{"id":11669,"date":"2022-06-08T09:00:00","date_gmt":"2022-06-08T12:00:00","guid":{"rendered":"https:\/\/professorpinguim.com.br\/blog\/?p=11669"},"modified":"2023-08-06T21:00:00","modified_gmt":"2023-08-07T00:00:00","slug":"capacitores-funcao-e-exercicios","status":"publish","type":"post","link":"https:\/\/professorpinguim.com.br\/blog\/capacitores-funcao-e-exercicios\/","title":{"rendered":"Capacitores: Fun\u00e7\u00e3o e Exerc\u00edcios"},"content":{"rendered":"\n<p class=\"wp-block-paragraph\">Nesta aula, vamos falar sobre capacitores. Ao final, vamos fazer exerc\u00edcios para fixa\u00e7\u00e3o do conte\u00fado. Bora l\u00e1!<\/p>\n\n\n\n<!--more-->\n\n\n\n<h2 class=\"wp-block-heading\">Carga armazenada em capacitor<\/h2>\n\n\n\n<p class=\"wp-block-paragraph\">O s\u00edmbolo que utilizamos para capacitor \u00e9 o seguinte:<\/p>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img decoding=\"async\" src=\"https:\/\/lh3.googleusercontent.com\/zDXI21VjesyvO4_efDgM1BZxdd6Lbz9OpISnQiwJFF_oWtA2WnJ4DoNL9vO9qG6hpZBiKnB26zHg5Zx5JexKNCWKPusGHexByLUlhuJYckFXL_yjCyRMfMqSwm_R4E22obQ_FVbYqeO4HjGZOw\" alt=\"\" width=\"227\" height=\"117\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Importante: <\/strong>cuidados para n\u00e3o confundir com os s\u00edmbolos utilizados para representar geradores e resistores<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Dentro dos capacitores temos um material isolante chamado diel\u00e9trico. Quando ligados o capacitor a uma bateria, conseguimos carreg\u00e1-lo, criando um circuito como o da figura abaixo:<\/p>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img decoding=\"async\" src=\"https:\/\/lh6.googleusercontent.com\/C8g_1RXfn-wdRrfqhVfdrJSNeQChNDW8VxeBXydpmTeYPmS3c6K_5_FxsCMlJjOn8SKlpWzAi9jpM78BPGCsE_eHFercSuRO8TCPeHHjAzE5h-n81S2cBpFFgRfaKRne5yleW7KlhodvzrBSKQ\" alt=\"\" width=\"144\" height=\"148\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Importante notar que, nesse circuito, a corrente (i) passar\u00e1 apenas pelo lado de fora. Ou seja, no capacitor n\u00e3o passa corrente, ele apenas armazena carga el\u00e9trica (Q) nas suas placas: uma positiva e outra negativa.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Para fazer o capacitor armazenar carga, basta ligarmos uma ddp (U). O material diel\u00e9trico isola as duas placas de metal, evitando fa\u00edscas.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Para calcular a carga armazenada no capacitor, utilizamos a f\u00f3rmula:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Q = C . U<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\"><li>Q: carga el\u00e9trica armazenada<\/li><li>U: ddp entre as placas<\/li><li>C: capacit\u00e2ncia<\/li><\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">Caso uma quest\u00e3o nos pe\u00e7a para calcular a energia potencial el\u00e9trica armazenada no capacitor, usaremos a seguinte f\u00f3rmula:<\/p>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img decoding=\"async\" src=\"https:\/\/lh4.googleusercontent.com\/YptzJnX3KC-k7dxZDUxd0pZpqt7ZOF9KoXGLiYi75YOmYWVqe3iU7JS9cMAiazJ6k2J1ANE35MNHTrD_zQ1W0TdXt7HZ2zOsfrbv95feRXxzMMCzNiAjHhAXwOlVEtI5AbtveZU227aJ4iYLkg\" alt=\"\" width=\"125\" height=\"51\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Veja que podemos substituir Q pela f\u00f3rmula que vimos h\u00e1 pouco. Isso