{"id":1745,"date":"2020-08-06T09:00:43","date_gmt":"2020-08-06T12:00:43","guid":{"rendered":"http:\/\/blog.professorpinguim.com.br\/?p=1745"},"modified":"2023-08-06T21:20:19","modified_gmt":"2023-08-07T00:20:19","slug":"fuvest-questoes-resolvidas-de-fisica","status":"publish","type":"post","link":"https:\/\/professorpinguim.com.br\/blog\/fuvest-questoes-resolvidas-de-fisica\/","title":{"rendered":"Fuvest: Quest\u00f5es Resolvidas de F\u00edsica"},"content":{"rendered":"<span style=\"font-weight: 400;\">Ol\u00e1, pessoal, tudo bem?\u00a0<\/span><span style=\"font-weight: 400;\">Neste post, vamos ver e resolver <strong><span style=\"color: #871b95;\">4 quest\u00f5es de F\u00edsica cobradas no vestibular da Fuvest, um dos mais concorridos e dif\u00edceis do pa\u00eds<\/span>.<\/strong> Ent\u00e3o, l\u00e1pis e papel na m\u00e3o, e vamos com calma!<\/span><!--more-->\n<h2><strong><span style=\"color: #871b95;\">Quest\u00e3o 1<\/span><\/strong><\/h2>\n<b>\u00c0 medida que a parcela de ar se eleva na atmosfera, nos limites da troposfera, a temperatura do ar decai a uma raz\u00e3o de 1 \u00b0C a cada 100 metros (Raz\u00e3o Adiab\u00e1tica Seca \u2010 RAS) ou 0,6 \u00b0C a cada 100 metros (Raz\u00e3o Adiab\u00e1tica \u00damida \u2010 RAU).<img loading=\"lazy\" decoding=\"async\" class=\"alignnone wp-image-1746 size-full\" src=\"http:\/\/blog.professorpinguim.com.br\/wp-content\/uploads\/2020\/07\/Raza\u0303o-Adiaba\u0301tica-U\u0301mida-\u2010-RAU.png\" alt=\"\" width=\"1284\" height=\"476\" srcset=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2020\/07\/Raza\u0303o-Adiaba\u0301tica-U\u0301mida-\u2010-RAU.png 1284w, https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2020\/07\/Raza\u0303o-Adiaba\u0301tica-U\u0301mida-\u2010-RAU-300x111.png 300w, https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2020\/07\/Raza\u0303o-Adiaba\u0301tica-U\u0301mida-\u2010-RAU-768x285.png 768w, https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2020\/07\/Raza\u0303o-Adiaba\u0301tica-U\u0301mida-\u2010-RAU-1024x380.png 1024w, https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2020\/07\/Raza\u0303o-Adiaba\u0301tica-U\u0301mida-\u2010-RAU-670x248.png 670w, https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2020\/07\/Raza\u0303o-Adiaba\u0301tica-U\u0301mida-\u2010-RAU-1060x393.png 1060w\" sizes=\"(max-width: 1284px) 100vw, 1284px\" \/><\/b>\n<ul>\n \t<li><b>Considerando os conceitos e a ilustra\u00e7\u00e3o, \u00e9 correto afirmar que as temperaturas do ar, em graus Celsius, T1 e T2, s\u00e3o, respectivamente,<\/b><\/li>\n<\/ul>\n<i><span style=\"font-weight: 400;\">Note e adote: Utilize RAS ou RAU de acordo com a presen\u00e7a ou n\u00e3o de ar saturado.<\/span><\/i>\n\n<i><span style=\"font-weight: 400;\">T<\/span><\/i><i><span style=\"font-weight: 400;\">ar<\/span><\/i><i><span style=\"font-weight: 400;\"> : temperatura do ar<\/span><\/i>\n\n<span style=\"font-weight: 400;\">(A) 8,0 e 26,0.<\/span>\n\n<span style=\"font-weight: 400;\">(B) 12,8 e 28,0.<\/span>\n\n<span style=\"font-weight: 400;\">(C) 12,0 e 26,0.<\/span>\n\n<span style=\"font-weight: 400;\">(D) 12,0 e 20,4.<\/span>\n\n<span style=\"font-weight: 400;\">(E) 11,6 e 20,4.