{"id":2336,"date":"2020-12-03T21:00:00","date_gmt":"2020-12-04T00:00:00","guid":{"rendered":"https:\/\/professorpinguim.com.br\/blog\/?p=2336"},"modified":"2023-08-06T21:18:53","modified_gmt":"2023-08-07T00:18:53","slug":"resolucao-da-prova-de-fisica-famema-2017","status":"publish","type":"post","link":"https:\/\/professorpinguim.com.br\/blog\/resolucao-da-prova-de-fisica-famema-2017\/","title":{"rendered":"Resolu\u00e7\u00e3o da prova de F\u00edsica &#8211; Famema 2017"},"content":{"rendered":"\n<p class=\"wp-block-paragraph\">Oi, pessoal! Belezinha?<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Vamos juntos resolver a prova da Famema 2017? As quest\u00f5es est\u00e3o abaixo e as resolu\u00e7\u00f5es, no v\u00eddeo. Bora?<\/p>\n\n\n\n<!--more-->\n\n\n\n<h3 class=\"wp-block-heading\">Quest\u00e3o 1:<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">Um helic\u00f3ptero sobrevoa horizontalmente o solo com velocidade constante e, no ponto A, abandona um objeto de dimens\u00f5es desprez\u00edveis que, a partir desse instante, cai sob a\u00e7\u00e3o exclusiva da for\u00e7a peso e toca o solo plano e horizontal no ponto B. Na figura, o helic\u00f3ptero e o objeto s\u00e3o representados em quatro instantes diferentes.<\/p>\n\n\n\n<div class=\"wp-block-image\"><figure class=\"aligncenter size-large\"><img fetchpriority=\"high\" decoding=\"async\" width=\"341\" height=\"262\" src=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2020\/12\/helic\u00f3ptero.png\" alt=\"\" class=\"wp-image-2337\" srcset=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2020\/12\/helic\u00f3ptero.png 341w, https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2020\/12\/helic\u00f3ptero-300x230.png 300w\" sizes=\"(max-width: 341px) 100vw, 341px\" \/><\/figure><\/div>\n\n\n\n<p class=\"wp-block-paragraph\">Considerando as informa\u00e7\u00f5es fornecidas, \u00e9 correto afirmar que a altura h de sobrevoo desse helic\u00f3ptero \u00e9 igual a<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(A) 200 m.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(B) 220 m.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(C) 240 m.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(D) 160 m.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(E) 180 m.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Quest\u00e3o 2:<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">A figura representa, em corte, parte de uma instala\u00e7\u00e3o utilizada para demonstra\u00e7\u00f5es de experimentos. Um corpo de dimens\u00f5es desprez\u00edveis escorrega pela superf\u00edcie inclinada e atinge o ponto A com velocidade escalar igual a 10 m\/s. Considere o atrito e a resist\u00eancia do ar desprez\u00edveis e<br>g = 10 m\/s2.<\/p>\n\n\n\n<div class=\"wp-block-image\"><figure class=\"aligncenter size-large\"><img decoding=\"async\" width=\"321\" height=\"186\" src=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2020\/12\/instala\u00e7\u00e3o-demonstra\u00e7\u00e3o-de-experimentos.png\" alt=\"\" class=\"wp-image-2338\" srcset=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2020\/12\/instala\u00e7\u00e3o-demonstra\u00e7\u00e3o-de-experimentos.png 321w, https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2020\/12\/instala\u00e7\u00e3o-demonstra\u00e7\u00e3o-de-experimentos-300x174.png 300w\" sizes=\"(max-width: 321px) 100vw, 321px\" \/><\/figure><\/div>\n\n\n\n<p class=\"wp-block-paragraph\">Em rela\u00e7\u00e3o ao n\u00edvel de refer\u00eancia indicado na figura, a altura, na superf\u00edcie inclinada, em que a energia cin\u00e9tica do corpo \u00e9 igual ao triplo de sua energia potencial gravitacional \u00e9<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(A) 1,25 m.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(B) 1,00 m.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(C) 2,00 m.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(D) 1,50 m.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(E) 1,75 m.