nos daria:<\/p>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/lh4.googleusercontent.com\/uOVJtAH9a1tmlWlB1Z5FUst-x9bur392mNTxOB_rCjA1nqKcuj-slZ_B8HF7-pPmHtsumlgfe68965MV7b0DuiJTxsRO_z6Bp09KeLLfviUBwVe_gF5gRV4xbATYcyde8r2s4I8b9gL_muPe8w\" alt=\"\" width=\"132\" height=\"50\"\/><\/figure>\n\n\n\n<h2 class=\"wp-block-heading\">Capacitor plano de placas paralelas<\/h2>\n\n\n\n<p class=\"wp-block-paragraph\">Observe a imagem:<\/p>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/lh3.googleusercontent.com\/ZSzG3Z0ICw1Vg-wWLEZ82JNfA3wg2FY27J3EQE-bc0Egbtf9MaT2V3ZxaRBwbvophEpAqp85U0lcqOuYf9Kru8e-iNZWbmLBCa96dfPI6Eqxy7h3GHszek1DaxYIkWkZEbPj5i9Tl6yXFD8x_Q\" alt=\"\" width=\"186\" height=\"159\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Este \u00e9 um tipo de capacitor especial, que possui uma f\u00f3rmula de capacit\u00e2ncia espec\u00edfica. Esse c\u00e1lculo vai depender da \u00e1rea (A), da dist\u00e2ncia entre as placas (d) e tamb\u00e9m constante diel\u00e9trica entre elas (\u03b5):<\/p>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/lh6.googleusercontent.com\/8N0MKd6ALoryxq7J1D4J3XZvU_ZKm4lx5EAAd0cR1ODjxiW_Oy5Aq5SsBRi372743fTb8iSdxyJAxCR5lozuFl3SiecyuSso9ZORwcTQOWEx0pVs-vNKr0Q-O75UF2FXAT1xweEingHbHtxVKg\" alt=\"\" width=\"98\" height=\"44\"\/><\/figure>\n\n\n\n<h2 class=\"wp-block-heading\">Associa\u00e7\u00e3o de capacitores em s\u00e9rie<\/h2>\n\n\n\n<p class=\"wp-block-paragraph\">Veja:<\/p>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/lh5.googleusercontent.com\/9jeadOk3CglCkbrasRj5Q6CsOSAGmSiMK0nV7QmWd6bwlMXejYrUw4DXehg06bcrIKwhpBbT38wxYUy0ZvmBWHF9wpTun2kJgLfDoKVll4q9nInWVxTYo-J0BYJ3k_RqRow2B7Q_h_ETMgUing\" alt=\"\" width=\"289\" height=\"159\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Quando associamos capacitores em s\u00e9rie, a carga ser\u00e1 a mesma para todos. Ou seja, toda vez que um capacitor adquire uma carga, o mesmo acontecer\u00e1 com os outros. Ent\u00e3o:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Q<sub>Total<\/sub> = Q<sub>1<\/sub> = Q<sub>2<\/sub> = Q<sub>3<\/sub><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">J\u00e1 em rela\u00e7\u00e3o \u00e0 ddp, temos a mesma situa\u00e7\u00e3o dos resistores, isto \u00e9, devemos somar as ddp de todos os capacitores:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">U<sub>Total<\/sub> = U<sub>1<\/sub> + U<sub>2<\/sub> + U<sub>3<\/sub><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Agora veja: vimos que Q = C . U. Como todos os capacitores ligados em s\u00e9rie ter\u00e3o a mesma carga, o capacitor que tiver menor capacit\u00e2ncia \u00e9 o que vai ter maior ddp.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Note tamb\u00e9m que, se a ddp total \u00e9 a soma de todas as outras, podemos isolar U na f\u00f3rmula e teremos:<\/p>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/lh3.googleusercontent.com\/wUcqni9grB9oW8tfTdSRsCQmQqkVFtxztrOpH-SHISyO9A3YPCsghfnNADd9Gu344q6A9k_7cRzqGlpERBNrI2pVdMnfhHhi2fuJpWAdLljGIVNUbiClhNooKOUiRD2fHCktoqQYS_MFRaHe_Q\" alt=\"\" width=\"176\" height=\"60\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Quando tivermos apenas dois capacitores ligados em s\u00e9rie, teremos uma outra f\u00f3rmula, que ser\u00e1 o produto pela