<\/span>\n\n<b>RESOLU\u00c7\u00c3O<\/b>\n\n<span style=\"font-weight: 400;\">Analisando o texto e a figura, podemos definir tr\u00eas regi\u00f5es:<\/span>\n\n<span style=\"font-weight: 400;\">I) 0 a 400 m \u2192 raz\u00e3o adiab\u00e1tica seca \u2013 RAS:<\/span>\n\n<span style=\"font-weight: 400;\">A umidade \u00e9 elevada devido \u00e0s altas temperaturas, por\u00e9m n\u00e3o ocorre precipita\u00e7\u00e3o.<\/span>\n\n<span style=\"font-weight: 400;\">II) 400 m a 1400 m \u2192 raz\u00e3o adiab\u00e1tica \u00famida \u2013 RAU:<\/span>\n\n<span style=\"font-weight: 400;\">A partir dos 400 m, atravessa-se o ponto de condensa\u00e7\u00e3o, o que favorecer\u00e1 a precipita\u00e7\u00e3o devido \u00e0 queda da temperatura.<\/span>\n\n<span style=\"font-weight: 400;\">III) 1400 m a 0 m \u2192 raz\u00e3o adiab\u00e1tica seca \u2013 RAS:<\/span>\n\n<span style=\"font-weight: 400;\">A sotavento, n\u00e3o ocorre precipita\u00e7\u00e3o devido ao aumento da temperatura.<\/span>\n\n<span style=\"font-weight: 400;\">Assim, temos:<\/span>\n\n<span style=\"font-weight: 400;\">1) A 400 m:<\/span>\n\n<span style=\"font-weight: 400;\">T<\/span><span style=\"font-weight: 400;\">0<\/span><span style=\"font-weight: 400;\"> = 20,0\u00b0C \u2013 200 m . <\/span><span style=\"font-weight: 400;\">1 \u00b0C<\/span><span style=\"font-weight: 400;\">100 m<\/span><span style=\"font-weight: 400;\"> = 18,0 \u00b0C<\/span>\n\n<span style=\"font-weight: 400;\">2) A 1400 m:<\/span>\n\n<span style=\"font-weight: 400;\">T<\/span><span style=\"font-weight: 400;\">1<\/span><span style=\"font-weight: 400;\"> = 18,0 \u00b0C \u2013 1000 m . <\/span><span style=\"font-weight: 400;\">0,6 \u00b0C<\/span><span style=\"font-weight: 400;\">100 m<\/span><span style=\"font-weight: 400;\"> = 12,0 \u00b0C<\/span>\n\n<span style=\"font-weight: 400;\">3) A 0 m:<\/span>\n\n<span style=\"font-weight: 400;\">T<\/span><span style=\"font-weight: 400;\">2<\/span><span style=\"font-weight: 400;\"> = 12,0 \u00b0C + 1400 m . <\/span><span style=\"font-weight: 400;\">1 \u00b0C<\/span><span style=\"font-weight: 400;\">100 m<\/span><span style=\"font-weight: 400;\"> = 26,0 \u00b0C<\/span>\n\n<b>RESPOSTA: C<\/b>\n\n<hr \/>\n\n<h2><strong><span style=\"color: #871b95;\">Quest\u00e3o 2<\/span><\/strong><\/h2>\n<b>Os grandes avi\u00f5es comerciais voam em altitudes onde o ar \u00e9 rarefeito e a press\u00e3o atmosf\u00e9rica \u00e9 baixa. Devido a isso, eles t\u00eam o seu interior pressurizado em uma press\u00e3o igual \u00e0 atmosf\u00e9rica na altitude de 2.000 m. A figura mostra o gr\u00e1fico da press\u00e3o atmosf\u00e9rica em fun\u00e7\u00e3o da altitude<img loading=\"lazy\" decoding=\"async\" class=\"alignnone wp-image-1749 size-full\" src=\"http:\/\/blog.professorpinguim.com.br\/wp-content\/uploads\/2020\/07\/A-figura-mostra-o-gra\u0301fico-da-pressa\u0303o-atmosfe\u0301rica-em-func\u0327a\u0303o-da-altitude.png\" alt=\"\" width=\"1230\" height=\"790\" srcset=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2020\/07\/A-figura-mostra-o-gra\u0301fico-da-pressa\u0303o-atmosfe\u0301rica-em-func\u0327a\u0303o-da-altitude.png 1230w, https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2020\/07\/A-figura-mostra-o-gra\u0301fico-da-pressa\u0303o-atmosfe\u0301rica-em-func\u0327a\u0303o-da-altitude-300x193.png 