{"id":11263,"date":"2022-05-27T09:00:00","date_gmt":"2022-05-27T12:00:00","guid":{"rendered":"https:\/\/professorpinguim.com.br\/blog\/?p=11263"},"modified":"2023-08-06T21:00:27","modified_gmt":"2023-08-07T00:00:27","slug":"reflexao-total","status":"publish","type":"post","link":"https:\/\/professorpinguim.com.br\/blog\/reflexao-total\/","title":{"rendered":"Reflex\u00e3o Total"},"content":{"rendered":"\n<p class=\"wp-block-paragraph\">Nesta aula, vamos resolver algumas quest\u00f5es sobre Reflex\u00e3o Total da Luz. Antes, vamos revisar os principais conceitos. Acompanhe!<\/p>\n\n\n\n<!--more-->\n\n\n\n<h1 class=\"wp-block-heading\">\u00c2ngulo Limite e Reflex\u00e3o Total da&nbsp; Luz<\/h1>\n\n\n\n<p class=\"wp-block-paragraph\">Quando a luz sofre refra\u00e7\u00e3o de um meio mais refringente para um meio menos refringente, o raio de luz se afasta da normal, como determina a Lei de Snell-Descartes<\/p>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img fetchpriority=\"high\" decoding=\"async\" src=\"https:\/\/lh5.googleusercontent.com\/fkUaxB09gP_8FNxZmLgrabw3WNSyuHXCjN6nvOMMTVc_ajEJZanOxKbAruKX-kCpGgDT7xxWn4z7qc_j-roeOFxB0by6E7wSt9nulM_4Njbbjsso9bZhsQiC0tAOjpRSamEtcriyXKj1F6tLwg\" alt=\"\" width=\"321\" height=\"276\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Quanto maior o \u00e2ngulo de incid\u00eancia, maior o \u00e2ngulo de refra\u00e7\u00e3o.<\/p>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img decoding=\"async\" src=\"https:\/\/lh4.googleusercontent.com\/QEcL39ytzVuYU82RNHKXq0__Z1XZkmhFPt46_vVdD-xLnCnSGn6Ugn-ZSyEsWMC_hwG2VI39LKZBXSChgH49LUiwyF-wZrfEJjWt0eJPwHfHB46kkTkrEUmgYNoTGzB8Wyi35VBRIhwVPFQ6xw\" alt=\"\" width=\"317\" height=\"251\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Chega uma hora que o \u00e2ngulo de incid\u00eancia \u00e9 t\u00e3o grande que o raio refratado fica quase rasante \u00e0 superf\u00edcie de separa\u00e7\u00e3o dos meios. Neste caso, chamamos o \u00e2ngulo de incid\u00eancia de \u00c2ngulo Limite, L.<br><br><img decoding=\"async\" src=\"https:\/\/lh4.googleusercontent.com\/QXDkYZaCgM4orXa5zXt1eoW-YePsYrgbS9yr4yq8OWqu1QWsOgaBXyti-wXYhJO-CkePbqGMkr6xsrhISAAOQgCq39xqd3zcJkWJiM8CqpEEVPrcyQwW_jAWfP4U0C2TT37wjcEH3u6TF_LNDw\" width=\"329\" height=\"230\"><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Este \u00e2ngulo Limite pode ser calculado usando a Lei de Snell:<\/p>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/lh5.googleusercontent.com\/VZLMBeEFi1KSsWll0y_8jWV7_k09TamuyDnXCyHY2UsUdoLz7hh-6kgt-HYnniO1I1kDd-GNIfRiiEfIFYxCAGdGn3sRF0N7pUpTJ6jgqqkKwxq3F-E43U2pOXkLAmqCcBb5NlR-5hFi1E984w\" alt=\"\" width=\"369\" height=\"133\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Como sen 90\u00b0= 1, temos<\/p>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/lh4.googleusercontent.com\/c8EOW-44NGr2iAPbWtqOwgc6DBDhU-yKLrhwkWl-E_TLkQirX8Tufsbqvj7C9eC2fG-S0cgdOmHRFvxUUk3xkO3s6mSMrBs0BR4j6aRQBnIoqQ9nVs9LD3WqYMjzT9nxPn-9aUb0zcBcx8O9WA\" alt=\"\" width=\"256\" height=\"102\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Como o meio B \u00e9 menos refringente que o meio A, podemos escrever:<br><img decoding=\"async\" src=\"https:\/\/lh4.googleusercontent.com\/DukYLjrixxA-KteFV-srDBD-eQTlzAxgII7Eh3sbOOSleLTEPZ9sk-sQjDV9uwPCDJzspH408NDLRGLD9LnWc4ZgerKg9b8ygF4fnPj71ffarqRp2uMRRIluoUBXQ2K6ts_Nzcs61BXoVUK65Q\" style=\"width: 300px;\"><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Se o \u00e2ngulo de incid\u00eancia for maior que o \u00e2ngulo Limite L, a luz n\u00e3o mais refrata e sofre a chamada <strong>reflex\u00e3o total<\/strong>, retornando para o meio de origem.