soma:<\/p>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/lh5.googleusercontent.com\/ZqjIw1a8LTLMS23ZViEof0e34uLDw0FjeqsswsyMVY243KBS1_WqAi5IJYm017nVuzHzMMJWh5eA1KPr_MCg17DdkUw_6Wa4Hvz5p-DrCj_2Dl20NDxjMlcU-K3ZJXyXXCX85E0si7A7C2cQNw\" alt=\"\" width=\"125\" height=\"54\"\/><\/figure>\n\n\n\n<h2 class=\"wp-block-heading\">Capacitores ligados em paralelo<\/h2>\n\n\n\n<p class=\"wp-block-paragraph\">Os capacitores em paralelo est\u00e3o ligados no mesmo par de pontos. Veja:<\/p>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/lh5.googleusercontent.com\/WcOTDl9fy1HRml1izcYN5FiFXzzIsTDamzxqSG_eMfOB8s6bSt0ycE5uAubGh1eqjLSj43wNt39BTleXdqGmLv5tcXcbxeYsOcK8Z0GWrrIN2Es6BBmjbxDS7q7I9I8ne0D_GvWVfYrYlWo2lg\" alt=\"\" width=\"315\" height=\"138\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Nesse caso, todos os capacitores recebem a mesma ddp:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">U<sub>Total<\/sub> = U<sub>1<\/sub> = U<sub>2<\/sub> = U<sub>3<\/sub><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Por outro lado, devemos somar as cargas de cada um para descobrir a carga total:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Q<sub>Total<\/sub> = Q<sub>1<\/sub> + Q<sub>2<\/sub> + Q<sub>3<\/sub><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Para calcular a capacit\u00e2ncia equivalente, basta somarmos as capacit\u00e2ncias de cada capacitor:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">C<sub>Eq<\/sub> = C<sub>1<\/sub> + C<sub>2<\/sub> + C<sub>3<\/sub><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Como vimos que Q = C . U e que a ddp \u00e9 a mesma para todos, vai acumular mais carga o capacitor que tiver mais capacit\u00e2ncia.<\/p>\n\n\n\n<h2 class=\"wp-block-heading\">Associa\u00e7\u00e3o mista de capacitores<\/h2>\n\n\n\n<p class=\"wp-block-paragraph\">Para vermos a associa\u00e7\u00e3o mista de capacitores, vamos fazer isso na pr\u00e1tica, vendo um exemplo e calculando tudo o que uma quest\u00e3o pode nos pedir para calcular:<\/p>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/lh4.googleusercontent.com\/q3a0hzzxCNsbg5CRGR0YpDycwF4WerlRcazYXqK3PjvN6NPb2wjLNaJ_jhMAQyEh_wW04E1iK4gpzGIecOZo-CeQYfbaXG2JZRocYTjpSRbCWDz9kyG_dUIt3ge-dk3W5UDYA7TbqOxi6aE9xA\" alt=\"\" width=\"275\" height=\"153\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Veja que temos um capacitor de 20 \u03bcF ligado em paralelo com um capacitor de 60 \u03bcF e que esses dois est\u00e3o ligados em s\u00e9rie (ap\u00f3s resolvermos os c\u00e1lculos da liga\u00e7\u00e3o em paralelo) a outro capacitor de 10 \u03bcF. Esse sistema est\u00e1 ligado a uma fonte de 90 V.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Vamos calcular a capacit\u00e2ncia equivalente e as cargas armazenadas, total e em cada capacitor<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Para come\u00e7ar, vamos resolver os capacitores ligados em paralelo:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">C<sub>1<\/sub> = 20 + 60 = \u03bcF<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Com isso, conseguimos &#8220;eliminar&#8221; a liga\u00e7\u00e3o em paralelo do sistema, ficando apenas com uma liga\u00e7\u00e3o em s\u00e9rie entre esse &#8220;novo&#8221; capacitor de 80 \u03bcF e o de 10 \u03bcF.