{"id":2320,"date":"2020-12-01T21:00:00","date_gmt":"2020-12-02T00:00:00","guid":{"rendered":"https:\/\/professorpinguim.com.br\/blog\/?p=2320"},"modified":"2023-08-06T21:18:57","modified_gmt":"2023-08-07T00:18:57","slug":"resolucao-da-prova-de-fisica-famema-2020","status":"publish","type":"post","link":"https:\/\/professorpinguim.com.br\/blog\/resolucao-da-prova-de-fisica-famema-2020\/","title":{"rendered":"Resolu\u00e7\u00e3o da prova de F\u00edsica &#8211; Famema 2020"},"content":{"rendered":"\n<p class=\"wp-block-paragraph\">Oi, pessoal! Belezinha?<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Vamos juntos resolver a prova da Famema 2020? As quest\u00f5es est\u00e3o abaixo e as resolu\u00e7\u00f5es, no v\u00eddeo. Bora?<\/p>\n\n\n\n<!--more-->\n\n\n\n<h3 class=\"wp-block-heading\">Quest\u00e3o 1:<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">De dentro do \u00f4nibus, que ainda fazia manobras para estacionar no ponto de parada, o rapaz, atrasado para o encontro com a namorada, a v\u00ea indo embora pela cal\u00e7ada. Quando finalmente o \u00f4nibus para e o rapaz desce, a dist\u00e2ncia que o separa da namorada \u00e9 de 180 m.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Sabendo que a namorada do rapaz se movimenta com velocidade constante de 0,5 m\/s e que o rapaz pode correr com velocidade constante de 5 m\/s, o tempo m\u00ednimo para que ele consiga alcan\u00e7\u00e1-la \u00e9 de<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(A) 10 s.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(B) 45 s.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(C) 25 s.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(D) 50 s.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(E) 40 s.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Quest\u00e3o 2:<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">A figura mostra uma esfera, de 250 g, em repouso, apoiada sobre uma mola ideal comprimida. Ao ser liberada, a mola transfere 50 J \u00e0 esfera, que inicia, a partir do repouso e da altura indicada na figura, um movimento vertical para cima<\/p>\n\n\n\n<div class=\"wp-block-image\"><figure class=\"aligncenter size-large\"><img decoding=\"async\" width=\"130\" height=\"141\" src=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2020\/12\/esfera-250g.png\" alt=\"\" class=\"wp-image-2321\"\/><\/figure><\/div>\n\n\n\n<p class=\"wp-block-paragraph\">Desprezando-se a resist\u00eancia do ar e adotando-se g=10 m\/s2, a m\u00e1xima altura que a esfera alcan\u00e7a, em rela\u00e7\u00e3o \u00e0 altura de sua partida, \u00e9<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(A) 40 m.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(B) 25 m.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(C) 20 m.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(D) 10 m.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(E) 50 m.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Quest\u00e3o 3:<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">Considere que um fog\u00e3o forne\u00e7a um fluxo constante de calor e que esse calor seja inteiramente transferido da chama ao que se deseja aquecer. O calor espec\u00edfico da \u00e1gua \u00e9 1,00 cal\/(g\u22c5\u00baC) e o calor espec\u00edfico de determinado \u00f3leo \u00e9 0,45 cal\/(g\u22c5\u00baC). Para que 1000 g de \u00e1gua, inicialmente a 20 \u00baC, atinja a temperatura de 100 \u00baC, \u00e9 necess\u00e1rio aquec\u00ea-la por cinco minutos sobre a chama desse fog\u00e3o. Se 200 g desse \u00f3leo for aquecido nesse fog\u00e3o durante um minuto, a temperatura desse \u00f3leo ser\u00e1 elevada em, aproximadamente,<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(A) 120 \u00baC.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(B) 180 \u00baC.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(C) 140 \u00baC.