{"id":2345,"date":"2020-12-04T21:00:00","date_gmt":"2020-12-05T00:00:00","guid":{"rendered":"https:\/\/professorpinguim.com.br\/blog\/?p=2345"},"modified":"2023-08-06T21:18:52","modified_gmt":"2023-08-07T00:18:52","slug":"resolucao-da-prova-de-fisica-famema-2016","status":"publish","type":"post","link":"https:\/\/professorpinguim.com.br\/blog\/resolucao-da-prova-de-fisica-famema-2016\/","title":{"rendered":"Resolu\u00e7\u00e3o da prova de F\u00edsica &#8211; Famema 2016"},"content":{"rendered":"\n<p class=\"wp-block-paragraph\">Oi, pessoal! Belezinha?<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Vamos juntos resolver a prova da Famema 2016? As quest\u00f5es est\u00e3o abaixo e as resolu\u00e7\u00f5es, no v\u00eddeo. Bora?<\/p>\n\n\n\n<!--more-->\n\n\n\n<h3 class=\"wp-block-heading\">Quest\u00e3o 1:<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">Um brinquedo consiste em um fole acoplado a um tubo pl\u00e1stico horizontal que se encaixa na traseira de um carrinho, inicialmente em repouso. Quando uma crian\u00e7a pisa no fole, comprimindo-o at\u00e9 o final, o ar expelido impulsiona o carrinho.<\/p>\n\n\n\n<div class=\"wp-block-image\"><figure class=\"aligncenter size-large\"><img decoding=\"async\" width=\"241\" height=\"176\" src=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2020\/12\/brinquedo.png\" alt=\"\" class=\"wp-image-2346\"\/><\/figure><\/div>\n\n\n\n<p class=\"wp-block-paragraph\">Considere que a massa do carrinho seja de 300 g, que o tempo necess\u00e1rio para que a crian\u00e7a comprima completamente o fole seja de 0,2 s e que ao final desse intervalo de tempo o carrinho adquira uma velocidade de 8 m\/s. Admitindo desprez\u00edveis todas as for\u00e7as de resist\u00eancia ao movimento do carrinho, o m\u00f3dulo da for\u00e7a m\u00e9dia (Fm\u00e9d) aplicada pelo ar expelido pelo tubo sobre o carrinho, nesse intervalo de tempo, \u00e9 igual a<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(A) 10 N.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(B) 14 N.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(C) 12 N.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(D) 8 N.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(E) 16 N<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Quest\u00e3o 2:<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">A figura mostra parte de um aqu\u00e1rio no qual a \u00e1gua encontra-se parada. Nesse ambiente, o peixe amarelo movimenta-se do ponto A ao ponto D, segundo a trajet\u00f3ria ABCD representada pela linha branca.<\/p>\n\n\n\n<div class=\"wp-block-image\"><figure class=\"aligncenter size-large\"><img fetchpriority=\"high\" decoding=\"async\" width=\"240\" height=\"251\" src=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2020\/12\/aqu\u00e1rio.png\" alt=\"\" class=\"wp-image-2347\"\/><\/figure><\/div>\n\n\n\n<p class=\"wp-block-paragraph\">Considerando a densidade da \u00e1gua constante ao longo de todo o trajeto, assinale a alternativa que indica corretamente o esbo\u00e7o do gr\u00e1fico de como varia a press\u00e3o sobre o peixe amarelo, em fun\u00e7\u00e3o do tempo, nesse deslocamento.<\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img decoding=\"async\" width=\"182\" height=\"498\" src=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2020\/12\/respostas-quest\u00e3o-2.png\" alt=\"\" class=\"wp-image-2348\" srcset=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2020\/12\/respostas-quest\u00e3o-2.png 182w, https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2020\/12\/respostas-quest\u00e3o-2-110x300.png 110w\" sizes=\"(max-width: 182px) 100vw, 182px\" \/><\/figure>\n\n\n\n<h3 class=\"wp-block-heading\">Quest\u00e3o 3:<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">Uma pessoa observa uma letra F impressa em uma folha de papel utilizando uma lente convergente como lupa, a qual \u00e9 mantida em repouso, paralela \u00e0 folha e a 10 cm dela. Nessa situa\u00e7\u00e3o, as dimens\u00f5es da imagem s\u00e3o tr\u00eas vezes maiores do que as da letra impressa, conforme mostra a figura.<\/p>\n\n\n\n<div class=\"wp-block-image\"><figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"292\" height=\"170\" src=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2020\/12\/letra-f.png\" alt=\"\" class=\"wp-image-2349\"\/><\/figure><\/div>\n\n\n\n<p class=\"wp-block-paragraph\">Considerando v\u00e1lidas as condi\u00e7\u00f5es de nitidez de Gauss, a dist\u00e2ncia focal da lente utilizada pela pessoa, em cent\u00edmetros, \u00e9 igual a<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(A) 37,5.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(B) 15,0.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(C) 22,5.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(D) 7,50.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(E) 30,0.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Quest\u00e3o 4:<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">Com o objetivo de simular as ondas no mar, foram geradas, em uma cuba de ondas de um laborat\u00f3rio, as ondas bidimensionais representadas na figura, que se propagam de uma regi\u00e3o mais funda (regi\u00e3o 1) para uma regi\u00e3o mais rasa (regi\u00e3o 2).