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Nesse caso, para encontrar a capacit\u00e2ncia, basta fazermos o produto pela soma. Portanto:<\/p>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/lh6.googleusercontent.com\/Vpm0KaPRjbU7LDCNCTSXBrxwdcWGMg2_nHGqNDPdVCd8j0Nt0VnFo0oi5sIHOotgivuslQ-yPwd3sGZuHnk3pmQJd9ZSVX6k1dCseC4_Vhq_hLH7zaNbQ6nUk4WTNmTt_2kIoFCjggsdAABrAw\" alt=\"\" width=\"125\" height=\"55\"\/><\/figure>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/lh3.googleusercontent.com\/EYWVzD-KltOMUulBViwUxGueUyIVt3hxBY8d-Mz4bDRyN25SUJ5PseBeCa6oC5q8WfI6WuY5mMGnqY0CL4cmh_xKNQVahtb1mV_xZpBUBapeXmk0GTxhd9xbzLG9vyC0SnoGg2HviYtKngAIAA\" alt=\"\" width=\"138\" height=\"50\"\/><\/figure>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/lh6.googleusercontent.com\/068MZ2HDbqUQCLJmqN4TPrsUmp0YtX_nHeiHM3ifrijLTr7ijVurU0O5m5ExDRyflPrk-GnoWF-81NrHlQXxjTZW7wFndOnfstRJ83kN3XfRFK6RkuuVycQyo9vf7D-XeglZchaYXNQMAqji1A\" alt=\"\" width=\"143\" height=\"59\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Repare que agora chegamos a um sistema que possui uma bateria e um capacitor. Assim, podemos aplicar a f\u00f3rmula para calcular a carga.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Q = C<sub>eq<\/sub> . U<\/p>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/lh5.googleusercontent.com\/Cgux6fzonYBmARUg-hkoPg92-K8a2d3Z2c0myO-uN-kyqAUCLF-yteMhsNJ8oQlr_hAkiaa8rh-nbO9xE4U7ZZI4p5oSx65doO_7Nk7ogOfLMXltp2oV-8NJNCSUycyu6PYqzRK4HShuR2aHWQ\" alt=\"\" width=\"106\" height=\"36\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Q = 800 \u03bcC<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Pergunta: qual capacitor pega essa carga que calculamos? Essa carga \u00e9 relativa ao capacitor em que calculamos a capacidade equivalente.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">No entanto, voltando um passo para tr\u00e1s, quando t\u00ednhamos dois capacitores, um de 80 \u03bcF e outro de 10 \u03bcF, a\u00ed sim a carga de cada um deles ser\u00e1 de 800 \u03bcC. Afinal, eles n\u00e3o estavam ligados em s\u00e9rie? Quando isso acontece, as cargas s\u00e3o iguais, lembra?<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Ent\u00e3o, quando calculamos a carga total da associa\u00e7\u00e3o mista de capacitores, acabamos encontrando, tamb\u00e9m, o resultado da associa\u00e7\u00e3o em s\u00e9rie.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Saber isso \u00e9 importante pois podemos calcular a ddp que chegar\u00e1 a cada um dos capacitores em s\u00e9rie, pois j\u00e1 sabemos a carga a capacit\u00e2ncia.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Vamos chamar o capacitor de 80 \u03bcF de A e o de 10 \u03bcF de B. Utilizando a f\u00f3rmula:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Q<sub>A<\/sub> = C<sub>A<\/sub> . U<sub>A<\/sub><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">800 = 80 . U<sub>A<\/sub><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">U<sub>A<\/sub> = 10 V<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Para o outro, n\u00e3o precisamos utilizar a f\u00f3rmula novamente, pois a carga total \u00e9 igual \u00e0 soma das cargas dos capacitores. Ou seja, se U<sub>A<\/sub> vale 10 V, ent\u00e3o U<sub>B<\/sub> s\u00f3 pode valer 80 V, pois a carga total \u00e9 90 V.