300w, https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2020\/07\/A-figura-mostra-o-gra\u0301fico-da-pressa\u0303o-atmosfe\u0301rica-em-func\u0327a\u0303o-da-altitude-768x493.png 768w, https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2020\/07\/A-figura-mostra-o-gra\u0301fico-da-pressa\u0303o-atmosfe\u0301rica-em-func\u0327a\u0303o-da-altitude-1024x658.png 1024w, https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2020\/07\/A-figura-mostra-o-gra\u0301fico-da-pressa\u0303o-atmosfe\u0301rica-em-func\u0327a\u0303o-da-altitude-670x430.png 670w, https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2020\/07\/A-figura-mostra-o-gra\u0301fico-da-pressa\u0303o-atmosfe\u0301rica-em-func\u0327a\u0303o-da-altitude-1060x681.png 1060w\" sizes=\"(max-width: 1230px) 100vw, 1230px\" \/><\/b>\n\n<b>A for\u00e7a, em N, a que fica submetida uma janela plana de vidro, de 20 x 30 cm<\/b><b>2<\/b><b>, na cabine de passageiros na altitude de 10.000 m, \u00e9, aproximadamente,<\/b>\n\n<span style=\"font-weight: 400;\">(A) 12.400\n<\/span><span style=\"font-weight: 400;\">(B) 6.400\n<\/span><span style=\"font-weight: 400;\">(C) 4.800\n<\/span><span style=\"font-weight: 400;\">(D) 3.200\n<\/span><span style=\"font-weight: 400;\">(E) 1.600<\/span>\n\n<b>RESOLU\u00c7\u00c3O:<\/b>\n\n<span style=\"font-weight: 400;\">De acordo com o gr\u00e1fico:<\/span>\n\n<span style=\"font-weight: 400;\">h<\/span><span style=\"font-weight: 400;\">1<\/span><span style=\"font-weight: 400;\"> = 10.000 m\u2026\u2026 p<\/span><span style=\"font-weight: 400;\">1<\/span><span style=\"font-weight: 400;\"> \u2245 26.000 Pa<\/span>\n\n<span style=\"font-weight: 400;\">h<\/span><span style=\"font-weight: 400;\">2<\/span><span style=\"font-weight: 400;\"> = 2.000 m \u2026\u2026 p<\/span><span style=\"font-weight: 400;\">2<\/span><span style=\"font-weight: 400;\"> \u2245 78.000 Pa<\/span>\n\n<span style=\"font-weight: 400;\">A for\u00e7a resultante aplicada pelo ar sobre a janela \u00e9<\/span>\n\n<span style=\"font-weight: 400;\">dada por:<\/span>\n\n<span style=\"font-weight: 400;\">F<\/span><span style=\"font-weight: 400;\">ar<\/span><span style=\"font-weight: 400;\"> = \u0394p<\/span><span style=\"font-weight: 400;\">ar<\/span><span style=\"font-weight: 400;\"> . A<\/span>\n\n<span style=\"font-weight: 400;\">A = 600 cm<\/span><span style=\"font-weight: 400;\">2<\/span><span style=\"font-weight: 400;\"> = 600 . 10<\/span><span style=\"font-weight: 400;\">\u20134<\/span><span style=\"font-weight: 400;\"> m<\/span><span style=\"font-weight: 400;\">2<\/span><span style=\"font-weight: 400;\"> = 6,0 . 10<\/span><span style=\"font-weight: 400;\">\u20132<\/span><span style=\"font-weight: 400;\"> m<\/span><span style=\"font-weight: 400;\">2<\/span>\n\n<span style=\"font-weight: 400;\">F<\/span><span style=\"font-weight: 400;\">ar<\/span><span style=\"font-weight: 400;\"> \u2245 (78 \u2013 26) . 10<\/span><span style=\"font-weight: 400;\">3<\/span><span style=\"font-weight: 400;\"> . 6,0 . 10<\/span><span style=\"font-weight: 400;\">\u20132<\/span><span style=\"font-weight: 400;\"> (N)<\/span>\n\n<span style=\"font-weight: 400;\">F<\/span><span style=\"font-weight: 400;\">ar<\/span><span style=\"font-weight: 400;\"> \u2245 52 . 6,0 . 