baC. Esse l\u00edquido \u00e9 uma mistura que tem calor espec\u00edfico igual a 0,6 cal\/(g \u00b4 \u00baC) e sua densidade pode ser igualada \u00e0 da \u00e1gua, que \u00e9 de 1 000 g\/L. Considere um ve\u00edculo que usa 10 L de l\u00edquido de arrefeci- mento para manter a temperatura do motor controlada. Em uma eventual falha no processo de resfriamento desse l\u00edqui- do, a menor quantidade de calor acumulada para que, a partir da temperatura de 15 \u00baC, a luz de advert\u00eancia se acenda \u00e9 de<\/p>\n<p>a) 750<\/p>\n<p>b) 1 200<\/p>\n<p>c) 600<\/p>\n<p>d) 1 500<\/p>\n<p>e) 300<\/p>\n<p><strong>QUEST\u00c3O 39\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/strong><\/p>\n<p>O \u00edndice de refra\u00e7\u00e3o relativo nA,B entre dois meios, A e B, \u00e9 0,5. Sabendo que o \u00edndice de refra\u00e7\u00e3o absoluto do meio A vale 2, o \u00edndice absoluto do meio B tem valor igual a<\/p>\n<p>a) 5<\/p>\n<p>b) 2<\/p>\n<p>c) 1<\/p>\n<p>d) 10<\/p>\n<p>e) 4<\/p>\n<p><strong>QUEST\u00c3O 40\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/strong><\/p>\n<p>Um aquecedor el\u00e9trico \u00e9 constru\u00eddo com 4 resistores \u00f4hmi- cos de mesmo valor de resist\u00eancia el\u00e9trica cada um. Os fios de liga\u00e7\u00e3o e o gerador s\u00e3o ideais. A pot\u00eancia el\u00e9trica total ori- ginal tem valor Pot e o circuito el\u00e9trico \u00e9 o indicado na figura.<\/p>\n\n\n<figure class=\"wp-block-image size-full is-resized\"><img loading=\"lazy\" decoding=\"async\" width=\"488\" height=\"339\" src=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2024\/08\/image-2.png\" alt=\"\" class=\"wp-image-30577\" style=\"width:324px;height:auto\" srcset=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2024\/08\/image-2.png 488w, https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2024\/08\/image-2-300x208.png 300w\" sizes=\"(max-width: 488px) 100vw, 488px\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\"><img loading=\"lazy\" decoding=\"async\" width=\"7\" height=\"9\" src=\"file:\/\/\/C:\/Users\/Windows\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image002.gif\"><img loading=\"lazy\" decoding=\"async\" width=\"7\" height=\"9\" src=\"file:\/\/\/C:\/Users\/Windows\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image003.gif\">Um peda\u00e7o de fio, ideal, \u00e9 soldado ao circuito, nos pontos indi- cados pelos n\u00fameros 2 e 3. Promovida essa altera\u00e7\u00e3o, a nova pot\u00eancia el\u00e9trica total dissipada pelo aquecedor passa a ser<\/p>\n\n\n\n<figure class=\"wp-block-image size-full is-resized\"><img loading=\"lazy\" decoding=\"async\" width=\"169\" height=\"478\" src=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2024\/08\/image-3.png\" alt=\"\" class=\"wp-image-30578\" style=\"width:87px;height:auto\" srcset=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2024\/08\/image-3.png 169w, https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2024\/08\/image-3-106x300.png 106w\" sizes=\"(max-width: 169px) 100vw, 169px\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\"><\/p>\n","protected":false},"excerpt":{"rendered":"<p>QUEST\u00c3O 36&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; Uma sequ\u00eancia engra\u00e7ada que j\u00e1 foi muitas vezes explora- da em com\u00e9dias e desenhos animados tem como cen\u00e1rio as estruturas em a\u00e7o de edif\u00edcios. Nessa sequ\u00eancia, um perso- nagem, son\u00e2mbulo, caminha sobre uma viga da estrutura de um pr\u00e9dio. Quando o personagem est\u00e1 prestes a cair, uma outra viga, que est\u00e1 sendo erguida [&hellip;]<\/p>\n","protected":false},"author":101017,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[956],"tags":[],"class_list":["post-30572","post","type-post","status-publish","format-standard","hentry","category-geral"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v20.12 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Resolu\u00e7\u00e3o FAMEMA 2024 - Professor Pinguim | F\u00edsica<\/title>\n<meta name=\"description\" content=\"Resolu\u00e7\u00e3o da prova de F\u00edsica da FAMEMA (Medicina Mar\u00edlia) de 2024, elaborada pela Vunesp.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/professorpinguim.com.br\/blog\/resolucao-famema-2024\/\" \/>\n<meta property=\"og:locale\" content=\"pt_BR\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Resolu\u00e7\u00e3o FAMEMA 2024 - 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