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(D) 160 \u00baC.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(E) 100 \u00baC.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Quest\u00e3o 4:<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">Ao entrar no banheiro de um shopping, uma pessoa se depara com uma parede onde se encontra afixado um grande espelho plano. Enquanto caminha com velocidade de 1 m\/s em uma dire\u00e7\u00e3o perpendicular a esse espelho e no sentido de aproximar-se dele, essa pessoa observa que, relativamente a seu corpo, sua imagem<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(A) se afasta com velocidade 1 m\/s.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(B) se aproxima com velocidade 2 m\/s.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(C) se aproxima com velocidade 4 m\/s.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(D) se aproxima com velocidade 1 m\/s.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(E) se afasta com velocidade 2 m\/s.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Quest\u00e3o 5:<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">Um potenci\u00f4metro foi constru\u00eddo utilizando-se dois fios resistivos \u00f4hmicos, paralelos, de mesmo comprimento e mesma resist\u00eancia el\u00e9trica. Os fios s\u00e3o tocados por um contato m\u00f3vel, de resist\u00eancia desprez\u00edvel, que desliza perpendicularmente aos fios, tornando todo o conjunto um potenci\u00f4metro. Este potenci\u00f4metro est\u00e1 ligado a um gerador de 100 V e a um<br>amper\u00edmetro, ambos ideais.<\/p>\n\n\n\n<div class=\"wp-block-image\"><figure class=\"aligncenter size-large\"><img fetchpriority=\"high\" decoding=\"async\" width=\"358\" height=\"164\" src=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2020\/12\/potenci\u00f4metro.png\" alt=\"\" class=\"wp-image-2322\" srcset=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2020\/12\/potenci\u00f4metro.png 358w, https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2020\/12\/potenci\u00f4metro-300x137.png 300w\" sizes=\"(max-width: 358px) 100vw, 358px\" \/><\/figure><\/div>\n\n\n\n<p class=\"wp-block-paragraph\">Quando o contato m\u00f3vel do potenci\u00f4metro se encontra na<br>posi\u00e7\u00e3o indicada na figura, o amper\u00edmetro indica a passagem<br>de uma corrente el\u00e9trica de 5 A.<br>Individualmente, cada um dos fios resistivos que constituem<br>o potenci\u00f4metro apresenta, entre seus extremos, a resist\u00eancia el\u00e9trica de<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(A) 80 \u2126.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(B) 40 \u2126.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(C) 20 \u2126.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(D) 100 \u2126.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">(E) 60 \u2126.<\/p>\n\n\n\n<figure class=\"wp-block-embed-youtube aligncenter wp-block-embed is-type-video is-provider-youtube wp-embed-aspect-16-9 wp-has-aspect-ratio\"><div class=\"wp-block-embed__wrapper\">\n<iframe title=\"FAMEMA 2020 - Resolu\u00e7\u00e3o da prova de F\u00edsica  - Professor Pinguim\" width=\"800\" height=\"450\" src=\"https:\/\/www.youtube.com\/embed\/qeFihGcV23k?feature=oembed\" frameborder=\"0\" allow=\"accelerometer; autoplay; clipboard-write; encrypted-media; gyroscope; picture-in-picture; web-share\" referrerpolicy=\"strict-origin-when-cross-origin\" allowfullscreen><\/iframe>\n<\/div><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Tem d\u00favidas de como funciona a minha plataforma e a minha metodologia de ensino? <strong><a rel=\"noreferrer noopener\" href=\"https:\/\/conteudo.professorpinguim.com.br\/experimente-plataforma\" target=\"_blank\">Clique aqui<\/a> <\/strong>e acesse gratuitamente os m\u00f3dulos de <strong>Cinem\u00e1tica <\/strong>e <strong>\u00d3ptica<\/strong> do meu <strong>\u00a0SEMIEXTENSIVO exclusivo para FUVEST, UNICAMP, UNESP E UNIFESP. <\/strong>Tenho certeza que vai mudar a sua vida.