<\/p>\n\n\n\n<div class=\"wp-block-image\"><figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"272\" height=\"223\" src=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2020\/12\/cuba-de-ondas.png\" alt=\"\" class=\"wp-image-2350\"\/><\/figure><\/div>\n\n\n\n<p class=\"wp-block-paragraph\">Sabendo que quando as ondas passam de uma regi\u00e3o para a outra sua frequ\u00eancia de oscila\u00e7\u00e3o n\u00e3o se altera e considerando as medidas indicadas na figura, \u00e9 correto afirmar que a raz\u00e3o v1\/v2 entre as velocidades de propaga\u00e7\u00e3o das ondas nas regi\u00f5es 1 e 2 \u00e9 igual a<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(A) 1,6.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(B) 0,4.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(C) 2,8.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(D) 2,5.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(E) 1,2.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Quest\u00e3o 5:<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">Um garoto desenvolveu, para a feira de ci\u00eancias de sua escola, um projeto que chamou de \u201cA casa el\u00e9trica\u201d. Para isso, utilizou resistores \u00f4hmicos e fios met\u00e1licos de resist\u00eancia desprez\u00edvel, representados em vermelho na figura. Para dar a forma que queria \u00e0 casa, tamb\u00e9m utilizou materiais isolantes,<br>representados em azul. Todos os elementos da casa est\u00e3o contidos em um mesmo plano.<\/p>\n\n\n\n<div class=\"wp-block-image\"><figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"260\" height=\"172\" src=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2020\/12\/a-casa-el\u00e9trica.png\" alt=\"\" class=\"wp-image-2351\"\/><\/figure><\/div>\n\n\n\n<p class=\"wp-block-paragraph\">Pode-se afirmar corretamente que a resist\u00eancia equivalente entre os pontos A e B da figura, em ohms, \u00e9 igual a<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(A) 50.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(B) 60.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(C) 30.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(D) 20.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(E) 40.<\/p>\n\n\n\n<figure class=\"wp-block-embed-youtube aligncenter wp-block-embed is-type-video is-provider-youtube wp-embed-aspect-16-9 wp-has-aspect-ratio\"><div class=\"wp-block-embed__wrapper\">\n<iframe title=\"FAMEMA 2016 - Resolu\u00e7\u00e3o da prova de F\u00edsica  - Professor Pinguim\" width=\"800\" height=\"450\" src=\"https:\/\/www.youtube.com\/embed\/_RnfVWtgRSQ?feature=oembed\" frameborder=\"0\" allow=\"accelerometer; autoplay; clipboard-write; encrypted-media; gyroscope; picture-in-picture; web-share\" referrerpolicy=\"strict-origin-when-cross-origin\" allowfullscreen><\/iframe>\n<\/div><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Tem d\u00favidas de como funciona a minha plataforma e a minha metodologia de ensino? <strong><a rel=\"noreferrer noopener\" href=\"https:\/\/conteudo.professorpinguim.com.br\/experimente-plataforma\" target=\"_blank\">Clique aqui<\/a> <\/strong>e acesse gratuitamente os m\u00f3dulos de <strong>Cinem\u00e1tica <\/strong>e <strong>\u00d3ptica<\/strong> do meu <strong>\u00a0SEMIEXTENSIVO exclusivo para FUVEST, UNICAMP, UNESP E UNIFESP. <\/strong>Tenho certeza que vai mudar a sua vida.<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2020\/07\/BannerBlog_728x90.png\" alt=\"O atributo alt desta imagem est\u00e1 vazio. O nome do arquivo \u00e9 BannerBlog_728x90.png\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Me acompanhe nas redes sociais: curta a minha&nbsp;<a href=\"https:\/\/www.facebook.com\/professorpinguim\/\"><strong>p\u00e1gina no Facebook<\/strong><\/a><strong>,<\/strong>&nbsp;me&nbsp;siga no&nbsp;<a href=\"https:\/\/www.instagram.com\/professorpinguim\/\"><strong>Instagram<\/strong><\/a><strong>,<\/strong>&nbsp;se inscreva no&nbsp;<a href=\"https:\/\/www.youtube.com\/c\/PinguimV%C3%ADdeoF%C3%ADsica\/?sub_confirmation=1\"><strong>Youtube<\/strong><\/a>&nbsp;e participe do meu canal oficial no&nbsp;<strong><a href=\"http:\/\/professorpinguim.com.br\/telegram\">Telegram<\/a><\/strong>.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Oi, pessoal! Belezinha? Vamos juntos resolver a prova da Famema 2016? As quest\u00f5es est\u00e3o abaixo e as resolu\u00e7\u00f5es, no v\u00eddeo. Bora?<\/p>\n","protected":false},"author":1,"featured_media":2352,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[448],"tags":[450,452,449,457],"class_list":["post-2345","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-exercicios-resolvidos-famema","tag-famema","tag-prova-de-fisica-famema","tag-prova-famema","tag-prova-famema-2016"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v20.12 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Resolu\u00e7\u00e3o da prova de F\u00edsica - Famema 2016 - Professor Pinguim | F\u00edsica<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/professorpinguim.com.br\/blog\/resolucao-da-prova-de-fisica-famema-2016\/\" \/>\n<meta property=\"og:locale\" content=\"pt_BR\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Resolu\u00e7\u00e3o da prova de F\u00edsica - Famema 2016 - Professor Pinguim | F\u00edsica\" \/>\n<meta property=\"og:description\" content=\"Oi, pessoal! 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