<br><br><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/lh6.googleusercontent.com\/B3t8DEvhU05kWyKeziwytFC7pqTuBG3Opmfc89qOONvllYy83XMPzivifjHYxm93xqSSqm4NQKWmFh0bcBTEwVSqefB0HG9DnnQHwPzGqv7yCmjdDYiT-bAiIoj2-HNst00tagZdPBjyhZ5-tg\" width=\"292\" height=\"201\"><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Note que o \u00e2ngulo de reflex\u00e3o \u00e9 igual ao \u00e2ngulo de incid\u00eancia:&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">r = i<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Condi\u00e7\u00f5es para ocorrer a Reflex\u00e3o Total:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">1) A luz deve se propagar no sentido do meio mais refringente para o meio menos refringente<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">2) O \u00e2ngulo de incid\u00eancia deve ser maior que o \u00e2ngulo Limite: i &gt; L<\/p>\n\n\n\n<hr class=\"wp-block-separator\"\/>\n\n\n\n<h1 class=\"wp-block-heading\">Exerc\u00edcios de Reflex\u00e3o Total<\/h1>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>&nbsp;1. (Fmc)&nbsp;<\/strong> Refrat\u00f4metro \u00e9 um dispositivo \u00f3ptico utilizado para medir o \u00edndice de refra\u00e7\u00e3o de subst\u00e2ncias transl\u00facidas. A subst\u00e2ncia \u00e9 depositada sobre a superf\u00edcie plana de um meio com \u00edndice de refra\u00e7\u00e3o conhecido (n<sub>0<\/sub>). Um feixe de luz monocrom\u00e1tico atravessa esse meio e incide na interface que o separa da subst\u00e2ncia cujo \u00edndice de refra\u00e7\u00e3o (n) desejamos medir. O refrat\u00f4metro faz uso do fen\u00f4meno de reflex\u00e3o total, onde raios de luz com \u00e2ngulos de incid\u00eancia maiores do que um \u00e2ngulo limite (ou cr\u00edtico)&nbsp; s\u00e3o totalmente refletidos nessa interface. O refrat\u00f4metro identifica esse \u00e2ngulo limite e, a partir dele, <strong>n<\/strong> \u00e9 determinado.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">&nbsp;Dois l\u00edquidos com \u00edndices de refra\u00e7\u00f5es distintos n<sub>1<\/sub> e n<sub>2<\/sub> s\u00e3o observados em um refrat\u00f4metro. Verifica-se que o \u00e2ngulo limite do l\u00edquido 1 \u00e9 maior que o do l\u00edquido 2.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">&nbsp;A rela\u00e7\u00e3o entre os \u00edndices de refra\u00e7\u00e3o n<sub>0<\/sub>, n<sub>1<\/sub> e n<sub>2<\/sub> \u00e9:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">a) n<sub>0<\/sub> &gt; n<sub>1<\/sub> &gt; n<sub>2<\/sub>&nbsp; &nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">b) n<sub>0<\/sub> &gt; n<sub>2<\/sub> &gt; n<sub>1<\/sub>&nbsp; &nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">c) n<sub>2<\/sub> &gt; n<sub>1<\/sub> &gt; n<sub>0<\/sub>&nbsp; &nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">d) n<sub>1<\/sub> &gt; n<sub>2<\/sub> &gt; n<sub>0<\/sub>&nbsp; &nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">e) n<sub>1<\/sub> &gt; n<sub>0<\/sub> &gt; n<sub>2<\/sub>&nbsp; &nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Resposta: <\/strong>[A]<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/lh5.googleusercontent.com\/UVOzXywD-yAOojdAwdZsVfm8M3w7O6aPkTubjPe9Cm0JlQKT6ux9jnW9hY0XbFTMdpOAIUHaqg9bbx6jmzNSWf9WU37XKCzErE6bOJkd37XuNvIOCI2B3H41nxZKiJbUfZ-R4Ec8QeMXxOZzlw\" alt=\"\"\/><\/figure>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/lh3.googleusercontent.com\/30iSPk-wmB5h1rYK48KwjOo6Q3nbSbCtpqkxHZ76iWASlg03ri7CnZCRrHC-g6IA-jCH723J-QdQkMz3wWF363-eTukDCaTfFJn5EGdEOGcY8bzQF1L46479LIuDt-eOKkH0dcNwiXCqvwSliQ\" alt=\"\" width=\"497\" height=\"297\"\/><\/figure>\n\n\n\n<hr class=\"wp-block-separator\"\/>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>2. (Mackenzie)&nbsp;<\/strong><\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/lh6.googleusercontent.com\/IfNTMxJKaLyYWu-zQSdK55cKWxl-qYWxPCBkedFWdZxhf51sMHHkPEw8VPL-wRkcihTFbgwgsrrgsbRjPVUR3vA8fzF_4St7rCXTyY33-WW0Qe6KeqCo3pKv97DA7fNchBy-8rO5VudddLzERA\" alt=\"\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\"><strong><em>A flor Vit\u00f3ria R\u00e9gia em um lago amazonense calmo<\/em><\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong><em>&nbsp;<\/em><\/strong>A vit\u00f3ria r\u00e9gia \u00e9 uma flor da Amaz\u00f4nia que tem forma de c\u00edrculo. Tentando guardar uma pepita de ouro, um \u00edndio a pendurou em um barbante prendendo a outra extremidade bem no centro de uma vit\u00f3ria r\u00e9gia de raio R = 0,50 m dentro da \u00e1gua de um lago amazonense muito calmo. Considerando-se o \u00edndice de refra\u00e7\u00e3o do ar igual a 1,0 o da \u00e1gua n<sub>A<\/sub><strong> <\/strong>e o comprimento do barbante, depois de amarrado no centro da flor e solto, 50 cm pode-se afirmar que o valor de n<sub>A<\/sub> de modo que, do lado de fora do lago, ningu\u00e9m consiga ver a pepita de ouro \u00e9:&nbsp;<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/lh3.googleusercontent.com\/HyqletZdK_NjgXBOi3B2JvzrZsScRNZCJxUkMuEy5dYIdGNaw_kSCxwDkf8dCEj9OSw3fpjnJLvu3Q21cecER7lo4yHMAsiIK_46kbvPxvHoYV9YAlG7s2a-h-vfFFPfqO7gtQ4SwIaAURvXdg\" alt=\"\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Resposta: <\/strong>[C]<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/lh5.googleusercontent.com\/sCEm59Ocg3rl8sE-4PfIp35wti617k1VyNlEKEHxgAFtGvSpjcPpI1VtTJ72VqJ77bCqL47vF3BeBQcKNvTRSf66VInIJ_ITKuUFQmJyps5PcpNxCR9dt8UwoHRdjvYXb4jNgiSaWqRk5vAOzA\" alt=\"\"\/><\/figure>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/lh5.googleusercontent.com\/KxiD5N0DZKd45LAQZi_mGWLN9ykpRTuhFHss-tbmQ4I__6pkcqImdQh9rnd8N92DLkyHs4HiMnuV33JLpbEl9ivaNM-yWA4PuLVF15-oog7FY51hyCeBEsOpTylGOV-y46WytEx18kYjmDp5Ng\" alt=\"\"\/><\/figure>\n\n\n\n<hr class=\"wp-block-separator\"\/>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>3. (Ita)<\/strong>&nbsp; Em f\u00e9rias no litoral, um estudante faz para um colega as seguintes observa\u00e7\u00f5es:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">I. A luz solar consiste de uma onda eletromagn\u00e9tica transversal, n\u00e3o polarizada e policrom\u00e1tica.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">II. A partir de um certo hor\u00e1rio, toda a luz solar que incide sobre o mar sofre reflex\u00e3o total.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">III. A brisa mar\u00edtima \u00e9 decorrente da diferen\u00e7a entre o calor espec\u00edfico da areia e o da \u00e1gua do mar.