<\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><a href=\"https:\/\/professorpinguim.com.br\/\"><img decoding=\"async\" width=\"728\" height=\"90\" src=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2020\/07\/BannerBlog_728x90.png\" alt=\"\" class=\"wp-image-1733\" srcset=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2020\/07\/BannerBlog_728x90.png 728w, https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2020\/07\/BannerBlog_728x90-300x37.png 300w, https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2020\/07\/BannerBlog_728x90-670x83.png 670w\" sizes=\"(max-width: 728px) 100vw, 728px\" \/><\/a><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Me acompanhe nas redes sociais: curta a minha&nbsp;<a href=\"https:\/\/www.facebook.com\/professorpinguim\/\"><strong>p\u00e1gina no Facebook<\/strong><\/a><strong>,<\/strong>&nbsp;me&nbsp;siga no&nbsp;<a href=\"https:\/\/www.instagram.com\/professorpinguim\/\"><strong>Instagram<\/strong><\/a><strong>,<\/strong>&nbsp;se inscreva no&nbsp;<a href=\"https:\/\/www.youtube.com\/c\/PinguimV%C3%ADdeoF%C3%ADsica\/?sub_confirmation=1\"><strong>Youtube<\/strong><\/a>&nbsp;e participe do meu canal oficial no&nbsp;<strong><a href=\"http:\/\/professorpinguim.com.br\/telegram\">Telegram<\/a><\/strong>.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Oi, pessoal! Belezinha? Vamos juntos resolver a prova da Famema 2020? As quest\u00f5es est\u00e3o abaixo e as resolu\u00e7\u00f5es, no v\u00eddeo. Bora?<\/p>\n","protected":false},"author":1,"featured_media":2323,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[448],"tags":[450,451,452,449],"class_list":["post-2320","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-exercicios-resolvidos-famema","tag-famema","tag-famema-2020","tag-prova-de-fisica-famema","tag-prova-famema"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v20.12 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Resolu\u00e7\u00e3o da prova de F\u00edsica - Famema 2020 - Professor Pinguim | F\u00edsica<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/professorpinguim.com.br\/blog\/resolucao-da-prova-de-fisica-famema-2020\/\" \/>\n<meta property=\"og:locale\" content=\"pt_BR\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Resolu\u00e7\u00e3o da prova de F\u00edsica - Famema 2020 - Professor Pinguim | F\u00edsica\" \/>\n<meta property=\"og:description\" content=\"Oi, pessoal! Belezinha? Vamos juntos resolver a prova da Famema 2020? As quest\u00f5es est\u00e3o abaixo e as resolu\u00e7\u00f5es, no v\u00eddeo. Bora?\" \/>\n<meta property=\"og:url\" content=\"https:\/\/professorpinguim.com.br\/blog\/resolucao-da-prova-de-fisica-famema-2020\/\" \/>\n<meta property=\"og:site_name\" content=\"Professor Pinguim | F\u00edsica\" \/>\n<meta property=\"article:publisher\" content=\"https:\/\/www.facebook.com\/Betminds.Digital\/\" \/>\n<meta property=\"article:published_time\" content=\"2020-12-02T00:00:00+00:00\" \/>\n<meta property=\"article:modified_time\" content=\"2023-08-07T00:18:57+00:00\" \/>\n<meta property=\"og:image\" content=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2020\/12\/famema-2020.jpg\" \/>\n\t<meta property=\"og:image:width\" content=\"640\" \/>\n\t<meta property=\"og:image:height\" content=\"480\" \/>\n\t<meta property=\"og:image:type\" content=\"image\/jpeg\" \/>\n<meta name=\"author\" content=\"Professor Pinguim\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Escrito por\" \/>\n\t<meta name=\"twitter:data1\" content=\"Professor Pinguim\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. tempo de leitura\" \/>\n\t<meta name=\"twitter:data2\" content=\"3 minutos\" \/>\n<script