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Voltando mais um passo, vamos calcular quanto de carga cada um dos capacitores ligados em paralelo recebe. Chamando o de 20 \u03bcF de X e o de 60 de Y, vamos utilizar a f\u00f3rmula:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Q<sub>X<\/sub> = C<sub>X<\/sub> . U<sub>X<\/sub><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Note que a ddp desse capacitor \u00e9 a mesma que calculamos anteriormente, pois transformamos essa liga\u00e7\u00e3o em paralelo em uma em s\u00e9rie, lembra? Ent\u00e3o:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Q<sub>X<\/sub> = 20 . 10<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Q<sub>X<\/sub> = 200 \u03bcC<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Para o outro:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Q<sub>Y<\/sub> = 60 . 10<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Q<sub>Y<\/sub> = 600 \u03bcC<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Veja que n\u00e3o precisar\u00edamos ter calculado Q<sub>Y<\/sub>, pois, em paralelo, a carga total \u00e9 igual \u00e0 soma das cargas de cada capacitor.<\/p>\n\n\n\n<hr class=\"wp-block-separator\"\/>\n\n\n\n<h2 class=\"wp-block-heading\">Exerc\u00edcio de fixa\u00e7\u00e3o sobre capacitores<\/h2>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>(EsPCEx) Um capacitor de capacit\u00e2ncia igual a 2 \u00b5F est\u00e1 completamente carregado e possui uma diferen\u00e7a de potencial entre suas armaduras de 3 V. Em seguida, este capacitor \u00e9 ligado a um resistor \u00f4hmico por meio de fios condutores ideais, conforme representado no circuito abaixo, sendo completamente descarregado atrav\u00e9s do resistor.&nbsp;<\/strong><\/p>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/lh5.googleusercontent.com\/gtycv8SrlWR5z-6NmefcvZuUlz3ZmAr5X1yaVOva3KEz6CX0637fDrNRYhCr7U7CL9NSsMXJu0g3_oeGgN1pNMAQCDIRtBijHpCJhGXUVzvFKC_NpW82kmnkyozZVPJbQVjPDDl1iGHqYUSm5w\" alt=\"\" width=\"310\" height=\"159\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Nesta situa\u00e7\u00e3o, a energia el\u00e9trica total transformada em calor pelo resistor \u00e9 de<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">&nbsp;a) 1,5 . 10<sup>-6<\/sup> J&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">b) 6,0 . 10<sup>-6<\/sup> J<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">c) 9,0 . 10<sup>-6<\/sup> J<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">d) 12,0 . 10<sup>-6<\/sup> J<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">e) 18,0 . 10<sup>-6<\/sup> J&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>RESOLU\u00c7\u00c3O:<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">A energia que ser\u00e1 dissipada no resistor \u00e9 a mesma que estava acumulada no capacitor. Dito isso, vamos lembrar uma das f\u00f3rmulas para calcular a energia potencial do capacitor. Como temos C e U, j\u00e1 podemos utilizar direto:<\/p>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/lh4.googleusercontent.com\/uOVJtAH9a1tmlWlB1Z5FUst-x9bur392mNTxOB_rCjA1nqKcuj-slZ_B8HF7-pPmHtsumlgfe68965MV7b0DuiJTxsRO_z6Bp09KeLLfviUBwVe_gF5gRV4xbATYcyde8r2s4I8b9gL_muPe8w\" alt=\"\" width=\"108\" height=\"41\"\/><\/figure>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/lh6.googleusercontent.com\/TGWGE2I6fDhws8V3vRwxMnvkcblr6oDDg6GfqRJQ57gRgaof5UyNEkq0rHsZVFtrfPJq1wwG8QKWNAthVL2JKQ62D4PRR1WJpVwmvsKuNcRvkna_-N7XxNmROOf-KLd6YIIdey6PrXN8fQuzEA\" alt=\"\" width=\"122\" height=\"44\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">E<sub>pot<\/sub> = 