{"id":14219,"date":"2022-08-07T15:24:11","date_gmt":"2022-08-07T18:24:11","guid":{"rendered":"https:\/\/professorpinguim.com.br\/blog\/?p=14219"},"modified":"2023-08-06T20:59:48","modified_gmt":"2023-08-06T23:59:48","slug":"equilibrio-de-corpo-extenso-torque-momento-de-forca","status":"publish","type":"post","link":"https:\/\/professorpinguim.com.br\/blog\/equilibrio-de-corpo-extenso-torque-momento-de-forca\/","title":{"rendered":"Equil\u00edbrio de Corpo Extenso &#8211; Torque &#8211; Momento de For\u00e7a"},"content":{"rendered":"\n<p class=\"wp-block-paragraph\">Usar cortador de unha, tesoura, alicate, trocar pneu do carro, fazer uma alavanca para levantar um corpo. Todas essas situa\u00e7\u00f5es s\u00e3o embasadas pela teoria desta aula. Acompanhe.<\/p>\n\n\n\n<!--more-->\n\n\n\n<h2 class=\"wp-block-heading\">Momento de uma for\u00e7a ou Torque<\/h2>\n\n\n\n<p class=\"wp-block-paragraph\">Considere a t\u00e1bua da gangorra da figura a seguir. O eixo de rota\u00e7\u00e3o \u00e9 fixo no centro da gangorra. A t\u00e1bua est\u00e1 sendo empurrada pelas for\u00e7as F<sub>1<\/sub> e F<sub>2<\/sub>. Essas for\u00e7as poderiam corresponder, por exemplo, \u00e0s a\u00e7\u00f5es de duas crian\u00e7as colocadas nas extremidades da t\u00e1bua.<\/p>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img fetchpriority=\"high\" decoding=\"async\" src=\"https:\/\/lh6.googleusercontent.com\/Q-86l7fFUPlUQKoNun1yHjLgGlbbHJGVvG_5OBk1EjO4D2XdaErtMINGaCCjXdIQqIjnqBeS4D3TfnIU2R9RAufzryQJlwoE6CZ9zNResQguxyxDn-6R_CZiZzvMmGSkSJW9fUqzNQXwOMYprqfyeQg\" alt=\"\" width=\"393\" height=\"163\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Se apenas a for\u00e7a F<sub>1<\/sub> atuasse na t\u00e1bua, provocaria uma rota\u00e7\u00e3o no sentido anti-hor\u00e1rio. Por outro lado, se apenas a for\u00e7a F<sub>2<\/sub> atuasse na t\u00e1bua, a rota\u00e7\u00e3o teria sentido hor\u00e1rio.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">A grandeza f\u00edsica momento (torque) est\u00e1 relacionada \u00e0 capacidade de uma for\u00e7a em produzir rota\u00e7\u00e3o em um corpo extenso. O momento de uma for\u00e7a pode ser determinado multiplicando-se o m\u00f3dulo da for\u00e7a pelo bra\u00e7o.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Momento de uma for\u00e7a<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">|M| = F . b<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Bra\u00e7o de uma for\u00e7a (b) \u00e9 a dist\u00e2ncia entre o eixo de rota\u00e7\u00e3o e a linha de a\u00e7\u00e3o da for\u00e7a.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">A unidade de momento, no Sistema Internacional, \u00e9 o newton multiplicado pelo metro:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">[M] = N.m<\/p>\n\n\n\n<h2 class=\"wp-block-heading\">Condi\u00e7\u00f5es de equil\u00edbrio de um corpo extenso r\u00edgido<\/h2>\n\n\n\n<p class=\"wp-block-paragraph\">Para que um corpo extenso permane\u00e7a em equil\u00edbrio devem-se impor duas condi\u00e7\u00f5es: equil\u00edbrio de transla\u00e7\u00e3o e equil\u00edbrio de rota\u00e7\u00e3o.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Equil\u00edbrio de transla\u00e7\u00e3o<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Para que um corpo extenso n\u00e3o sofra transla\u00e7\u00e3o, ou seja, para que n\u00e3o saia do lugar, a soma vetorial das for\u00e7as deve ser nula.<\/p>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img decoding=\"async\" src=\"https:\/\/lh4.googleusercontent.com\/N77yh1NwdlA8cNCjIcX2clGNOP2D2sJAZAJygPFfTAlBUWRqTo4EBhXlagBFYVhkk_sFZfLt7whmya5zbRn7h48jRBFeYlElhEEZ5sPRDuIhzAkvnwZZQhW-Q70t5OAL-NhYoYYMwJ6boWIwAiUkb2w\" alt=\"\" width=\"68\" height=\"38\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Equil\u00edbrio de rota\u00e7\u00e3o<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Para que um corpo extenso n\u00e3o sofre rota\u00e7\u00e3o, ou seja, n\u00e3o gire em torno de um eixo, o momento total no sentido hor\u00e1rio deve cancelar o efeito do momento total no sentido anti-hor\u00e1rio.