type=\"application\/ld+json\" class=\"yoast-schema-graph\">{\"@context\":\"https:\/\/schema.org\",\"@graph\":[{\"@type\":\"WebPage\",\"@id\":\"https:\/\/professorpinguim.com.br\/blog\/resolucao-da-prova-de-fisica-famema-2020\/\",\"url\":\"https:\/\/professorpinguim.com.br\/blog\/resolucao-da-prova-de-fisica-famema-2020\/\",\"name\":\"Resolu\u00e7\u00e3o da prova de F\u00edsica - Famema 2020 - Professor Pinguim | F\u00edsica\",\"isPartOf\":{\"@id\":\"https:\/\/professorpinguim.com.br\/blog\/#website\"},\"datePublished\":\"2020-12-02T00:00:00+00:00\",\"dateModified\":\"2023-08-07T00:18:57+00:00\",\"author\":{\"@id\":\"https:\/\/professorpinguim.com.br\/blog\/#\/schema\/person\/dcbdcdaaf74b619f8b699c2454e5d536\"},\"breadcrumb\":{\"@id\":\"https:\/\/professorpinguim.com.br\/blog\/resolucao-da-prova-de-fisica-famema-2020\/#breadcrumb\"},\"inLanguage\":\"pt-BR\",\"potentialAction\":[{\"@type\":\"ReadAction\",\"target\":[\"https:\/\/professorpinguim.com.br\/blog\/resolucao-da-prova-de-fisica-famema-2020\/\"]}]},{\"@type\":\"BreadcrumbList\",\"@id\":\"https:\/\/professorpinguim.com.br\/blog\/resolucao-da-prova-de-fisica-famema-2020\/#breadcrumb\",\"itemListElement\":[{\"@type\":\"ListItem\",\"position\":1,\"name\":\"In\u00edcio\",\"item\":\"https:\/\/professorpinguim.com.br\/blog\/\"},{\"@type\":\"ListItem\",\"position\":2,\"name\":\"Resolu\u00e7\u00e3o da prova de F\u00edsica &#8211; Famema 2020\"}]},{\"@type\":\"WebSite\",\"@id\":\"https:\/\/professorpinguim.com.br\/blog\/#website\",\"url\":\"https:\/\/professorpinguim.com.br\/blog\/\",\"name\":\"Professor Pinguim | F\u00edsica\",\"description\":\"F\u00edsica para Vestibular Paulista, ENEM e Ensino M\u00e9dio\",\"potentialAction\":[{\"@type\":\"SearchAction\",\"target\":{\"@type\":\"EntryPoint\",\"urlTemplate\":\"https:\/\/professorpinguim.com.br\/blog\/?s={search_term_string}\"},\"query-input\":\"required name=search_term_string\"}],\"inLanguage\":\"pt-BR\"},{\"@type\":\"Person\",\"@id\":\"https:\/\/professorpinguim.com.br\/blog\/#\/schema\/person\/dcbdcdaaf74b619f8b699c2454e5d536\",\"name\":\"Professor Pinguim\",\"image\":{\"@type\":\"ImageObject\",\"inLanguage\":\"pt-BR\",\"@id\":\"https:\/\/professorpinguim.com.br\/blog\/#\/schema\/person\/image\/\",\"url\":\"https:\/\/secure.gravatar.com\/avatar\/ffd75b6cb46865dcea0fd25e6b0348a12def6ae98b940d19c65c9a512d1f0cf6?s=96&r=g\",\"contentUrl\":\"https:\/\/secure.gravatar.com\/avatar\/ffd75b6cb46865dcea0fd25e6b0348a12def6ae98b940d19c65c9a512d1f0cf6?s=96&r=g\",\"caption\":\"Professor Pinguim\"},\"description\":\"A plataforma do Professor Pinguim \u00e9 dedicada ao ensino da F\u00edsica e vai te ensinar com uma metodologia completa essa incr\u00edvel mat\u00e9ria.\",\"sameAs\":[\"https:\/\/professorpinguim.com.br\/\"],\"url\":\"https:\/\/professorpinguim.com.br\/blog\/author\/admin\/\"}]}<\/script>\n<!-- \/ Yoast SEO plugin. -->","yoast_head_json":{"title":"Resolu\u00e7\u00e3o da prova de F\u00edsica - Famema 2020 - Professor Pinguim | F\u00edsica","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/professorpinguim.com.br\/blog\/resolucao-da-prova-de-fisica-famema-2020\/","og_locale":"pt_BR","og_type":"article","og_title":"Resolu\u00e7\u00e3o da prova de F\u00edsica - Famema 2020 - Professor Pinguim | F\u00edsica","og_description":"Oi, pessoal! Belezinha? Vamos juntos resolver a prova da Famema 2020? As quest\u00f5es est\u00e3o abaixo e as resolu\u00e7\u00f5es, no v\u00eddeo. Bora?","og_url":"https:\/\/professorpinguim.com.br\/blog\/resolucao-da-prova-de-fisica-famema-2020\/","og_site_name":"Professor Pinguim | F\u00edsica","article_publisher":"https:\/\/www.facebook.com\/Betminds.Digital\/","article_published_time":"2020-12-02T00:00:00+00:00","article_modified_time":"2023-08-07T00:18:57+00:00","og_image":[{"width":640,"height":480,"url":"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2020\/12\/famema-2020.jpg","type":"image\/jpeg"}],"author":"Professor