10 (N)<\/span>\n\n<span style=\"font-weight: 400;\">F<\/span><span style=\"font-weight: 400;\">ar<\/span><span style=\"font-weight: 400;\"> \u2245 3120 N<\/span>\n\n<span style=\"font-weight: 400;\">O valor mais pr\u00f3ximo \u00e9 3200 N.<\/span>\n\n<b>RESPOSTA: D<\/b>\n\n<hr \/>\n\n<h2><strong><span style=\"color: #871b95;\">Quest\u00e3o 3<\/span><\/strong><\/h2>\n<b>O consumo cal\u00f3rico de um animal de sangue quente \u00e9 proporcional \u00e0 \u00e1rea superficial de seu corpo. Um animal com massa 3,5 kg consome 250 kcal di\u00e1rias. O gr\u00e1fico relaciona a \u00e1rea superficial desse animal com sua massa<\/b><img loading=\"lazy\" decoding=\"async\" class=\"alignnone wp-image-1750 size-full\" src=\"http:\/\/blog.professorpinguim.com.br\/wp-content\/uploads\/2020\/07\/O-gra\u0301fico-relaciona-a-a\u0301rea-superficial-desse-animal-com-sua-massa.png\" alt=\"\" width=\"1250\" height=\"784\" srcset=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2020\/07\/O-gra\u0301fico-relaciona-a-a\u0301rea-superficial-desse-animal-com-sua-massa.png 1250w, https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2020\/07\/O-gra\u0301fico-relaciona-a-a\u0301rea-superficial-desse-animal-com-sua-massa-300x188.png 300w, https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2020\/07\/O-gra\u0301fico-relaciona-a-a\u0301rea-superficial-desse-animal-com-sua-massa-768x482.png 768w, https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2020\/07\/O-gra\u0301fico-relaciona-a-a\u0301rea-superficial-desse-animal-com-sua-massa-1024x642.png 1024w, https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2020\/07\/O-gra\u0301fico-relaciona-a-a\u0301rea-superficial-desse-animal-com-sua-massa-600x375.png 600w, https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2020\/07\/O-gra\u0301fico-relaciona-a-a\u0301rea-superficial-desse-animal-com-sua-massa-670x420.png 670w, https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2020\/07\/O-gra\u0301fico-relaciona-a-a\u0301rea-superficial-desse-animal-com-sua-massa-1060x665.png 1060w\" sizes=\"(max-width: 1250px) 100vw, 1250px\" \/>\n\n<b>Considerando o gr\u00e1fico, conclui-se que, se a massa deste animal dobrar, o seu novo consumo di\u00e1rio de energia, em kcal, ser\u00e1, aproximadamente,<\/b>\n\n<span style=\"font-weight: 400;\">(A) 130\n<\/span>(B) 250\n<span style=\"font-weight: 400;\">(C) 310\n<\/span><span style=\"font-weight: 400;\">(D) 390\n<\/span><span style=\"font-weight: 400;\">(E) 500<\/span>\n\n<b>RESOLU\u00c7\u00c3O:<\/b>\n\n<span style=\"font-weight: 400;\">Sendo C o consumo cal\u00f3rico do animal e A a \u00e1rea superficial de seu corpo, tem-se, de acordo com o enunciado: <\/span><b>C = k A <\/b><span style=\"font-weight: 400;\">em que k \u00e9 uma constante de proporcionalidade.<\/span>\n\n<span style=\"font-weight: 400;\">Do gr\u00e1fico, para a massa de 3,5 kg, obt\u00e9m-se A<\/span><span style=\"font-weight: 400;\">1<\/span><span style=\"font-weight: 400;\"> \u2245 0,14 m<\/span><span style=\"font-weight: 400;\">2<\/span><span style=\"font-weight: 400;\">. Logo: 250 = k 0,14 <\/span><b>\u24f5<\/b>\n\n<span style=\"font-weight: 400;\">Tamb\u00e9m do gr\u00e1fico, para a massa de 2 . 3,5 kg = 7,0 kg, obt\u00e9m-se A<\/span><span style=\"font-weight: 400;\">2<\/span><span style=\"font-weight: 400;\"> \u2245 0,22 m<\/span><span style=\"font-weight: 400;\">2<\/span><span style=\"font-weight: 400;\">.