9.10<sup>-6<\/sup> J<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">RESPOSTA: C<\/p>\n\n\n\n<hr class=\"wp-block-separator\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Para aprender mais<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">Se quiser assistir a esta aula, acesse:<\/p>\n\n\n\n<figure class=\"wp-block-embed-youtube wp-block-embed is-type-video is-provider-youtube wp-embed-aspect-16-9 wp-has-aspect-ratio\"><div class=\"wp-block-embed__wrapper\">\n<iframe title=\"Capacitores\" width=\"800\" height=\"450\" src=\"https:\/\/www.youtube.com\/embed\/IhskQWZCaO4?feature=oembed\" frameborder=\"0\" allow=\"accelerometer; autoplay; clipboard-write; encrypted-media; gyroscope; picture-in-picture; web-share\" referrerpolicy=\"strict-origin-when-cross-origin\" allowfullscreen><\/iframe>\n<\/div><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Espero que voc\u00ea tenha entendido um pouco melhor sobre<strong> <\/strong>capacitores. E se quiser ajuda para melhorar seu n\u00edvel de F\u00edsica em outras mat\u00e9rias,<a href=\"https:\/\/professorpinguim.com.br\/\"> <strong>entre em contato comigo e escolha o curso de F\u00edsica mais adequado para voc\u00ea<\/strong><\/a><strong>!<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>SAIBA MAIS<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">\ud83d\udc27 <a href=\"https:\/\/professorpinguim.com.br\/blog\/exercicios-de-eletrodinamica-carga-corrente-eletrica-e-ddp\/\">Exerc\u00edcios de Eletrodin\u00e2mica: Carga, Corrente El\u00e9trica e DDP<br><\/a>\ud83d\udc27 <a href=\"https:\/\/professorpinguim.com.br\/blog\/leis-de-kirchhoff-definicao-exemplo-e-exercicios\/\">Leis de Kirchhoff: defini\u00e7\u00e3o, exemplo e exerc\u00edcios!<br><\/a>\ud83d\udc27 <a href=\"https:\/\/professorpinguim.com.br\/blog\/qual-e-a-formula-para-calcular-a-corrente-eletrica\/\">Qual \u00e9 a f\u00f3rmula para calcular a corrente el\u00e9trica?<\/a><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Me acompanhe nas redes sociais: curta a minha <a href=\"https:\/\/www.facebook.com\/professorpinguim\/\"><strong>p\u00e1gina no Facebook<\/strong><\/a><strong>,<\/strong> me siga no <a href=\"https:\/\/www.instagram.com\/professorpinguim\/\"><strong>Instagram<\/strong><\/a><strong>,<\/strong> se inscreva no <a href=\"https:\/\/www.youtube.com\/c\/PinguimV%C3%ADdeoF%C3%ADsica\/?sub_confirmation=1\"><strong>Youtube<\/strong><\/a> e participe do meu canal oficial no <a href=\"https:\/\/professorpinguim.com.br\/telegram\"><strong>Telegram<\/strong><\/a>.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Nesta aula vamos ver como calcular a carga el\u00e9trica armazenada em um capacitor e ainda aprendera a calcular associa\u00e7\u00e3o de capacitores em s\u00e9rie e em paralelo.<\/p>\n","protected":false},"author":1,"featured_media":11670,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[746,729],"tags":[941,935,936,937,939,940,938,762],"class_list":["post-11669","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-eletricidade","category-eletrostatica","tag-capacitancia-equivalente","tag-capacitor","tag-capacitor-em-paralelo","tag-capacitor-em-serie","tag-capacitor-exercicios","tag-carga-eletrica-no-capacitor","tag-circuito-eletrico","tag-eletrostatica"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v20.12 - 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