Pinguim","twitter_card":"summary_large_image","twitter_misc":{"Escrito por":"Professor Pinguim","Est. tempo de leitura":"3 minutos"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/professorpinguim.com.br\/blog\/resolucao-da-prova-de-fisica-famema-2020\/","url":"https:\/\/professorpinguim.com.br\/blog\/resolucao-da-prova-de-fisica-famema-2020\/","name":"Resolu\u00e7\u00e3o da prova de F\u00edsica - Famema 2020 - Professor Pinguim | F\u00edsica","isPartOf":{"@id":"https:\/\/professorpinguim.com.br\/blog\/#website"},"datePublished":"2020-12-02T00:00:00+00:00","dateModified":"2023-08-07T00:18:57+00:00","author":{"@id":"https:\/\/professorpinguim.com.br\/blog\/#\/schema\/person\/dcbdcdaaf74b619f8b699c2454e5d536"},"breadcrumb":{"@id":"https:\/\/professorpinguim.com.br\/blog\/resolucao-da-prova-de-fisica-famema-2020\/#breadcrumb"},"inLanguage":"pt-BR","potentialAction":[{"@type":"ReadAction","target":["https:\/\/professorpinguim.com.br\/blog\/resolucao-da-prova-de-fisica-famema-2020\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/professorpinguim.com.br\/blog\/resolucao-da-prova-de-fisica-famema-2020\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"In\u00edcio","item":"https:\/\/professorpinguim.com.br\/blog\/"},{"@type":"ListItem","position":2,"name":"Resolu\u00e7\u00e3o da prova de F\u00edsica &#8211; Famema 2020"}]},{"@type":"WebSite","@id":"https:\/\/professorpinguim.com.br\/blog\/#website","url":"https:\/\/professorpinguim.com.br\/blog\/","name":"Professor Pinguim | F\u00edsica","description":"F\u00edsica para Vestibular Paulista, ENEM e Ensino M\u00e9dio","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/professorpinguim.com.br\/blog\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"pt-BR"},{"@type":"Person","@id":"https:\/\/professorpinguim.com.br\/blog\/#\/schema\/person\/dcbdcdaaf74b619f8b699c2454e5d536","name":"Professor Pinguim","image":{"@type":"ImageObject","inLanguage":"pt-BR","@id":"https:\/\/professorpinguim.com.br\/blog\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/ffd75b6cb46865dcea0fd25e6b0348a12def6ae98b940d19c65c9a512d1f0cf6?s=96&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/ffd75b6cb46865dcea0fd25e6b0348a12def6ae98b940d19c65c9a512d1f0cf6?s=96&r=g","caption":"Professor Pinguim"},"description":"A plataforma do Professor Pinguim \u00e9 dedicada ao ensino da F\u00edsica e vai te ensinar com uma metodologia completa essa incr\u00edvel mat\u00e9ria.","sameAs":["https:\/\/professorpinguim.com.br\/"],"url":"https:\/\/professorpinguim.com.br\/blog\/author\/admin\/"}]}},"_links":{"self":[{"href":"https:\/\/professorpinguim.com.br\/blog\/wp-json\/wp\/v2\/posts\/2320","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/professorpinguim.com.br\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/professorpinguim.com.br\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/professorpinguim.com.br\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/professorpinguim.com.br\/blog\/wp-json\/wp\/v2\/comments?post=2320"}],"version-history":[{"count":2,"href":"https:\/\/professorpinguim.com.br\/blog\/wp-json\/wp\/v2\/posts\/2320\/revisions"}],"predecessor-version":[{"id":2326,"href":"https:\/\/professorpinguim.com.br\/blog\/wp-json\/wp\/v2\/posts\/2320\/revisions\/2326"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/professorpinguim.com.br\/blog\/wp-json\/wp\/v2\/media\/2323"}],"wp:attachment":[{"href":"https:\/\/professorpinguim.com.br\/blog\/wp-json\/wp\/v2\/media?parent=2320"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/professorpinguim.com.br\/blog\/wp-json\/wp\/v2\/categories?post=2320"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/professorpinguim.com.br\/blog\/wp-json\/wp\/v2\/tags?post=2320"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}