<\/span>\n\n<span style=\"font-weight: 400;\">Assim: C<\/span><span style=\"font-weight: 400;\">2<\/span><span style=\"font-weight: 400;\"> = k 0,22 <\/span><b>\u2781<\/b>\n\n<span style=\"font-weight: 400;\">Dividindo-se <\/span><b>\u24f5<\/b><span style=\"font-weight: 400;\"> por <\/span><b>\u2781<\/b><span style=\"font-weight: 400;\"> membro a membro, depreende-se que: <\/span><span style=\"font-weight: 400;\">C<\/span><span style=\"font-weight: 400;\">2<\/span><span style=\"font-weight: 400;\">250<\/span><span style=\"font-weight: 400;\"> = <\/span><span style=\"font-weight: 400;\">k 0,22<\/span><span style=\"font-weight: 400;\">k 0,14<\/span><span style=\"font-weight: 400;\">\u21d2 C<\/span><span style=\"font-weight: 400;\">2<\/span><span style=\"font-weight: 400;\"> \u2245 390 kcal<\/span>\n\n<b>RESPOSTA: D<\/b>\n\n<hr \/>\n\n<h2><span style=\"color: #871b95;\"><strong><span style=\"color: #871b95;\">Quest\u00e3o<\/span> 4<\/strong><\/span><\/h2>\n<b>Dois corpos de massas iguais s\u00e3o soltos, ao mesmo tempo, a partir do repouso, da altura h<\/b><b>1<\/b><b> e percorrem os diferentes trajetos (A) e (B), mostrados na figura, onde x<\/b><b>1<\/b><b> &gt; x<\/b><b>2<\/b><b> e h<\/b><b>1<\/b><b> &gt; h<\/b><b>2<\/b><b>.<\/b>\n\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone wp-image-1751 size-full\" src=\"http:\/\/blog.professorpinguim.com.br\/wp-content\/uploads\/2020\/07\/Dois-corpos-de-massas-iguais-sa\u0303o-soltos-ao-mesmo-tempo-a-partir-do-repouso.png\" alt=\"\" width=\"1332\" height=\"324\" srcset=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2020\/07\/Dois-corpos-de-massas-iguais-sa\u0303o-soltos-ao-mesmo-tempo-a-partir-do-repouso.png 1332w, https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2020\/07\/Dois-corpos-de-massas-iguais-sa\u0303o-soltos-ao-mesmo-tempo-a-partir-do-repouso-300x73.png 300w, https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2020\/07\/Dois-corpos-de-massas-iguais-sa\u0303o-soltos-ao-mesmo-tempo-a-partir-do-repouso-768x187.png 768w, https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2020\/07\/Dois-corpos-de-massas-iguais-sa\u0303o-soltos-ao-mesmo-tempo-a-partir-do-repouso-1024x249.png 1024w, https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2020\/07\/Dois-corpos-de-massas-iguais-sa\u0303o-soltos-ao-mesmo-tempo-a-partir-do-repouso-670x163.png 670w, https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2020\/07\/Dois-corpos-de-massas-iguais-sa\u0303o-soltos-ao-mesmo-tempo-a-partir-do-repouso-1060x258.png 1060w\" sizes=\"(max-width: 1332px) 100vw, 1332px\" \/>\n\n<b>Considere as seguintes afirma\u00e7\u00f5es:<\/b>\n<ol>\n \t<li><b> As energias cin\u00e9ticas finais dos corpos em (A) e em (B) s\u00e3o diferentes.<\/b><\/li>\n \t<li><b> As energias mec\u00e2nicas dos corpos, logo antes de come\u00e7arem a subir a rampa, s\u00e3o iguais.<\/b><\/li>\n<\/ol>\n<b>III. O tempo para completar o percurso independe da trajet\u00f3ria.<\/b>\n<ol>\n \t<li><b> O corpo em (B) chega primeiro ao final da trajet\u00f3ria.<\/b><\/li>\n \t<li><b> O trabalho realizado pela for\u00e7a peso \u00e9 o mesmo nos dois casos.<\/b><\/li>\n<\/ol>\n<b>\u00c9 correto somente o que se afirma em:<\/b>\n\n<i><span style=\"font-weight: 400;\">Note e adote: Desconsidere for\u00e7as dissipativas.