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Quest\u00e3o 3:<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">Duas m\u00e1quinas t\u00e9rmicas ideais, 1 e 2, t\u00eam seus ciclos termodin\u00e2micos representados no diagrama press\u00e3o \u00d7 volume, no qual est\u00e3o representadas duas transforma\u00e7\u00f5es isot\u00e9rmicas (Tmaior e Tmenor) e quatro transforma\u00e7\u00f5es adiab\u00e1ticas. O ciclo ABCDA refere-se \u00e0 m\u00e1quina 1 e o ciclo EFGHE, \u00e0 m\u00e1quina 2.<\/p>\n\n\n\n<div class=\"wp-block-image\"><figure class=\"aligncenter size-large\"><img decoding=\"async\" width=\"337\" height=\"321\" src=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2020\/12\/duas-m\u00e1quinas-t\u00e9rmicas.png\" alt=\"\" class=\"wp-image-2339\" srcset=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2020\/12\/duas-m\u00e1quinas-t\u00e9rmicas.png 337w, https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2020\/12\/duas-m\u00e1quinas-t\u00e9rmicas-300x286.png 300w\" sizes=\"(max-width: 337px) 100vw, 337px\" \/><\/figure><\/div>\n\n\n\n<p class=\"wp-block-paragraph\">Sobre essas m\u00e1quinas, \u00e9 correto afirmar que, a cada ciclo realizado,<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(A) o rendimento da m\u00e1quina 1 \u00e9 maior do que o da m\u00e1quina 2.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(B) a varia\u00e7\u00e3o de energia interna sofrida pelo g\u00e1s na m\u00e1quina 1 \u00e9 maior do que na m\u00e1quina 2.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(C) a varia\u00e7\u00e3o de energia interna sofrida pelo g\u00e1s na m\u00e1quina 1 \u00e9 menor do que na m\u00e1quina 2.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(D) nenhuma delas transforma integralmente calor em trabalho.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(E) o rendimento da m\u00e1quina 2 \u00e9 maior do que o da m\u00e1quina 1.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Quest\u00e3o 4:<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">Na figura, O \u00e9 um ponto objeto virtual, v\u00e9rtice de um pincel de luz c\u00f4nico convergente que incide sobre um espelho esf\u00e9rico c\u00f4ncavo E de dist\u00e2ncia focal f. Depois de refletidos no espelho, os raios desse pincel convergem para o ponto I sobre o eixo principal do espelho, a uma dist\u00e2ncia f\/4 de seu v\u00e9rtice.<\/p>\n\n\n\n<div class=\"wp-block-image\"><figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"350\" height=\"304\" src=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2020\/12\/pincel-de-luz-c\u00f4nico.png\" alt=\"\" class=\"wp-image-2340\" srcset=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2020\/12\/pincel-de-luz-c\u00f4nico.png 350w, https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2020\/12\/pincel-de-luz-c\u00f4nico-300x261.png 300w\" sizes=\"(max-width: 350px) 100vw, 350px\" \/><\/figure><\/div>\n\n\n\n<p class=\"wp-block-paragraph\">Considerando v\u00e1lidas as condi\u00e7\u00f5es de nitidez de Gauss, \u00e9 correto afirmar que a dist\u00e2ncia focal desse espelho \u00e9 igual a<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(A) 150 cm.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(B) 160 cm.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(C) 120 cm.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(D) 180 cm.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(E) 200 cm.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Quest\u00e3o 5:<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">Uma mesma espira retangular, de massa desprez\u00edvel, foi parcialmente imersa em um mesmo campo magn\u00e9tico constante e uniforme B de duas maneiras distintas. Na primeira, a espira \u00e9 mantida em equil\u00edbrio sob a\u00e7\u00e3o apenas da for\u00e7a vertical F1 e da for\u00e7a magn\u00e9tica gerada pela circula\u00e7\u00e3o de uma corrente el\u00e9trica cont\u00ednua pela espira, conforme figura 1.<\/p>\n\n\n\n<div class=\"wp-block-image\"><figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"264\" height=\"257\" src=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2020\/12\/figura-1.png\" alt=\"\" class=\"wp-image-2341\"\/><\/figure><\/div>\n\n\n\n<p class=\"wp-block-paragraph\">Na segunda, a espira \u00e9 mantida em equil\u00edbrio sob a\u00e7\u00e3o apenas da for\u00e7a vertical F2 e da for\u00e7a magn\u00e9tica gerada pela circula\u00e7\u00e3o de uma corrente el\u00e9trica cont\u00ednua pela espira, conforme figura 2.