<\/p>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img decoding=\"async\" src=\"https:\/\/lh6.googleusercontent.com\/Z5thz-UTwQDPkse3py93EfveMGMJjuwUaq2XE7heXjUcIjwQtcC0b7R40RPIE0PZsqxpEQjlFxPmfqVkF--WMk5XOKZv25A5MDNI_FxcTnih33VsFbb-QbtToAcTBRhVvvUwEWoyifzuOmcyLg0nedI\" alt=\"\" width=\"216\" height=\"50\"\/><\/figure>\n\n\n\n<h2 class=\"wp-block-heading\">Exemplo de aplica\u00e7\u00e3o<\/h2>\n\n\n\n<p class=\"wp-block-paragraph\">Considere a barra r\u00edgida da figura a seguir. As for\u00e7as F<sub>1<\/sub>, F<sub>2<\/sub> , peso (P) e normal (N) s\u00e3o perpendiculares em rela\u00e7\u00e3o \u00e0 barra. As dist\u00e2ncias b<sub>1<\/sub>, b<sub>2<\/sub> e b<sub>3<\/sub> s\u00e3o os bra\u00e7os dessas for\u00e7as F<sub>1<\/sub>, F<sub>2<\/sub> e peso. O bra\u00e7o da normal \u00e9 nulo.<\/p>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/lh5.googleusercontent.com\/HeKOWveltq29PXTslkXM4fFFCEoiJDbI34kkZGm14B0ZPjpFhJB9W4YmsGelBVrkDCxjAhuZhYDsr4UHmwNhirPe7lOW1Vs0xtyYIiRt7zce47DgBbv3nJRATzWcZyZD_tuKUYNIPlLQkgGIk7-FrJ8\" alt=\"\" width=\"413\" height=\"244\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Para que a barra permane\u00e7a em equil\u00edbrio, devemos ter:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Equil\u00edbrio de transla\u00e7\u00e3o<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">F<sub>RESULTANTE<\/sub> = 0 &nbsp; &nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">N = F<sub>1<\/sub> + F<sub>2<\/sub> + P<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Equil\u00edbrio de rota\u00e7\u00e3o<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Considerando que o bra\u00e7o da normal, nesse caso, \u00e9 nulo, o momento da normal tamb\u00e9m ser\u00e1 nulo.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">A for\u00e7a F<sub>1<\/sub> produz momento anti-hor\u00e1rio e as for\u00e7as peso e F<sub>2<\/sub> produzem momentos hor\u00e1rios. Para que a barra n\u00e3o gire o momento de F<sub>1<\/sub>\u00ad deve ser igual \u00e0 soma do momento de F<sub>2<\/sub>&nbsp; com o momento do peso.<\/p>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/lh6.googleusercontent.com\/DzuJKR43GSTfPvp3NfYwuxemT7rtHgvFWCypyb0bAH5hA192nVUb15gDcQ6JePQr3zEqJRU6QdEXWb7mGpbvgaXqjIpJnL64l2Oo-b0U4inuvHCKksAeBDq6YHx6TI68yjvcurzwVQgIyjUNNTW-lx4\" alt=\"\" width=\"174\" height=\"37\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">F<sub>1<\/sub> . b<sub>1<\/sub> = F<sub>2<\/sub> . b<sub>2<\/sub> + P. b<sub>3<\/sub><\/p>\n\n\n\n<hr class=\"wp-block-separator\"\/>\n\n\n\n<p class=\"wp-block-paragraph\">Aprenda mais com exerc\u00edcios resolvidos<br><\/p>\n\n\n\n<figure class=\"wp-block-embed-youtube wp-block-embed is-type-video is-provider-youtube wp-embed-aspect-16-9 wp-has-aspect-ratio\"><div class=\"wp-block-embed__wrapper\">\n<iframe title=\"TORQUE | Equil\u00edbrio Corpo Extenso | Momento de For\u00e7a [Professor Pinguim]\" width=\"800\" height=\"450\" src=\"https:\/\/www.youtube.com\/embed\/yns5xHBRqRg?feature=oembed\" frameborder=\"0\" allow=\"accelerometer; autoplay; clipboard-write; encrypted-media; gyroscope; picture-in-picture; web-share\" referrerpolicy=\"strict-origin-when-cross-origin\" allowfullscreen><\/iframe>\n<\/div><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Usar cortador de unha, tesoura, alicate, trocar pneu do carro, fazer uma alavanca para levantar um corpo. Todas essas situa\u00e7\u00f5es s\u00e3o embasadas pela teoria desta aula. Acompanhe.<\/p>\n","protected":false},"author":101017,"featured_media":14222,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[956],"tags":[987,994,986,990,989,985,991,993,992,356,988,359],"class_list":["post-14219","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-geral","tag-braco-de-alavanca","tag-como-se-calcula-momento","tag-equilibrio-de-corpo-extenso","tag-fisica-momento-de-forca","tag-fisica-torque","tag-momento-de-forca","tag-momento-de-uma-forca","tag-quais-os-tipos-de-momento","tag-quando-o-momento-e-negativo","tag-torque","tag-torque-fisica","tag-torque-ou-momento"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v20.12 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Equil\u00edbrio de Corpo Extenso - Torque - Momento de For\u00e7a - Professor Pinguim | F\u00edsica<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/professorpinguim.com.br\/blog\/equilibrio-de-corpo-extenso-torque-momento-de-forca\/\" \/>\n<meta property=\"og:locale\" content=\"pt_BR\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Equil\u00edbrio de Corpo Extenso - Torque - Momento de For\u00e7a - Professor Pinguim | F\u00edsica\" \/>\n<meta property=\"og:description\" content=\"Usar cortador de unha, tesoura, alicate, trocar pneu do carro, fazer uma alavanca para levantar um corpo. 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