<\/span><\/i>\n\n(A) I e III.\n<span style=\"font-weight: 400;\">(B) II e V\n<\/span><span style=\"font-weight: 400;\">(C) IV e V\n<\/span><span style=\"font-weight: 400;\">(D) II e III\n<\/span><span style=\"font-weight: 400;\">(E) I e V<\/span>\n\n<b>RESOLU\u00c7\u00c3O:<\/b>\n\n<span style=\"font-weight: 400;\">I) Falsa. Nas duas configura\u00e7\u00f5es, temos:<\/span>\n\n<span style=\"font-weight: 400;\">E<\/span><span style=\"font-weight: 400;\">final<\/span><span style=\"font-weight: 400;\"> = E<\/span><span style=\"font-weight: 400;\">inicial<\/span><span style=\"font-weight: 400;\"> (refer\u00eancia no solo)<\/span>\n\n<span style=\"font-weight: 400;\">E<\/span><span style=\"font-weight: 400;\">cin final <\/span><span style=\"font-weight: 400;\">+ mg h<\/span><span style=\"font-weight: 400;\">2<\/span><span style=\"font-weight: 400;\"> = mg h<\/span><span style=\"font-weight: 400;\">1<\/span>\n\n<span style=\"font-weight: 400;\">E<\/span><span style=\"font-weight: 400;\">cin final<\/span><span style=\"font-weight: 400;\"> = mg (h<\/span><span style=\"font-weight: 400;\">1<\/span><span style=\"font-weight: 400;\"> \u2013 h<\/span><span style=\"font-weight: 400;\">2<\/span><span style=\"font-weight: 400;\">)<\/span>\n\n<span style=\"font-weight: 400;\">Portanto: E<\/span><span style=\"font-weight: 400;\">cin B<\/span><span style=\"font-weight: 400;\"> = E<\/span><span style=\"font-weight: 400;\">cin A<\/span>\n\n<span style=\"font-weight: 400;\">II) Verdadeira. Como o sistema \u00e9 conservativo e as energias mec\u00e2nicas iniciais s\u00e3o iguais, ent\u00e3o em qualquer instante as energias mec\u00e2nicas s\u00e3o iguais.<\/span>\n\n<span style=\"font-weight: 400;\">III) Falsa. O tempo total gasto depender\u00e1 da extens\u00e3o da trajet\u00f3ria.<\/span>\n\n<span style=\"font-weight: 400;\">IV) Falsa. De acordo com a figura, o percurso total \u00e9 o mesmo e, como no trajeto A existe um intervalo de tempo em que a velocidade escalar do corpo \u00e9 maior, ent\u00e3o o tempo gasto por A \u00e9 menor e o corpo em A chega primeiro ao final da trajet\u00f3ria.<\/span>\n\n<span style=\"font-weight: 400;\">V) Verdadeira. O trabalho do peso em ambos os casos \u00e9 dado por:<\/span>\n\n<span style=\"font-weight: 400;\">W<\/span><span style=\"font-weight: 400;\">P<\/span><span style=\"font-weight: 400;\"> = mg (h<\/span><span style=\"font-weight: 400;\">1<\/span><span style=\"font-weight: 400;\"> \u2013 h<\/span><span style=\"font-weight: 400;\">2<\/span><span style=\"font-weight: 400;\">)<\/span>\n\n<span style=\"font-weight: 400;\">Portanto: W<\/span><span style=\"font-weight: 400;\">A<\/span><span style=\"font-weight: 400;\"> = W<\/span><span style=\"font-weight: 400;\">B<\/span>\n\n<b>RESPOSTA: B<\/b>\n\n<hr \/>\n\n<span style=\"font-weight: 400;\">Espero que voc\u00ea tenha entendido um pouco melhor sobre o tipo de quest\u00e3o que a Fuvest costuma cobrar. E se quiser ajuda para melhorar seu n\u00edvel de F\u00edsica em outras mat\u00e9rias, <\/span><strong><span style=\"color: #871b95;\"><a style=\"color: #871b95;\" href=\"https:\/\/professorpinguim.com.br\/\">entre em <span style=\"color: #871b95;\">contato<\/span> comigo e escolha o curso de F\u00edsica mais adequado para voc\u00ea<\/a>!