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">&nbsp;A respeito dessas observa\u00e7\u00f5es, \u00e9 correto afirmar que<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">a) todas s\u00e3o verdadeiras.&nbsp; &nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">b) apenas I \u00e9 falsa.&nbsp; &nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">c) apenas II \u00e9 falsa.&nbsp; &nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">d) apenas III \u00e9 falsa.&nbsp; &nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">e) h\u00e1 mais de uma observa\u00e7\u00e3o falsa.&nbsp; &nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Resposta: <\/strong>C<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">[I] Verdadeira. A luz solar \u00e9 uma onda eletromagn\u00e9tica transversal, cujos campos el\u00e9trico e magn\u00e9tico oscilam perpendicularmente \u00e0 sua dire\u00e7\u00e3o de propaga\u00e7\u00e3o em planos diversos, o que implica numa caracter\u00edstica de n\u00e3o polariza\u00e7\u00e3o. E como a luz solar (supostamente branca) \u00e9 constitu\u00edda pela jun\u00e7\u00e3o de v\u00e1rias cores, ela \u00e9 policrom\u00e1tica.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">[II] Falsa. Para que ocorra reflex\u00e3o total, o raio de luz deve partir do meio mais refringente para o menos refringente. Como n<sub>ar<\/sub>&lt;n<sub>agua<\/sub> n\u00e3o ocorre tal fen\u00f4meno.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">[III] Verdadeira. A diferen\u00e7a entre os calores espec\u00edficos c<sub>agua<\/sub> &gt; c<sub>areia<\/sub>&nbsp; dos meios faz com que haja diferen\u00e7a nas temperaturas do ar sobre ambos, assim como em suas densidades, fazendo com que o ar sobre a areia suba e o ar sobre a \u00e1gua do mar se desloque para o continente.<\/p>\n\n\n\n<hr class=\"wp-block-separator\"\/>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>4. (Fgv)<\/strong>&nbsp; S\u00e3o dados os \u00edndices de refra\u00e7\u00e3o absolutos&nbsp; dos seguintes meios \u00f3pticos: n<sub>ar<\/sub> = 1 n<sub>\u00e1gua<\/sub> = 1,3;&nbsp; n<sub>vidro C<\/sub> = 1,5 n<sub>vidro P<\/sub> = 1,8<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/lh4.googleusercontent.com\/QI3VPw_XAWO9bzYqGg-9MyEanI52nruDx5Sd-JoSkdYeutqUvKHve7C8qP50spOJZhq1dfIT1a1tCMSTO_aMrtyBSP6zc529wIGOF6-BBJ9GKQXlvSZpnrhsiqtXBK1NFcg2tDpM829vTYZl_g\" alt=\"\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Um raio de luz monocrom\u00e1tica foi emitido sobre um sistema \u00f3ptico formado por 3 desses meios, obtendo-se a configura\u00e7\u00e3o seguinte. I e II s\u00e3o dioptros planos, que separam os meios A de B e B de C respectivamente.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Resposta: <\/strong>A<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/lh4.googleusercontent.com\/xp2irpMJemLQqvUCVFmuXx5iO4IjO5fyPmGyTVrBbN_m1Z7yAqUmXOXKuLA9Y14cJgZJ1rZUncSH5UogHE5Kf-5kEWJi9ybKg3fTRbTdAi9Mlm3KwXTTLAQnx_rwxynLRfg4j0Va99nRP6Wi2w\" alt=\"\"\/><\/figure>\n\n\n\n<hr class=\"wp-block-separator\"\/>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>5. (Ufjf-pism)&nbsp;<\/strong> Em um experimento realizado em um laborat\u00f3rio, Maria Meitner colocou uma caneta laser adequadamente protegida no fundo de um aqu\u00e1rio e depois o encheu com um l\u00edquido desconhecido. Ao instalar o laser, ela mediu o \u00e2ngulo limite,&nbsp; para que ocorra a reflex\u00e3o total na interface com o ar, encontrando o valor de&nbsp; A figura a seguir representa o experimento, sendo que a seta no fundo do aqu\u00e1rio representa a caneta laser e as outras, por sua vez, indicam a dire\u00e7\u00e3o de propaga\u00e7\u00e3o do feixe.