<\/p>\n\n\n\n<div class=\"wp-block-image\"><figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"279\" height=\"204\" src=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2020\/12\/figura-2.png\" alt=\"\" class=\"wp-image-2342\"\/><\/figure><\/div>\n\n\n\n<p class=\"wp-block-paragraph\">Sabendo que nas duas situa\u00e7\u00f5es a intensidade da corrente el\u00e9trica que circula pela espira \u00e9 a mesma, que a intensidade de F1 \u00e9 10 N e considerando as informa\u00e7\u00f5es contidas nas figuras, \u00e9 correto afirmar que a intensidade de F2 \u00e9 igual a<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(A) 50 N.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(B) 10 N.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(C) 75 N<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(D) 20 N.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(E) 25 N.<\/p>\n\n\n\n<figure class=\"wp-block-embed-youtube aligncenter wp-block-embed is-type-video is-provider-youtube wp-embed-aspect-16-9 wp-has-aspect-ratio\"><div class=\"wp-block-embed__wrapper\">\n<iframe title=\"FAMEMA 2017 - Resolu\u00e7\u00e3o da prova de F\u00edsica  - Professor Pinguim\" width=\"800\" height=\"450\" src=\"https:\/\/www.youtube.com\/embed\/cduSb0tP1N8?feature=oembed\" frameborder=\"0\" allow=\"accelerometer; autoplay; clipboard-write; encrypted-media; gyroscope; picture-in-picture; web-share\" referrerpolicy=\"strict-origin-when-cross-origin\" allowfullscreen><\/iframe>\n<\/div><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Tem d\u00favidas de como funciona a minha plataforma e a minha metodologia de ensino? <strong><a rel=\"noreferrer noopener\" href=\"https:\/\/conteudo.professorpinguim.com.br\/experimente-plataforma\" target=\"_blank\">Clique aqui<\/a> <\/strong>e acesse gratuitamente os m\u00f3dulos de <strong>Cinem\u00e1tica <\/strong>e <strong>\u00d3ptica<\/strong> do meu <strong>\u00a0SEMIEXTENSIVO exclusivo para FUVEST, UNICAMP, UNESP E UNIFESP. <\/strong>Tenho certeza que vai mudar a sua vida.<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2020\/07\/BannerBlog_728x90.png\" alt=\"O atributo alt desta imagem est\u00e1 vazio. O nome do arquivo \u00e9 BannerBlog_728x90.png\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Me acompanhe nas redes sociais: curta a minha&nbsp;<a href=\"https:\/\/www.facebook.com\/professorpinguim\/\"><strong>p\u00e1gina no Facebook<\/strong><\/a><strong>,<\/strong>&nbsp;me&nbsp;siga no&nbsp;<a href=\"https:\/\/www.instagram.com\/professorpinguim\/\"><strong>Instagram<\/strong><\/a><strong>,<\/strong>&nbsp;se inscreva no&nbsp;<a href=\"https:\/\/www.youtube.com\/c\/PinguimV%C3%ADdeoF%C3%ADsica\/?sub_confirmation=1\"><strong>Youtube<\/strong><\/a>&nbsp;e participe do meu canal oficial no&nbsp;<strong><a href=\"http:\/\/professorpinguim.com.br\/telegram\">Telegram<\/a><\/strong>.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Oi, pessoal! Belezinha? Vamos juntos resolver a prova da Famema 2017? As quest\u00f5es est\u00e3o abaixo e as resolu\u00e7\u00f5es, no v\u00eddeo. Bora?<\/p>\n","protected":false},"author":1,"featured_media":2343,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[448],"tags":[450,454,452,449],"class_list":["post-2336","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-exercicios-resolvidos-famema","tag-famema","tag-famema-2017","tag-prova-de-fisica-famema","tag-prova-famema"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v20.12 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Resolu\u00e7\u00e3o da prova de F\u00edsica - Famema 2017 - Professor Pinguim | F\u00edsica<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/professorpinguim.com.br\/blog\/resolucao-da-prova-de-fisica-famema-2017\/\" \/>\n<meta property=\"og:locale\" content=\"pt_BR\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Resolu\u00e7\u00e3o da prova de F\u00edsica - Famema 2017 - Professor Pinguim | F\u00edsica\" \/>\n<meta property=\"og:description\" content=\"Oi, pessoal! 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