<\/span><\/strong>\n<div class=\"entry-content\">\n\n\n\nTem d\u00favidas de como funciona a minha plataforma e a minha metodologia de ensino? <strong><a href=\"https:\/\/conteudo.professorpinguim.com.br\/experimente-plataforma\" target=\"_blank\" rel=\"noreferrer noopener\">Clique aqui<\/a> <\/strong>e acesse gratuitamente os m\u00f3dulos de <strong>Cinem\u00e1tica <\/strong>e <strong>\u00d3ptica<\/strong> do meu <strong>\u00a0SEMIEXTENSIVO exclusivo para FUVEST, UNICAMP, UNESP E UNIFESP. <\/strong>Tenho certeza que vai mudar a sua vida.\n\n \n<figure class=\"wp-block-image size-large\"><a href=\"https:\/\/professorpinguim.com.br\/\"><img loading=\"lazy\" decoding=\"async\" width=\"728\" height=\"90\" class=\"wp-image-1733\" src=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2020\/07\/BannerBlog_728x90.png\" alt=\"\" srcset=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2020\/07\/BannerBlog_728x90.png 728w, https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2020\/07\/BannerBlog_728x90-300x37.png 300w, https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2020\/07\/BannerBlog_728x90-670x83.png 670w\" sizes=\"(max-width: 728px) 100vw, 728px\" \/><\/a><\/figure>\n \n\nMe acompanhe nas redes sociais: curta a minha\u00a0<a href=\"https:\/\/www.facebook.com\/professorpinguim\/\"><strong>p\u00e1gina no Facebook<\/strong><\/a><strong>,<\/strong>\u00a0me\u00a0siga no\u00a0<a href=\"https:\/\/www.instagram.com\/professorpinguim\/\"><strong>Instagram<\/strong><\/a><strong>,<\/strong>\u00a0se inscreva no\u00a0<a href=\"https:\/\/www.youtube.com\/c\/PinguimV%C3%ADdeoF%C3%ADsica\/?sub_confirmation=1\"><strong>Youtube<\/strong><\/a>\u00a0e participe do meu canal oficial no\u00a0<strong><a href=\"http:\/\/professorpinguim.com.br\/telegram\">Telegram<\/a><\/strong>.\n\n\n\n<\/div>","protected":false},"excerpt":{"rendered":"<p>Ol\u00e1, pessoal, tudo bem?\u00a0Neste post, vamos ver e resolver 4 quest\u00f5es de F\u00edsica cobradas no vestibular da Fuvest, um dos mais concorridos e dif\u00edceis do pa\u00eds. Ent\u00e3o, l\u00e1pis e papel na m\u00e3o, e vamos com calma!<\/p>\n","protected":false},"author":1,"featured_media":1756,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[282],"tags":[211,210,215,213,214,212],"class_list":["post-1745","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-exercicios-resolvidos-fuvest","tag-exercicios","tag-fuvest","tag-questao-de-fisica","tag-questoes","tag-questoes-resolvidas-de-fisica","tag-vestibulares"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v20.12 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Fuvest: Quest\u00f5es Resolvidas de F\u00edsica - Professor Pinguim | F\u00edsica<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/professorpinguim.com.br\/blog\/fuvest-questoes-resolvidas-de-fisica\/\" \/>\n<meta property=\"og:locale\" content=\"pt_BR\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Fuvest: Quest\u00f5es Resolvidas de F\u00edsica - Professor Pinguim | F\u00edsica\" \/>\n<meta property=\"og:description\" content=\"Ol\u00e1, pessoal, tudo bem?\u00a0Neste post, vamos ver e resolver 4 quest\u00f5es de F\u00edsica cobradas no vestibular da Fuvest, um dos mais concorridos e dif\u00edceis do pa\u00eds. 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