<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/lh5.googleusercontent.com\/XW1r2acKiurI6_2v4yQt6pbLJbWK0ssEwcRoxbpYMLj_XhEcDrcKuu5K9He73p6mTm0IHEqfdJMliDNqYvfdMjLl3abb7Arnfs3VL8bXaA7VPxqpLkN2ixEz_p8QuAJoi7LdKpH4BpLLnfH2Vg\" alt=\"\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Dados: cos 42\u00b0 = 0.74; sen 42\u00b0 = 0.67<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">n<sub>ar<\/sub> = 1 (\u00edndice de refra\u00e7\u00e3o do ar).<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Os \u00edndices de refra\u00e7\u00e3o de cinco l\u00edquidos diferentes est\u00e3o indicados na tabela abaixo.<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/lh4.googleusercontent.com\/cwL1ehf35yywlGLJTllIBTbCUfFa33wJ-gMAG1hYE3MRG1UF8eeT8FkME4JWHk__SSOeJKSd-4CeSZgCeD2zxZnmp4bs_rIU3NzaSmftXPZPiucGwbUyo_rBoWntnqShhv0dzluWLWhYsUS_pw\" alt=\"\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">O \u00edndice de refra\u00e7\u00e3o de qual l\u00edquido se aproxima mais do obtido pelo experimento de Maria Meitner?<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">a) Do l\u00edquido 5.&nbsp; &nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">b) Do l\u00edquido 4.&nbsp; &nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">c) Do l\u00edquido 3.&nbsp; &nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">d) Do l\u00edquido 2.&nbsp; &nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">e) Do l\u00edquido 1.&nbsp; &nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Resposta: <\/strong>C<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">&nbsp;Aplicando a Lei de Snell, temos:<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/lh6.googleusercontent.com\/PX9NlclQHCkW383b0sAQ_y1NM0be1Fey3x2t9VvBIU4zIk7BDUFn4FwHGRjgvR6AlkXepl4X3qs-enEZ4FmbISii5tN4fRXC7BvPoHWOVixF4Gtepnku28ILPL_V5jWGsnAe3dkL1_jYUZFdHQ\" alt=\"\"\/><\/figure>\n\n\n\n<hr class=\"wp-block-separator\"\/>\n\n\n\n<h2 class=\"wp-block-heading\"><strong>Para aprender mais<\/strong><\/h2>\n\n\n\n<figure class=\"wp-block-embed-youtube wp-block-embed is-type-video is-provider-youtube wp-embed-aspect-16-9 wp-has-aspect-ratio\"><div class=\"wp-block-embed__wrapper\">\n<iframe title=\"Ext I 21.3 Lista 1 \u25ba Reflex\u00e3o Total | Professor Pinguim\" width=\"800\" height=\"450\" src=\"https:\/\/www.youtube.com\/embed\/3rOj3eSF198?feature=oembed\" frameborder=\"0\" allow=\"accelerometer; autoplay; clipboard-write; encrypted-media; gyroscope; picture-in-picture; web-share\" referrerpolicy=\"strict-origin-when-cross-origin\" allowfullscreen><\/iframe>\n<\/div><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Espero que voc\u00ea tenha entendido um pouco melhor a&nbsp;<strong>Reflex\u00e3o Total<\/strong>. E se quiser ajuda para melhorar seu n\u00edvel de F\u00edsica em outras mat\u00e9rias,<a href=\"https:\/\/professorpinguim.com.br\/\">&nbsp;<strong>entre em contato comigo e escolha o curso de F\u00edsica mais adequado para voc\u00ea<\/strong><\/a><strong>!<\/strong><\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><a href=\"https:\/\/conteudo.professorpinguim.com.br\/curso-de-fisica-gratuito\" target=\"_blank\" rel=\"noreferrer noopener\"><img decoding=\"async\" src=\"https:\/\/professorpinguim.com.br\/blog\/wp-content\/uploads\/2022\/05\/BannerPesquisa-BannerEmail-970x250px-ProfessorPinguim-1.png\" alt=\"Curso Gr\u00e1tis de F\u00edsica do Pro. Pinguim\" class=\"wp-image-11360\"\/><\/a><figcaption><em>Gr\u00e1tis Curso de F\u00edsica<\/em><\/figcaption><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>SAIBA MAIS<\/strong><br>\ud83d\udc27&nbsp;<a rel=\"noreferrer noopener\" href=\"https:\/\/professorpinguim.com.br\/blog\/exercicios-sobre-reflexao-da-luz-em-espelho-plano\/\" target=\"_blank\">Reflex\u00e3o da Luz em Espelho Plano<\/a><br>\ud83d\udc27&nbsp;<a rel=\"noreferrer noopener\" href=\"https:\/\/professorpinguim.com.br\/blog\/como-estudar-optica-para-vestibulares-paulistas\/\" target=\"_blank\">Como estudar \u00f3ptica para Unesp e da Fuvest<\/a><a href=\"https:\/\/professorpinguim.com.br\/blog\/leis-de-newton-exercicios-de-blocos-e-atrito\/\"><br><\/a>\ud83d\udc27&nbsp;<a href=\"https:\/\/professorpinguim.com.br\/blog\/exercicios-sobre-movimento-e-associacao-de-espelhos-planos\/\" target=\"_blank\" rel=\"noreferrer noopener\">Exerc\u00edcios sobre movimento e associa\u00e7\u00e3o de espelhos planos<\/a><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Me acompanhe nas redes sociais: curta a minha&nbsp;<a href=\"https:\/\/www.facebook.com\/professorpinguim\/\"><strong>p\u00e1gina no Facebook<\/strong><\/a><strong>,<\/strong>&nbsp;me siga no&nbsp;<a href=\"https:\/\/www.instagram.com\/professorpinguim\/\"><strong>Instagram<\/strong><\/a><strong>,<\/strong>&nbsp;se inscreva no&nbsp;<a href=\"https:\/\/www.youtube.com\/c\/PinguimV%C3%ADdeoF%C3%ADsica\/?sub_confirmation=1\"><strong>Youtube<\/strong><\/a>&nbsp;e participe do meu canal oficial no&nbsp;<a href=\"https:\/\/professorpinguim.com.br\/telegram\"><strong>Telegram<\/strong><\/a>.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Nesta aula, vamos resolver algumas quest\u00f5es sobre Reflex\u00e3o Total da Luz. Antes, vamos revisar as principais conceitos. Acompanhe!<\/p>\n","protected":false},"author":1,"featured_media":11268,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[744,764,228,573,656,1],"tags":[926,925,923,924,906,922,905],"class_list":["post-11263","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-exercicios-resolvidos","category-ondas","category-optica","category-optica-geometrica","category-termologia","category-uncategorized","tag-angulo","tag-lei-de-snell-descartes","tag-luz","tag-principais-conceitos","tag-raio-de-luz","tag-reflexao-total","tag-refracao"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v20.12 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Reflex\u00e3o Total - Professor Pinguim | F\u00edsica<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/professorpinguim.com.br\/blog\/reflexao-total\/\" \/>\n<meta property=\"og:locale\" content=\"pt_BR\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Reflex\u00e3o Total - Professor Pinguim | F\u00edsica\" \/>\n<meta property=\"og:description\" content=\"Nesta aula, vamos resolver algumas quest\u00f5es sobre Reflex\u00e3o Total da Luz. 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